COMPUTER SCIENCE ILLUMIN.-TEXT
6th Edition
ISBN: 2810016866372
Author: Dale
Publisher: JONES+BART
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Expert Solution & Answer
Chapter 18, Problem 34E
a.
Explanation of Solution
Representing the numbers in a linked list:
- The numbers can be represented in a linked list by representing each digit in a node.
- Then, the digits in the number 1066 is 1, 0, 6, and 6 which can be represented separately in a linked list as shown:
b.
Explanation of Solution
Addition of two numbers in two different lists and storing the results in another list:
- To add the numbers present in two linked lists, the values present in each node should be added from right to left.
- The carry should be added with the previous node values...
c.
Explanation of Solution
// Set the current pointer of first linked list to point
// the last node of the first linked list.
Set ptr1 to last
// Set the current pointer of second linked list to point
// the last node of the second linked list.
Set ptr2 to last
// Set the value 0 to the variable “remainder”
Set remainder to 0
// Continue the following set of statements until the first // linked list and second linked list becomes empty.
While (ptr1 <> NULL and ptr2 <> NULL)
// Create a new node.
Get a node_new
// Add the value of the node where the current pointer
// of first linked list points with the value of the
// node where the current pointer of second linked
// list points.
// Then by using the MOD function perform the division
// to get the remainder of the additional values and
// set it to new node.
Set info(node_new) to (info(ptr1) + info(ptr2) + remainder) MOD 10
// Add the value of the node where the current pointer
// of first linked list points with the value of the
// node where the current pointer of second linked
// list points.
// Then by using the DIV function perform the division // to get the quotient of the additional values and
// set it to new node
Set remainder to (info(ptr1) + info(ptr2) + remainder)DIV 10
// Set the current pointer of first linked list to
// point the previous node of the current node of the
// first linked list...
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I need help to solve a simple problem using Grover’s algorithm, where the solution is not necessarily known beforehand. The problem is a 2×2 binary sudoku with two rules:
• No column may contain the same value twice.
• No row may contain the same value twice.
Each square in the sudoku is assigned to a variable as follows:
We want to design a quantum circuit that outputs a valid solution to this sudoku. While using Grover’s algorithm for this task is not necessarily practical, the goal is to demonstrate how classical decision problems can be converted into oracles for Grover’s algorithm.
Turning the Problem into a Circuit
To solve this, an oracle needs to be created that helps identify valid solutions. The first step is to construct a classical function within a quantum circuit that checks whether a given state satisfies the sudoku rules.
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using r language
I need help to solve a simple problem using Grover’s algorithm, where the solution is not necessarily known beforehand. The problem is a 2×2 binary sudoku with two rules:
• No column may contain the same value twice.
• No row may contain the same value twice.
Each square in the sudoku is assigned to a variable as follows:
We want to design a quantum circuit that outputs a valid solution to this sudoku. While using Grover’s algorithm for this task is not necessarily practical, the goal is to demonstrate how classical decision problems can be converted into oracles for Grover’s algorithm.
Turning the Problem into a Circuit
To solve this, an oracle needs to be created that helps identify valid solutions. The first step is to construct a classical function within a quantum circuit that checks whether a given state satisfies the sudoku rules.
Since we need to check both columns and rows, there are four conditions to verify:
v0 ≠ v1 # Check top row
v2 ≠ v3 # Check bottom row…
Chapter 18 Solutions
COMPUTER SCIENCE ILLUMIN.-TEXT
Ch. 18 - Prob. 1ECh. 18 - Prob. 2ECh. 18 - Prob. 3ECh. 18 - Prob. 4ECh. 18 - Prob. 5ECh. 18 - Prob. 6ECh. 18 - Prob. 7ECh. 18 - Prob. 8ECh. 18 - Prob. 9ECh. 18 - Prob. 10E
Ch. 18 - Prob. 11ECh. 18 - Prob. 12ECh. 18 - Prob. 13ECh. 18 - Prob. 14ECh. 18 - Prob. 15ECh. 18 - Prob. 16ECh. 18 - Prob. 17ECh. 18 - Prob. 18ECh. 18 - Prob. 19ECh. 18 - Prob. 20ECh. 18 - Prob. 21ECh. 18 - Prob. 22ECh. 18 - Prob. 23ECh. 18 - Prob. 24ECh. 18 - Prob. 25ECh. 18 - Prob. 26ECh. 18 - Prob. 27ECh. 18 - Prob. 28ECh. 18 - Prob. 29ECh. 18 - Prob. 30ECh. 18 - Prob. 31ECh. 18 - Prob. 32ECh. 18 - Prob. 33ECh. 18 - Prob. 34ECh. 18 - Prob. 35ECh. 18 - Prob. 36ECh. 18 - Prob. 37ECh. 18 - Prob. 38ECh. 18 - Prob. 39ECh. 18 - Prob. 40ECh. 18 - Prob. 41ECh. 18 - Prob. 42ECh. 18 - Prob. 43ECh. 18 - Prob. 44ECh. 18 - Prob. 45ECh. 18 - Prob. 46ECh. 18 - Prob. 47ECh. 18 - Prob. 48ECh. 18 - Prob. 49ECh. 18 - Prob. 50ECh. 18 - Prob. 51ECh. 18 - Prob. 52ECh. 18 - Prob. 53ECh. 18 - Prob. 54ECh. 18 - Prob. 55ECh. 18 - Prob. 56ECh. 18 - Prob. 57ECh. 18 - Prob. 58ECh. 18 - Prob. 59ECh. 18 - Prob. 60ECh. 18 - Prob. 61ECh. 18 - Prob. 1TQCh. 18 - Prob. 2TQCh. 18 - Prob. 3TQ
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