Explanation It is given that the pressure p exerted on the surface is the ratio of the force F to its area A and it is denoted by p = F A . The force F exerted on the patch and side of the tank are 42.3 lb and 2.25 in respectively. The pressure exerted on the square patch is obtained from the above relation as follows. p = F A = 42.3 lb ( 2

11th Edition

ISBN: 9780134437705

Author: Washington

Publisher: PEARSON

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Chapter 18, Problem 13RE

To determine

The pressure p exerted on the square patch of the tank.

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Chapter 18, Problem 12RE

Chapter 18, Problem 14RE

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Chapter 18 Solutions

Basic Technical Mathematics

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