Blank in the description of frequency of electromagnetic radiation has to be filled. Concept Introduction: Formula to calculate frequency is as follows: v = c λ Planck’s hypothesis states energy associated with photon is as follows: E = h v = h c λ Formula to calculate wavenumber is as follows: v ¯ = v c Here, λ denotes wavelength. h denotes Planck’s constant c denotes speed of light. v ¯ denotes wavenumber.

Question

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Answer 1

Question

Chapter 18, Problem 18.1P

(a)

Interpretation Introduction

Interpretation:

Blank in the description of frequency of electromagnetic radiation has to be filled.

Concept Introduction:

Formula to calculate frequency is as follows:

v=cλ

Planck’s hypothesis states energy associated with photon is as follows:

E=hv=hcλ

Formula to calculate wavenumber is as follows:

v¯=vc

Here,

λ denotes wavelength.

h denotes Planck’s constant

c denotes speed of light.

v¯ denotes wavenumber.

(a)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of frequency is as follows:

E=hv

Since energy is directly related to frequency in accordance with Planck’s hypothesis thus when frequency is doubled, energy is also doubled. So energy will also double.

(b)

Interpretation Introduction

Interpretation:

Blank in the description of wavelength and energy of electromagnetic radiation has to be filled.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of wavelength is as follows:

E=hcλ

Since energy is inversely directly related to energy in accordance with Planck’s hypothesis thus when wavelength is doubled, energy is reduced by same amount doubled. So, energy will become halve.

(c)

Interpretation Introduction

Interpretation:

Blank in the description of wavenumber and energy of electromagnetic radiation has to be filled.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of wavenumber is as follows:

E=hcv¯

Since energy is inversely directly related to v¯ in accordance with Planck’s hypothesis thus when v¯ is doubled, energy is increased by same amount. So, energy will also become double.

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Answer 2

Question

Chapter 18, Problem 18.1P

(a)

Interpretation Introduction

Interpretation:

Blank in the description of frequency of electromagnetic radiation has to be filled.

Concept Introduction:

Formula to calculate frequency is as follows:

v=cλ

Planck’s hypothesis states energy associated with photon is as follows:

E=hv=hcλ

Formula to calculate wavenumber is as follows:

v¯=vc

Here,

λ denotes wavelength.

h denotes Planck’s constant

c denotes speed of light.

v¯ denotes wavenumber.

(a)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of frequency is as follows:

E=hv

Since energy is directly related to frequency in accordance with Planck’s hypothesis thus when frequency is doubled, energy is also doubled. So energy will also double.

(b)

Interpretation Introduction

Interpretation:

Blank in the description of wavelength and energy of electromagnetic radiation has to be filled.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of wavelength is as follows:

E=hcλ

Since energy is inversely directly related to energy in accordance with Planck’s hypothesis thus when wavelength is doubled, energy is reduced by same amount doubled. So, energy will become halve.

(c)

Interpretation Introduction

Interpretation:

Blank in the description of wavenumber and energy of electromagnetic radiation has to be filled.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of wavenumber is as follows:

E=hcv¯

Since energy is inversely directly related to v¯ in accordance with Planck’s hypothesis thus when v¯ is doubled, energy is increased by same amount. So, energy will also become double.

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Answer 3

Question

Chapter 18, Problem 18.1P

(a)

Interpretation Introduction

Interpretation:

Blank in the description of frequency of electromagnetic radiation has to be filled.

Concept Introduction:

Formula to calculate frequency is as follows:

v=cλ

Planck’s hypothesis states energy associated with photon is as follows:

E=hv=hcλ

Formula to calculate wavenumber is as follows:

v¯=vc

Here,

λ denotes wavelength.

h denotes Planck’s constant

c denotes speed of light.

v¯ denotes wavenumber.

(a)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of frequency is as follows:

E=hv

Since energy is directly related to frequency in accordance with Planck’s hypothesis thus when frequency is doubled, energy is also doubled. So energy will also double.

(b)

Interpretation Introduction

Interpretation:

Blank in the description of wavelength and energy of electromagnetic radiation has to be filled.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of wavelength is as follows:

E=hcλ

Since energy is inversely directly related to energy in accordance with Planck’s hypothesis thus when wavelength is doubled, energy is reduced by same amount doubled. So, energy will become halve.

(c)

Interpretation Introduction

Interpretation:

Blank in the description of wavenumber and energy of electromagnetic radiation has to be filled.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of wavenumber is as follows:

E=hcv¯

Since energy is inversely directly related to v¯ in accordance with Planck’s hypothesis thus when v¯ is doubled, energy is increased by same amount. So, energy will also become double.

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Answer 4

Question

Chapter 18, Problem 18.1P

(a)

Interpretation Introduction

Interpretation:

Blank in the description of frequency of electromagnetic radiation has to be filled.

Concept Introduction:

Formula to calculate frequency is as follows:

v=cλ

Planck’s hypothesis states energy associated with photon is as follows:

E=hv=hcλ

Formula to calculate wavenumber is as follows:

v¯=vc

Here,

λ denotes wavelength.

h denotes Planck’s constant

c denotes speed of light.

v¯ denotes wavenumber.

(a)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of frequency is as follows:

E=hv

Since energy is directly related to frequency in accordance with Planck’s hypothesis thus when frequency is doubled, energy is also doubled. So energy will also double.

(b)

Interpretation Introduction

Interpretation:

Blank in the description of wavelength and energy of electromagnetic radiation has to be filled.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of wavelength is as follows:

E=hcλ

Since energy is inversely directly related to energy in accordance with Planck’s hypothesis thus when wavelength is doubled, energy is reduced by same amount doubled. So, energy will become halve.

(c)

Interpretation Introduction

Interpretation:

Blank in the description of wavenumber and energy of electromagnetic radiation has to be filled.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of wavenumber is as follows:

E=hcv¯

Since energy is inversely directly related to v¯ in accordance with Planck’s hypothesis thus when v¯ is doubled, energy is increased by same amount. So, energy will also become double.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 18, Problem 18.1P

(a)

Interpretation Introduction

Interpretation:

Blank in the description of frequency of electromagnetic radiation has to be filled.

Concept Introduction:

Formula to calculate frequency is as follows:

v=cλ

Planck’s hypothesis states energy associated with photon is as follows:

E=hv=hcλ

Formula to calculate wavenumber is as follows:

v¯=vc

Here,

λ denotes wavelength.

h denotes Planck’s constant

c denotes speed of light.

v¯ denotes wavenumber.

(a)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of frequency is as follows:

E=hv

Since energy is directly related to frequency in accordance with Planck’s hypothesis thus when frequency is doubled, energy is also doubled. So energy will also double.

(b)

Interpretation Introduction

Interpretation:

Blank in the description of wavelength and energy of electromagnetic radiation has to be filled.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of wavelength is as follows:

E=hcλ

Since energy is inversely directly related to energy in accordance with Planck’s hypothesis thus when wavelength is doubled, energy is reduced by same amount doubled. So, energy will become halve.

(c)

Interpretation Introduction

Interpretation:

Blank in the description of wavenumber and energy of electromagnetic radiation has to be filled.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of wavenumber is as follows:

E=hcv¯

Since energy is inversely directly related to v¯ in accordance with Planck’s hypothesis thus when v¯ is doubled, energy is increased by same amount. So, energy will also become double.

Answer 6

Chapter 18, Problem 18.1P

(a)

Interpretation Introduction

Interpretation:

Blank in the description of frequency of electromagnetic radiation has to be filled.

Concept Introduction:

Formula to calculate frequency is as follows:

v=cλ

Planck’s hypothesis states energy associated with photon is as follows:

E=hv=hcλ

Formula to calculate wavenumber is as follows:

v¯=vc

Here,

λ denotes wavelength.

h denotes Planck’s constant

c denotes speed of light.

v¯ denotes wavenumber.

(a)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of frequency is as follows:

E=hv

Since energy is directly related to frequency in accordance with Planck’s hypothesis thus when frequency is doubled, energy is also doubled. So energy will also double.

Answer 7

Chapter 18, Problem 18.1P

(a)

Interpretation Introduction

Interpretation:

Blank in the description of frequency of electromagnetic radiation has to be filled.

Concept Introduction:

Formula to calculate frequency is as follows:

v=cλ

Planck’s hypothesis states energy associated with photon is as follows:

E=hv=hcλ

Formula to calculate wavenumber is as follows:

v¯=vc

Here,

λ denotes wavelength.

h denotes Planck’s constant

c denotes speed of light.

v¯ denotes wavenumber.

Answer 8

(a)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of frequency is as follows:

E=hv

Since energy is directly related to frequency in accordance with Planck’s hypothesis thus when frequency is doubled, energy is also doubled. So energy will also double.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

(b)

Interpretation Introduction

Interpretation:

Blank in the description of wavelength and energy of electromagnetic radiation has to be filled.

Concept Introduction:

Refer to part (a).

(b)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of wavelength is as follows:

E=hcλ

Since energy is inversely directly related to energy in accordance with Planck’s hypothesis thus when wavelength is doubled, energy is reduced by same amount doubled. So, energy will become halve.

Answer 13

(b)

Interpretation Introduction

Interpretation:

Blank in the description of wavelength and energy of electromagnetic radiation has to be filled.

Concept Introduction:

Refer to part (a).

Answer 14

(b)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of wavelength is as follows:

E=hcλ

Since energy is inversely directly related to energy in accordance with Planck’s hypothesis thus when wavelength is doubled, energy is reduced by same amount doubled. So, energy will become halve.

Answer 15

(b)

Expert Solution

Answer 16

(b)

Expert Solution

Answer 17

Expert Solution

Answer 18

(c)

Interpretation Introduction

Interpretation:

Blank in the description of wavenumber and energy of electromagnetic radiation has to be filled.

Concept Introduction:

Refer to part (a).

(c)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of wavenumber is as follows:

E=hcv¯

Since energy is inversely directly related to v¯ in accordance with Planck’s hypothesis thus when v¯ is doubled, energy is increased by same amount. So, energy will also become double.

Answer 19

(c)

Interpretation Introduction

Interpretation:

Blank in the description of wavenumber and energy of electromagnetic radiation has to be filled.

Concept Introduction:

Refer to part (a).

Answer 20

(c)

Expert Solution

Explanation of Solution

Planck’s hypothesis states energy associated with photon in terms of wavenumber is as follows:

E=hcv¯

Since energy is inversely directly related to v¯ in accordance with Planck’s hypothesis thus when v¯ is doubled, energy is increased by same amount. So, energy will also become double.