Explanation Given information: The linear density of string is 1.60 g / m , length of the string is 48.0 cm and time interval is 3.50 s . The tension as a function of time is given by, T = 15.0 + 10.0 t 3.50 (I) Formula to calculate the fundamental wavelength is, λ 1 = 2 L λ 1 is the fundamental wavelength. L is the length of the string. Formula to calculate the speed of the wave as a function of time is, v = T μ v is the speed of wave. μ is the linear density of string. Substitute ( 15.0 + 10.0 t 3.50 ) for T in the above equation. v = ( 15.0 + 10.0 t 3.50 μ ) 1 2 Formula to calculate the fundamental frequency is, f 1 = v λ 1 f 1 is the fundamental frequency. Substitute ( 15.0 + 10.0 t 3.50 μ ) 1 2 for v and 2 L for λ 1 in the above equation. f 1 = 1 2 L ( 15.0 + 10.0 t 3.50 μ ) 1 2 Substitute 48.0 cm for L and 1.60 g / m for μ in the above equation. f 1 = 1 2 × 48.0 cm × 10 − 2 m 1 cm ( 15

Bundle: Physics for Scientists and Engineers, Technology Update, 9th Loose-leaf Version + WebAssign Printed Access Card, Multi-Term

9th Edition

ISBN: 9781305714892

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

See similar textbooks

Concept explainers

Mechanical Properties of Solids

There are three types of matter- solid, liquid and gas. Out of them, solids have a rigid shaped and size. The intermolecular forces of attractions in solids are greatest. Mechanical properties are the physical properties of a material which it shows, whe…

Videos

Question

Chapter 18, Problem 18.81AP

To determine

The number of oscillations completed during 3.50 s interval.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 18, Problem 18.80AP

Chapter 18, Problem 18.82AP

Students have asked these similar questions

A 31.0-kg child on a 3.00-m-long swing is released from rest when the ropes of the swing make an angle of 29.0° with the vertical. (a) Neglecting friction, find the child's speed at the lowest position. m/s (b) If the actual speed of the child at the lowest position is 2.40 m/s, what is the mechanical energy lost due to friction? ]

A force acting on a particle moving in the xy plane is given by F = (2yî + x²), where F is in newtons and x and y are in meters. The particle moves from the origin to a final position having coordinates x = 5.60 m and y = 5.60 m, as shown in the figure below. y (m) B (x, y) x (m) (a) Calculate the work done by F on the particle as it moves along the purple path (0 Ⓐ©). ] (b) Calculate the work done by ♬ on the particle as it moves along the red path (0 BC). J (c) Is F conservative or nonconservative? ○ conservative nonconservative

A 3.5-kg block is pushed 2.9 m up a vertical wall with constant speed by a constant force of magnitude F applied at an angle of 0 = 30° with the horizontal, as shown in the figure below. If the coefficient of kinetic friction between block and wall is 0.30, determine the following. (a) the work done by F J (b) the work done by the force of gravity ] (c) the work done by the normal force between block and wall J (d) By how much does the gravitational potential energy increase during the block's motion? ]

Chapter 18 Solutions

Bundle: Physics for Scientists and Engineers, Technology Update, 9th Loose-leaf Version + WebAssign Printed Access Card, Multi-Term

Ch. 18 - Prob. 18.1QQ Ch. 18 - Consider the waves in Figure 17.8 to be waves on a...Ch. 18 - When a standing wave is set up on a string fixed...Ch. 18 - Prob. 18.4QQ Ch. 18 - Balboa Park in San Diego has an outdoor organ....Ch. 18 - In figure OQ18.1 (page 566), a sound wave of...Ch. 18 - A string of length L, mass pet unit length , and...Ch. 18 - In Example 18.1, we investigated an oscillator at...Ch. 18 - Prob. 18.4OQ Ch. 18 - A flute has a length of 58.0 cm. If the speed of...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

The number of oscillations completed during 3.50 s interval.

Solution Summary: The author explains the number of oscillations completed during 3.50s interval. The tension as a function of time is given by T=15.0+10.0t3.50

Concept explainers

Videos

The number of oscillations completed during 3.50 s interval.

Want to see the full answer?

Chapter 18 Solutions