For the reaction CH 3 OH ( l ) + 3 2 O 2 ( g ) → 2 H 2 O ( l ) + CO 2 ( g ) the value of Δ G ° is −702.2 kJ at 25°C. Other data are as follows: Δ H f ° (kJ/mol) at 25°C S° (J/mol · K) at 25°C CH 3 OH( l ) −238.7 126.8 H 2 O( l ) −285.8 70.0 CO 2 ( g ) −393.5 213.7 Calculate the standard entropy, S °, per mole of O 2 ( g ).
For the reaction CH 3 OH ( l ) + 3 2 O 2 ( g ) → 2 H 2 O ( l ) + CO 2 ( g ) the value of Δ G ° is −702.2 kJ at 25°C. Other data are as follows: Δ H f ° (kJ/mol) at 25°C S° (J/mol · K) at 25°C CH 3 OH( l ) −238.7 126.8 H 2 O( l ) −285.8 70.0 CO 2 ( g ) −393.5 213.7 Calculate the standard entropy, S °, per mole of O 2 ( g ).
Using the graphs could you help me explain the answers. I assumed that both graphs are proportional to the inverse of time, I think. Could you please help me.
Synthesis of Dibenzalacetone
[References]
Draw structures for the carbonyl electrophile and enolate nucleophile that react to give the enone below.
Question 1
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Question 2
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Question 3
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H
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Question 8
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Progress:
7/8 items
Que Feb 24 at
You do not have to consider stereochemistry.
. Draw the enolate ion in its carbanion form.
• Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner.
⚫ Separate multiple reactants using the + sign from the drop-down menu.
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4
Shown below is the mechanism presented for the formation of biasplatin in reference 1 from the Background and Experiment document. The amounts used of each reactant are shown. Either draw or describe a better alternative to this mechanism. (Note that the first step represents two steps combined and the proton loss is not even shown; fixing these is not the desired improvement.) (Hints: The first step is correct, the second step is not; and the amount of the anhydride is in large excess to serve a purpose.)
Chapter 18 Solutions
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