Quantitative Chemical Analysis 9e And Sapling Advanced Single Course For Analytical Chemistry (access Card)
Quantitative Chemical Analysis 9e And Sapling Advanced Single Course For Analytical Chemistry (access Card)
9th Edition
ISBN: 9781319090241
Author: Daniel C. Harris, Sapling Learning
Publisher: W. H. Freeman
Question
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Chapter 18, Problem 18.BE

(a)

Interpretation Introduction

Interpretation:

For the given compound A, the value of molar absorptivity has to be calculated.

Concept introduction:

Beer-lambert law:

A=-logPPo=εcbwhere,A-absorbancePo-incidentirradianceandP-transmittedirradianceε-molarabsorptivityc-concentrationandb-pathlength.

(a)

Expert Solution
Check Mark

Answer to Problem 18.BE

The molar absorptivity (ε) value of compound A is 1.50×103M-1cm-1.

Explanation of Solution

Given information,

Concentrationis3.96×10-4M.Absorbance(A)is0.624at238nmin1.000cmcuvet.Absorbanceforblanksolutionis0.029at238nm.

Apply the Beer’s law to calculate the value of molar absorptivity (ε)

A=εcbε=Abc=0.624-0.029(3.96×10-4M-1cm-1)(1.000cm)=1.50×103M-1cm-1.

The molar absorptivity (ε) value of compound A is 1.50×103M-1cm-1.

(b)

Interpretation Introduction

Interpretation:

The concentration of compound A in the unknown solution has to be calculated.

Concept introduction:

Beer-lambert law:

A=-logPPo=εcbwhere,A-absorbancePo-incidentirradianceandP-transmittedirradianceε-molarabsorptivityc-concentrationandb-pathlength.

(b)

Expert Solution
Check Mark

Answer to Problem 18.BE

The concentration of compound A in the unknown solution is 2.31×10-4M.

Explanation of Solution

Given information,

Absorbance(A)is0.375at238nmin1.000cmcuvet.Absorbanceforblanksolutionis0.029at238nm.Molarabsorptivityis1.50×103M-1cm-1.

Calculate the concentration of compound A in the unknown solution

c=Aεb=0.375-0.029(1.50×103M-1cm-1)(1.000cm)=2.31×10-4M.

The concentration of compound A in the unknown solution is 2.31×10-4M.

(c)

Interpretation Introduction

Interpretation:

The concentration of compound A in the concentrated solution has to be calculated.

Concept introduction:

Beer-lambert law:

A=-logPPo=εcbwhere,A-absorbancePo-incidentirradianceandP-transmittedirradianceε-molarabsorptivityc-concentrationandb-pathlength.

(c)

Expert Solution
Check Mark

Answer to Problem 18.BE

The concentration of compound A in the concentrated solution is 5.87×10-3M.

Explanation of Solution

Given information,

Initialvolumeis2.00mL,Finalvolumeis25.00mL.Absorbance(A)is0.733at238nmin1.000cmcuvet.Absorbanceforblanksolutionis0.029.Molarabsorptivityis1.50×103M-1cm-1.

Calculate the concentration of compound A in the concentrated solution

c=(dilutionfactor)Aεb=(25.00mL2.00mL)0.733-0.029(1.50×103M-1cm-1)(1.000cm)=5.87×10-3M.

The concentration of compound A in the concentrated solution is 5.87×10-3M.

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