The requirement of electrical energy for the production of Aluminum from Aluminum oxide is given. The comparison between the energy required for producing Aluminum from Aluminum oxide and the energy for melting Aluminum and the reason behind the economical feasibility of recycling Aluminum cans is to be stated. Concept introduction: For melting of any substance some specific amount of heat is required. Therefore, the amount of heat that is required for melting one mole of substance and that too at its melting point is called the heat of fusion. To determine: The comparison between the energy required for producing Aluminum from Aluminum oxide and the energy for melting Aluminum and the reason behind the economical feasibility of recycling Aluminum cans. The amount of electrical energy required to produce Aluminum from Aluminum oxide is 54 × 10 6 J . The amount of energy required to melt Aluminum metal is 395.9 × 10 3 J . The energy for melting Aluminum is lower than the energy required for producing Aluminum from Aluminum oxide. The requirement of lower energy for melting Aluminum than required to produce Aluminum from Aluminum oxide makes it an economically feasible process.
The requirement of electrical energy for the production of Aluminum from Aluminum oxide is given. The comparison between the energy required for producing Aluminum from Aluminum oxide and the energy for melting Aluminum and the reason behind the economical feasibility of recycling Aluminum cans is to be stated. Concept introduction: For melting of any substance some specific amount of heat is required. Therefore, the amount of heat that is required for melting one mole of substance and that too at its melting point is called the heat of fusion. To determine: The comparison between the energy required for producing Aluminum from Aluminum oxide and the energy for melting Aluminum and the reason behind the economical feasibility of recycling Aluminum cans. The amount of electrical energy required to produce Aluminum from Aluminum oxide is 54 × 10 6 J . The amount of energy required to melt Aluminum metal is 395.9 × 10 3 J . The energy for melting Aluminum is lower than the energy required for producing Aluminum from Aluminum oxide. The requirement of lower energy for melting Aluminum than required to produce Aluminum from Aluminum oxide makes it an economically feasible process.
Solution Summary: The author compares the amount of electrical energy required for producing Aluminum from Aluminum oxide and the energy for melting Aluminum, and explains the economic feasibility of recycling Aluminum cans.
The requirement of electrical energy for the production of Aluminum from Aluminum oxide is given. The comparison between the energy required for producing Aluminum from Aluminum oxide and the energy for melting Aluminum and the reason behind the economical feasibility of recycling Aluminum cans is to be stated.
Concept introduction:
For melting of any substance some specific amount of heat is required. Therefore, the amount of heat that is required for melting one mole of substance and that too at its melting point is called the heat of fusion.
To determine: The comparison between the energy required for producing Aluminum from Aluminum oxide and the energy for melting Aluminum and the reason behind the economical feasibility of recycling Aluminum cans.
The amount of electrical energy required to produce Aluminum from Aluminum oxide is
54×106J.
The amount of energy required to melt Aluminum metal is
395.9×103J.
The energy for melting Aluminum is lower than the energy required for producing Aluminum from Aluminum oxide.
The requirement of lower energy for melting Aluminum than required to produce Aluminum from Aluminum oxide makes it an economically feasible process.
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Question 59 of 70
The volume of
1
unit of plasma is 200.0 mL
If the recommended dosage
for adult patients is 10.0 mL per kg of body mass, how many units are needed for
a patient with a body mass of 80.0
kg ?
80.0
kg
10.0
DAL
1
units
X
X
4.00
units
1
1
Jeg
200.0
DAL
L
1 units
X
200.0 mL
= 4.00 units
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D
200.0
2.00
1.60 × 10³
80.0
4.00
0.0400
0.250
10.0
8.00
&
mL
mL/kg
kg
units/mL
L
unit
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Identify the starting material in the following reaction. Click the "draw structure" button to launch the
drawing utility.
draw structure ...
[1] 0 3
C10H18
[2] CH3SCH3
H
In an equilibrium mixture of the formation of ammonia from nitrogen and hydrogen, it is found that
PNH3 = 0.147 atm, PN2 = 1.41 atm and Pн2 = 6.00 atm. Evaluate Kp and Kc at 500 °C.
2 NH3 (g) N2 (g) + 3 H₂ (g)
K₂ = (PN2)(PH2)³ = (1.41) (6.00)³ = 1.41 x 104