For entropy of universe Δ S univ to be positive, entropy of the surroundings Δ S surr must be positive and greater in absolute value (or magnitude) than entropy of the system Δ S sys because, Δ S univ = Δ S sys + Δ S surr

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Chapter 18, Problem 14SAQ

Interpretation Introduction

Introduction: For entropy of universe ΔSuniv to be positive, entropy of the surroundings ΔSsurr must be positive and greater in absolute value (or magnitude) than entropy of the system ΔSsys because,

ΔSuniv=ΔSsys+ΔSsurr

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Answer 2

Question

Chapter 18, Problem 14SAQ

Interpretation Introduction

Introduction: For entropy of universe ΔSuniv to be positive, entropy of the surroundings ΔSsurr must be positive and greater in absolute value (or magnitude) than entropy of the system ΔSsys because,

ΔSuniv=ΔSsys+ΔSsurr

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Answer 3

Question

Chapter 18, Problem 14SAQ

Interpretation Introduction

Introduction: For entropy of universe ΔSuniv to be positive, entropy of the surroundings ΔSsurr must be positive and greater in absolute value (or magnitude) than entropy of the system ΔSsys because,

ΔSuniv=ΔSsys+ΔSsurr

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Answer 4

Question

Chapter 18, Problem 14SAQ

Interpretation Introduction

Introduction: For entropy of universe ΔSuniv to be positive, entropy of the surroundings ΔSsurr must be positive and greater in absolute value (or magnitude) than entropy of the system ΔSsys because,

ΔSuniv=ΔSsys+ΔSsurr

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Answer 5

Chapter 18, Problem 14SAQ

Interpretation Introduction

Introduction: For entropy of universe ΔSuniv to be positive, entropy of the surroundings ΔSsurr must be positive and greater in absolute value (or magnitude) than entropy of the system ΔSsys because,

ΔSuniv=ΔSsys+ΔSsurr

Answer 6

Chapter 18, Problem 14SAQ

Interpretation Introduction

Introduction: For entropy of universe ΔSuniv to be positive, entropy of the surroundings ΔSsurr must be positive and greater in absolute value (or magnitude) than entropy of the system ΔSsys because,

ΔSuniv=ΔSsys+ΔSsurr

Answer 7

Chapter 18, Problem 14SAQ

Interpretation Introduction

Introduction: For entropy of universe ΔSuniv to be positive, entropy of the surroundings ΔSsurr must be positive and greater in absolute value (or magnitude) than entropy of the system ΔSsys because,

ΔSuniv=ΔSsys+ΔSsurr

Answer 8

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Answer 11

Ch. 18 - Prob. 1SAQ Ch. 18 - Prob. 2SAQ Ch. 18 - Q3. Arrange the gases—F2, Ar, and CH3F—in order of...Ch. 18 - Q4. Calculate the change in entropy that occurs in...Ch. 18 - Q5. A reaction has a ΔHrxn = 54.2 kJ. Calculate...Ch. 18 - Prob. 6SAQ Ch. 18 - Q7. Use standard entropies to calculate for the...Ch. 18 - Q8. Use standard free energies of formation to...Ch. 18 - Q9. Find ΔG$$ for the reaction 2 A + B → 2 C from...Ch. 18 - Prob. 10SAQ

For entropy of universe Δ S univ to be positive, entropy of the surroundings Δ S surr must be positive and greater in absolute value (or magnitude) than entropy of the system Δ S sys because, Δ S univ = Δ S sys + Δ S surr

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Introduction: For entropy of universe ΔSuniv to be positive, entropy of the surroundings ΔSsurr must be positive and greater in absolute value (or magnitude) than entropy of the system ΔSsys because,

ΔSuniv=ΔSsys+ΔSsurr

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Chapter 18 Solutions

For entropy of universe Δ S univ to be positive, entropy of the surroundings Δ S surr must be positive and greater in absolute value (or magnitude) than entropy of the system Δ S sys because, Δ S univ = Δ S sys + Δ S surr

Videos

Introduction: For entropy of universe ΔSuniv to be positive, entropy of the surroundings ΔSsurr must be positive and greater in absolute value (or magnitude) than entropy of the system ΔSsys because, ΔSuniv=ΔSsys+ΔSsurr

Want to see the full answer?

Chapter 18 Solutions

Introduction: For entropy of universe ΔSuniv to be positive, entropy of the surroundings ΔSsurr must be positive and greater in absolute value (or magnitude) than entropy of the system ΔSsys because,

ΔSuniv=ΔSsys+ΔSsurr