The bases in the parent and new strands

Question

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Answer 1

Question

Chapter 17.7, Problem 17.55UTC

Interpretation Introduction

To determine: The bases in the parent and new strands

Expert Solution

Answer to Problem 17.55UTC

Solution:

EBK CHEMISTRY, Chapter 17.7, Problem 17.55UTC , additional homework tip 1

Explanation of Solution

As we know, in DNA, Guanine-Cytosine (G-C) and Adenine-Thymine (A-T) pair together and form hydrogen bonds between the two bases.

Conclusion

Based on the above fact, we can say that missing bases in the parent and new strands are

AGGTCGCCT

TCCAGCGGA

Interpretation Introduction

To determine: The m-RNA sequence using the new strand as template

Expert Solution

Answer to Problem 17.55UTC

Solution:

EBK CHEMISTRY, Chapter 17.7, Problem 17.55UTC , additional homework tip 2

Explanation of Solution

In RNA, the base present is Uracil instead of Thymine, which has a very alike structure to Thymine. As a result, the pairing of Adenine with Uracil (A-U) takes place by the same interaction that is hydrogen bonding as in the A-T base pair.

Conclusion

Based on the above fact we can say that the m-RNA sequence would be AGGUCGCCU

Interpretation Introduction

To determine: The 3 letters symbol for the amino acids that would go into the peptide from the m-RNA in part b

Expert Solution

Answer to Problem 17.55UTC

Solution: Arg-Ser-Pro

Explanation of Solution

A triplet codon is the consecutive three bases on RNA forming a genetic code. The representation of each triplet codon is an amino acid. The sequence of bases on RNA could be seen as sequence of triplet codons. Thus, an amino acid sequence can be determined by the sequence of three letter codons on m-RNA. Each three letter codons either codes for a specific amino acid or codes for a stop signal. In this m-RNA, AGG codes for arginine, UCG codes for serine and CCU codes for proline. So, the amino acid sequence would be:

Arg-Ser-Pro

Conclusion

Based on the explanation as provided, we can say that amino acid sequence would be Arg-Ser-Pro.

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Answer 2

Question

Chapter 17.7, Problem 17.55UTC

Interpretation Introduction

To determine: The bases in the parent and new strands

Expert Solution

Answer to Problem 17.55UTC

Solution:

EBK CHEMISTRY, Chapter 17.7, Problem 17.55UTC , additional homework tip 1

Explanation of Solution

As we know, in DNA, Guanine-Cytosine (G-C) and Adenine-Thymine (A-T) pair together and form hydrogen bonds between the two bases.

Conclusion

Based on the above fact, we can say that missing bases in the parent and new strands are

AGGTCGCCT

TCCAGCGGA

Interpretation Introduction

To determine: The m-RNA sequence using the new strand as template

Expert Solution

Answer to Problem 17.55UTC

Solution:

EBK CHEMISTRY, Chapter 17.7, Problem 17.55UTC , additional homework tip 2

Explanation of Solution

In RNA, the base present is Uracil instead of Thymine, which has a very alike structure to Thymine. As a result, the pairing of Adenine with Uracil (A-U) takes place by the same interaction that is hydrogen bonding as in the A-T base pair.

Conclusion

Based on the above fact we can say that the m-RNA sequence would be AGGUCGCCU

Interpretation Introduction

To determine: The 3 letters symbol for the amino acids that would go into the peptide from the m-RNA in part b

Expert Solution

Answer to Problem 17.55UTC

Solution: Arg-Ser-Pro

Explanation of Solution

A triplet codon is the consecutive three bases on RNA forming a genetic code. The representation of each triplet codon is an amino acid. The sequence of bases on RNA could be seen as sequence of triplet codons. Thus, an amino acid sequence can be determined by the sequence of three letter codons on m-RNA. Each three letter codons either codes for a specific amino acid or codes for a stop signal. In this m-RNA, AGG codes for arginine, UCG codes for serine and CCU codes for proline. So, the amino acid sequence would be:

Arg-Ser-Pro

Conclusion

Based on the explanation as provided, we can say that amino acid sequence would be Arg-Ser-Pro.

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Answer 3

Question

Chapter 17.7, Problem 17.55UTC

Interpretation Introduction

To determine: The bases in the parent and new strands

Expert Solution

Answer to Problem 17.55UTC

Solution:

EBK CHEMISTRY, Chapter 17.7, Problem 17.55UTC , additional homework tip 1

Explanation of Solution

As we know, in DNA, Guanine-Cytosine (G-C) and Adenine-Thymine (A-T) pair together and form hydrogen bonds between the two bases.

Conclusion

Based on the above fact, we can say that missing bases in the parent and new strands are

AGGTCGCCT

TCCAGCGGA

Interpretation Introduction

To determine: The m-RNA sequence using the new strand as template

Expert Solution

Answer to Problem 17.55UTC

Solution:

EBK CHEMISTRY, Chapter 17.7, Problem 17.55UTC , additional homework tip 2

Explanation of Solution

In RNA, the base present is Uracil instead of Thymine, which has a very alike structure to Thymine. As a result, the pairing of Adenine with Uracil (A-U) takes place by the same interaction that is hydrogen bonding as in the A-T base pair.

Conclusion

Based on the above fact we can say that the m-RNA sequence would be AGGUCGCCU

Interpretation Introduction

To determine: The 3 letters symbol for the amino acids that would go into the peptide from the m-RNA in part b

Expert Solution

Answer to Problem 17.55UTC

Solution: Arg-Ser-Pro

Explanation of Solution

A triplet codon is the consecutive three bases on RNA forming a genetic code. The representation of each triplet codon is an amino acid. The sequence of bases on RNA could be seen as sequence of triplet codons. Thus, an amino acid sequence can be determined by the sequence of three letter codons on m-RNA. Each three letter codons either codes for a specific amino acid or codes for a stop signal. In this m-RNA, AGG codes for arginine, UCG codes for serine and CCU codes for proline. So, the amino acid sequence would be:

Arg-Ser-Pro

Conclusion

Based on the explanation as provided, we can say that amino acid sequence would be Arg-Ser-Pro.

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Answer 4

Question

Chapter 17.7, Problem 17.55UTC

Interpretation Introduction

To determine: The bases in the parent and new strands

Expert Solution

Answer to Problem 17.55UTC

Solution:

EBK CHEMISTRY, Chapter 17.7, Problem 17.55UTC , additional homework tip 1

Explanation of Solution

As we know, in DNA, Guanine-Cytosine (G-C) and Adenine-Thymine (A-T) pair together and form hydrogen bonds between the two bases.

Conclusion

Based on the above fact, we can say that missing bases in the parent and new strands are

AGGTCGCCT

TCCAGCGGA

Interpretation Introduction

To determine: The m-RNA sequence using the new strand as template

Expert Solution

Answer to Problem 17.55UTC

Solution:

EBK CHEMISTRY, Chapter 17.7, Problem 17.55UTC , additional homework tip 2

Explanation of Solution

In RNA, the base present is Uracil instead of Thymine, which has a very alike structure to Thymine. As a result, the pairing of Adenine with Uracil (A-U) takes place by the same interaction that is hydrogen bonding as in the A-T base pair.

Conclusion

Based on the above fact we can say that the m-RNA sequence would be AGGUCGCCU

Interpretation Introduction

To determine: The 3 letters symbol for the amino acids that would go into the peptide from the m-RNA in part b

Expert Solution

Answer to Problem 17.55UTC

Solution: Arg-Ser-Pro

Explanation of Solution

A triplet codon is the consecutive three bases on RNA forming a genetic code. The representation of each triplet codon is an amino acid. The sequence of bases on RNA could be seen as sequence of triplet codons. Thus, an amino acid sequence can be determined by the sequence of three letter codons on m-RNA. Each three letter codons either codes for a specific amino acid or codes for a stop signal. In this m-RNA, AGG codes for arginine, UCG codes for serine and CCU codes for proline. So, the amino acid sequence would be:

Arg-Ser-Pro

Conclusion

Based on the explanation as provided, we can say that amino acid sequence would be Arg-Ser-Pro.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 17.7, Problem 17.55UTC

Interpretation Introduction

To determine: The bases in the parent and new strands

Expert Solution

Answer to Problem 17.55UTC

Solution:

EBK CHEMISTRY, Chapter 17.7, Problem 17.55UTC , additional homework tip 1

Explanation of Solution

As we know, in DNA, Guanine-Cytosine (G-C) and Adenine-Thymine (A-T) pair together and form hydrogen bonds between the two bases.

Conclusion

Based on the above fact, we can say that missing bases in the parent and new strands are

AGGTCGCCT

TCCAGCGGA

Interpretation Introduction

To determine: The m-RNA sequence using the new strand as template

Expert Solution

Answer to Problem 17.55UTC

Solution:

EBK CHEMISTRY, Chapter 17.7, Problem 17.55UTC , additional homework tip 2

Explanation of Solution

In RNA, the base present is Uracil instead of Thymine, which has a very alike structure to Thymine. As a result, the pairing of Adenine with Uracil (A-U) takes place by the same interaction that is hydrogen bonding as in the A-T base pair.

Conclusion

Based on the above fact we can say that the m-RNA sequence would be AGGUCGCCU

Interpretation Introduction

To determine: The 3 letters symbol for the amino acids that would go into the peptide from the m-RNA in part b

Expert Solution

Answer to Problem 17.55UTC

Solution: Arg-Ser-Pro

Explanation of Solution

A triplet codon is the consecutive three bases on RNA forming a genetic code. The representation of each triplet codon is an amino acid. The sequence of bases on RNA could be seen as sequence of triplet codons. Thus, an amino acid sequence can be determined by the sequence of three letter codons on m-RNA. Each three letter codons either codes for a specific amino acid or codes for a stop signal. In this m-RNA, AGG codes for arginine, UCG codes for serine and CCU codes for proline. So, the amino acid sequence would be:

Arg-Ser-Pro

Conclusion

Based on the explanation as provided, we can say that amino acid sequence would be Arg-Ser-Pro.

Answer 6

Chapter 17.7, Problem 17.55UTC

Interpretation Introduction

To determine: The bases in the parent and new strands

Expert Solution

Answer to Problem 17.55UTC

Solution:

EBK CHEMISTRY, Chapter 17.7, Problem 17.55UTC , additional homework tip 1

Explanation of Solution

As we know, in DNA, Guanine-Cytosine (G-C) and Adenine-Thymine (A-T) pair together and form hydrogen bonds between the two bases.

Conclusion

Based on the above fact, we can say that missing bases in the parent and new strands are

AGGTCGCCT

TCCAGCGGA

Answer 7

Chapter 17.7, Problem 17.55UTC

Interpretation Introduction

To determine: The bases in the parent and new strands

Answer 8

Expert Solution

Answer to Problem 17.55UTC

Solution:

EBK CHEMISTRY, Chapter 17.7, Problem 17.55UTC , additional homework tip 1

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

As we know, in DNA, Guanine-Cytosine (G-C) and Adenine-Thymine (A-T) pair together and form hydrogen bonds between the two bases.

Answer 13

Conclusion

Based on the above fact, we can say that missing bases in the parent and new strands are

AGGTCGCCT

TCCAGCGGA

Answer 14

Interpretation Introduction

To determine: The m-RNA sequence using the new strand as template

Expert Solution

Answer to Problem 17.55UTC

Solution:

EBK CHEMISTRY, Chapter 17.7, Problem 17.55UTC , additional homework tip 2

Explanation of Solution

In RNA, the base present is Uracil instead of Thymine, which has a very alike structure to Thymine. As a result, the pairing of Adenine with Uracil (A-U) takes place by the same interaction that is hydrogen bonding as in the A-T base pair.

Conclusion

Based on the above fact we can say that the m-RNA sequence would be AGGUCGCCU

Answer 15

Interpretation Introduction

To determine: The m-RNA sequence using the new strand as template

Answer 16

Expert Solution

Answer to Problem 17.55UTC

Solution:

EBK CHEMISTRY, Chapter 17.7, Problem 17.55UTC , additional homework tip 2

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Explanation of Solution

In RNA, the base present is Uracil instead of Thymine, which has a very alike structure to Thymine. As a result, the pairing of Adenine with Uracil (A-U) takes place by the same interaction that is hydrogen bonding as in the A-T base pair.

Answer 21

Conclusion

Based on the above fact we can say that the m-RNA sequence would be AGGUCGCCU

Answer 22

Interpretation Introduction

To determine: The 3 letters symbol for the amino acids that would go into the peptide from the m-RNA in part b

Expert Solution

Answer to Problem 17.55UTC

Solution: Arg-Ser-Pro

Explanation of Solution

A triplet codon is the consecutive three bases on RNA forming a genetic code. The representation of each triplet codon is an amino acid. The sequence of bases on RNA could be seen as sequence of triplet codons. Thus, an amino acid sequence can be determined by the sequence of three letter codons on m-RNA. Each three letter codons either codes for a specific amino acid or codes for a stop signal. In this m-RNA, AGG codes for arginine, UCG codes for serine and CCU codes for proline. So, the amino acid sequence would be:

Arg-Ser-Pro

Conclusion

Based on the explanation as provided, we can say that amino acid sequence would be Arg-Ser-Pro.

Answer 23

Interpretation Introduction

To determine: The 3 letters symbol for the amino acids that would go into the peptide from the m-RNA in part b

Answer 24

Expert Solution

Answer to Problem 17.55UTC

Solution: Arg-Ser-Pro

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Explanation of Solution

A triplet codon is the consecutive three bases on RNA forming a genetic code. The representation of each triplet codon is an amino acid. The sequence of bases on RNA could be seen as sequence of triplet codons. Thus, an amino acid sequence can be determined by the sequence of three letter codons on m-RNA. Each three letter codons either codes for a specific amino acid or codes for a stop signal. In this m-RNA, AGG codes for arginine, UCG codes for serine and CCU codes for proline. So, the amino acid sequence would be:

Arg-Ser-Pro