Mathematical Statistics and Data Analysis with CD Data Sets 3rd Edition
3rd Edition
ISBN: 9788131501832
Author: John A. Rice
Publisher: CENGAGE L
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Chapter 1.8, Problem 22P
a.
To determine
Find the
b.
To determine
Find the value of n when the probability value is 0.5.
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(c) Because logistic regression predicts probabilities of outcomes, observations used to build a logistic regression model need not be independent.
A. false: all observations must be independent
B. true
C. false: only observations with the same outcome need to be independent
I ANSWERED: A. false: all observations must be independent.
(This was marked wrong but I have no idea why. Isn't this a basic assumption of logistic regression)
Business discuss
Spam filters are built on principles similar to those used in logistic regression. We fit a probability that each message is spam or not spam. We have several variables for each email. Here are a few: to_multiple=1 if there are multiple recipients, winner=1 if the word 'winner' appears in the subject line, format=1 if the email is poorly formatted, re_subj=1 if "re" appears in the subject line. A logistic model was fit to a dataset with the following output:
Estimate
SE
Z
Pr(>|Z|)
(Intercept)
-0.8161
0.086
-9.4895
0
to_multiple
-2.5651
0.3052
-8.4047
0
winner
1.5801
0.3156
5.0067
0
format
-0.1528
0.1136
-1.3451
0.1786
re_subj
-2.8401
0.363
-7.824
0
(a) Write down the model using the coefficients from the model fit.log_odds(spam) = -0.8161 + -2.5651 + to_multiple + 1.5801 winner + -0.1528 format + -2.8401 re_subj(b) Suppose we have an observation where to_multiple=0, winner=1, format=0, and re_subj=0. What is the predicted probability that this message is spam?…
Chapter 1 Solutions
Mathematical Statistics and Data Analysis with CD Data Sets 3rd Edition
Ch. 1.8 - Prob. 1PCh. 1.8 - Prob. 2PCh. 1.8 - Prob. 3PCh. 1.8 - Prob. 4PCh. 1.8 - Prob. 5PCh. 1.8 - Prob. 6PCh. 1.8 - Prob. 7PCh. 1.8 - Prob. 8PCh. 1.8 - Prob. 9PCh. 1.8 - Prob. 10P
Ch. 1.8 - Prob. 11PCh. 1.8 - Prob. 12PCh. 1.8 - Prob. 13PCh. 1.8 - Prob. 14PCh. 1.8 - Prob. 15PCh. 1.8 - Prob. 16PCh. 1.8 - Prob. 17PCh. 1.8 - Prob. 18PCh. 1.8 - Prob. 19PCh. 1.8 - Prob. 20PCh. 1.8 - Prob. 21PCh. 1.8 - Prob. 22PCh. 1.8 - Prob. 23PCh. 1.8 - Prob. 24PCh. 1.8 - Prob. 25PCh. 1.8 - Prob. 26PCh. 1.8 - Prob. 27PCh. 1.8 - Prob. 28PCh. 1.8 - Prob. 29PCh. 1.8 - Prob. 30PCh. 1.8 - Prob. 31PCh. 1.8 - Prob. 32PCh. 1.8 - Prob. 33PCh. 1.8 - Prob. 34PCh. 1.8 - Prob. 35PCh. 1.8 - Prob. 36PCh. 1.8 - Prob. 37PCh. 1.8 - Prob. 38PCh. 1.8 - Prob. 39PCh. 1.8 - Prob. 40PCh. 1.8 - Prob. 41PCh. 1.8 - Prob. 42PCh. 1.8 - Prob. 43PCh. 1.8 - Prob. 44PCh. 1.8 - Prob. 45PCh. 1.8 - Prob. 46PCh. 1.8 - Prob. 47PCh. 1.8 - Prob. 48PCh. 1.8 - Prob. 49PCh. 1.8 - Prob. 50PCh. 1.8 - Prob. 51PCh. 1.8 - Prob. 52PCh. 1.8 - Prob. 53PCh. 1.8 - Prob. 54PCh. 1.8 - Prob. 55PCh. 1.8 - Prob. 56PCh. 1.8 - Prob. 57PCh. 1.8 - Prob. 59PCh. 1.8 - Prob. 60PCh. 1.8 - Prob. 61PCh. 1.8 - Prob. 62PCh. 1.8 - Prob. 63PCh. 1.8 - Prob. 64PCh. 1.8 - Prob. 65PCh. 1.8 - Prob. 66PCh. 1.8 - Prob. 67PCh. 1.8 - Prob. 68PCh. 1.8 - Prob. 69PCh. 1.8 - Prob. 70PCh. 1.8 - Prob. 71PCh. 1.8 - Prob. 72PCh. 1.8 - Prob. 73PCh. 1.8 - Prob. 74PCh. 1.8 - Prob. 75PCh. 1.8 - Prob. 77PCh. 1.8 - Prob. 78PCh. 1.8 - Prob. 79PCh. 1.8 - Prob. 80P
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