Modified Mastering Chemistry with Pearson eText -- Standalone Access Card -- for Introductory Chemistry (6th Edition)
6th Edition
ISBN: 9780134565620
Author: Nivaldo J. Tro
Publisher: PEARSON
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Textbook Question
Chapter 18, Problem 103E
Identify each organic compound as an
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Learning Goal:
This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this:
35 Cl
17
In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is:
It is also correct to write symbols by leaving off the atomic number, as in the following form:
atomic number
mass number Symbol
35 Cl or
mass number Symbol
This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons
are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written.
Watch this video to review the format for written symbols.
In the following table each column…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Chapter 18 Solutions
Modified Mastering Chemistry with Pearson eText -- Standalone Access Card -- for Introductory Chemistry (6th Edition)
Ch. 18 - Prob. 1SAQCh. 18 - Q2. What is the correct formula for the alkane...Ch. 18 - Which structure is not an isomer of...Ch. 18 - Prob. 4SAQCh. 18 - Prob. 5SAQCh. 18 - Name the compound. a. 2-methyI-3-pentene b....Ch. 18 - Prob. 7SAQCh. 18 - Prob. 8SAQCh. 18 - Prob. 9SAQCh. 18 - Prob. 10SAQ
Ch. 18 - Prob. 1ECh. 18 - Prob. 2ECh. 18 - Prob. 3ECh. 18 - 4. What is vitalism? How was vitalism usurped?
Ch. 18 - Prob. 5ECh. 18 - Prob. 6ECh. 18 - Prob. 7ECh. 18 - Prob. 8ECh. 18 - Prob. 9ECh. 18 - Prob. 10ECh. 18 - 11. Explain the difference between n-alkanes and...Ch. 18 - Prob. 12ECh. 18 - Prob. 13ECh. 18 - Prob. 14ECh. 18 - Prob. 15ECh. 18 - What are alkane substitution reactions? Provide an...Ch. 18 - 17. What is an alkene addition reaction? Provide...Ch. 18 - Prob. 18ECh. 18 - Prob. 19ECh. 18 - Prob. 20ECh. 18 - 21. What is the generic structure of alcohols?...Ch. 18 - Prob. 22ECh. 18 - Prob. 23ECh. 18 - Prob. 24ECh. 18 - Prob. 25ECh. 18 - Prob. 26ECh. 18 - Prob. 27ECh. 18 - Prob. 28ECh. 18 - Prob. 29ECh. 18 - Prob. 30ECh. 18 - Prob. 31ECh. 18 - Prob. 32ECh. 18 - Prob. 33ECh. 18 - Prob. 34ECh. 18 - Prob. 35ECh. 18 - Prob. 36ECh. 18 - Prob. 37ECh. 18 - Prob. 38ECh. 18 - Prob. 39ECh. 18 - Prob. 40ECh. 18 - Prob. 41ECh. 18 - Prob. 42ECh. 18 - Prob. 43ECh. 18 - Name each alkane.Ch. 18 - Prob. 45ECh. 18 - 46. Draw a structure for each alkane.
...Ch. 18 - Determine what is wrong with the name of each...Ch. 18 - Determine what is wrong with the name of each...Ch. 18 - Prob. 49ECh. 18 - Prob. 50ECh. 18 - Prob. 51ECh. 18 - Prob. 52ECh. 18 - Prob. 53ECh. 18 - Prob. 54ECh. 18 - Prob. 55ECh. 18 - 56. Name each alkane.
Ch. 18 - Prob. 57ECh. 18 - Prob. 58ECh. 18 - Prob. 59ECh. 18 - 60. Provide correct structures for each compound.
...Ch. 18 - Prob. 61ECh. 18 - Prob. 62ECh. 18 - Prob. 63ECh. 18 - Complete the table.Ch. 18 - Prob. 65ECh. 18 - Prob. 66ECh. 18 - Prob. 67ECh. 18 - Prob. 68ECh. 18 - What are the products of this alkene addition...Ch. 18 - Prob. 70ECh. 18 - Prob. 71ECh. 18 - Prob. 72ECh. 18 - Prob. 73ECh. 18 - Prob. 74ECh. 18 - Name each monosubstituted benzene.Ch. 18 - Prob. 76ECh. 18 - Prob. 77ECh. 18 - Prob. 78ECh. 18 - Prob. 79ECh. 18 - Prob. 80ECh. 18 - Prob. 81ECh. 18 - Prob. 82ECh. 18 - Based on its functional group, match the structure...Ch. 18 - Prob. 84ECh. 18 - Prob. 85ECh. 18 - Prob. 86ECh. 18 - Prob. 87ECh. 18 - Prob. 88ECh. 18 - Prob. 89ECh. 18 - Draw a structure for each alcohol. a. 1-hexanol b....Ch. 18 - Prob. 91ECh. 18 - Prob. 92ECh. 18 - Prob. 93ECh. 18 - For each compound, provide a name if the structure...Ch. 18 - Prob. 95ECh. 18 - Prob. 96ECh. 18 - Prob. 97ECh. 18 - Prob. 98ECh. 18 - Prob. 99ECh. 18 - Prob. 100ECh. 18 - Prob. 101ECh. 18 - Prob. 102ECh. 18 - Identify each organic compound as an alkane,...Ch. 18 - Prob. 104ECh. 18 - 105. Name each compound.
Ch. 18 - Name each compound.Ch. 18 - Prob. 107ECh. 18 - Prob. 108ECh. 18 - Prob. 109ECh. 18 - Prob. 110ECh. 18 - Prob. 111ECh. 18 - How many kilograms of CO2 are produced by the...Ch. 18 - Prob. 113ECh. 18 - Prob. 114ECh. 18 - Prob. 115ECh. 18 - Prob. 116ECh. 18 - Using complete sentences, compare and contrast...Ch. 18 - The octane rating for gasoline is a measurement of...Ch. 18 - Prob. 120QGWCh. 18 - Prob. 121DIA
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- Please correct answer and don't used hand raitingarrow_forwardneed help please and thanks dont understand a-b Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal energy Divide the…arrow_forwardPlease correct answer and don't used hand raitingarrow_forward
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Chapter 4 Alkanes and Cycloalkanes Lesson 2; Author: Linda Hanson;https://www.youtube.com/watch?v=AL_CM_Btef4;License: Standard YouTube License, CC-BY
Chapter 4 Alkanes and Cycloalkanes Lesson 1; Author: Linda Hanson;https://www.youtube.com/watch?v=PPIa6EHJMJw;License: Standard Youtube License