EBK FUNDAMENTALS OF MATERIALS SCIENCE A
5th Edition
ISBN: 9781119175506
Author: RETHWISCH
Publisher: JOHN WILEY+SONS INC.
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Question
Chapter 17.5, Problem 25QP
(a)
To determine
The type and magnitude of stress.
(b)
To determine
The stress magnitude if a rod 1 m long is used.
(c)
To determine
The type and magnitude of stress if part (a) is cooled from temperature
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Water is discharged into the atmosphere
through a bent nozzle of an angle (a) as
shown in the figure. The cross-sectional
area at the nozzle inlet and outlet are (Ain)
and (Aout), respectively. The discharge
through the nozzle is (Q). The gauge
pressure at the nozzle inlet is (Pin). The
bend lies in a horizontal plane.
Vin
Ain
Aout
Atmosphere
Vout
Problem (9): Given the values of Ain [m²], Aout [m²], Pin [atm], Q [m³/s], and a [degrees], calculate the
magnitude of the reaction force component in x-direction (Rx) in [N].
Givens:
A in = 0.301 m^2
Aout
Pin
=
0.177 m^2
1.338 atm
Q
α
=
0.669 m^3/s
37.183 degrees
Answers:
( 1 ) 23028.076 N
( 2 ) 29697.962 N
( 3 ) 18633.611 N
( 4 ) 14114.988 N
Please answer the following question in the picture and show all of your work please.
Please answer the following questions and make sure you answer each question please.
Chapter 17 Solutions
EBK FUNDAMENTALS OF MATERIALS SCIENCE A
Ch. 17.5 - Prob. 1QPCh. 17.5 - Prob. 2QPCh. 17.5 - Prob. 3QPCh. 17.5 - Prob. 4QPCh. 17.5 - Prob. 5QPCh. 17.5 - Prob. 6QPCh. 17.5 - Prob. 7QPCh. 17.5 - Prob. 8QPCh. 17.5 - Prob. 9QPCh. 17.5 - Prob. 10QP
Ch. 17.5 - Prob. 11QPCh. 17.5 - Prob. 12QPCh. 17.5 - Prob. 13QPCh. 17.5 - Prob. 14QPCh. 17.5 - Prob. 15QPCh. 17.5 - Prob. 16QPCh. 17.5 - Prob. 17QPCh. 17.5 - Prob. 18QPCh. 17.5 - Prob. 19QPCh. 17.5 - Prob. 20QPCh. 17.5 - Prob. 21QPCh. 17.5 - Prob. 22QPCh. 17.5 - Prob. 23QPCh. 17.5 - Prob. 24QPCh. 17.5 - Prob. 25QPCh. 17.5 - Prob. 26QPCh. 17.5 - Prob. 27QPCh. 17.5 - Prob. 28QPCh. 17.5 - Prob. 29QPCh. 17.5 - Prob. 1DPCh. 17.5 - Prob. 2DPCh. 17.5 - Prob. 3DPCh. 17.5 - Prob. 4DPCh. 17.5 - Prob. 1FEQPCh. 17.5 - Prob. 2FEQPCh. 17.5 - Prob. 3FEQP
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- Water is discharged into the atmosphere through a bent nozzle of an angle (a) as shown in the figure. The cross-sectional area at the nozzle inlet and outlet are (Ain) and (Aout), respectively. The discharge through the nozzle is (Q). The gauge pressure at the nozzle inlet is (Pin). The bend lies in a horizontal plane. Ain Vin Aout X Atmosphere Vout Problem (10): Given the values of Ain [m2], Aout [m²], Pin [atm], Q [m³/s], and a [degrees], calculate the magnitude of the reaction force component in y-direction (Ry) in [N]. Givens: A in 0.169 m^2 A out Pin 0.143 m^2 0.552 atm = Q α 0.367 m^3/s = 31.72 degrees Answers: ( 1 ) 6264.193 N (2) 12041.886 N ( 3 ) 8715.747 N ( 4 ) 7139.937 Narrow_forwardProblem (12): A pump is being used to lift water from the bottom tank to the top tank in a pipe of diameter (d) at a discharge (Q). The pipe system comprises four Long radius 90° threaded elbows. The pipe entrance is sharp-edged, and the pipe exit is sudden. A Ball valve (1/3 closed) is used to control the discharge in the pipeline. Given the values of Q [Lit/s], and d [cm], calculate the power loss due to components (i.e., minor losses) in the pipe (Wminor-loss) in [W]. Givens: Q = 12.275 lit/s d = 6.266 cm Answers: ( 1 ) 1142.006 W (2) 952.086 W ( 3 ) 1225.555 W ( 4 ) 1331.216 W Loss Coefficients for Pipe Components (h,= K,Y) Component a. Elbows KL elbow Regular 90°, flanged 0.3 Regular 90°, threaded 1.5 Long radius 90°, flanged 0.2 V 90° elbow Long radius 90°, threaded 0.7 Long radius 45°, flanged 0.2 0.4 Regular 45°, threaded . 180° return bends 180° return bend, flanged 0.2 V 45° elbow 180° return bend, threaded 1.5 c. Tees Line flow, flanged 0.2 Line flow, threaded 0.9 180°…arrow_forward80 V 300 Ω t = 0 500 i(t) Vc(t) 40 nF 2,5 mH -arrow_forward
- Compute for the stresses (initial, const and final stage) and check for compliance in NSCP provisions. Also compute the following: 1. Compute and check if the section is Uncracked, Transition or Cracked as per NSCP. 2. Compute for its flexural capacity and check if it could carry the given load. BEAM SECTION NOT TO SCALE 1400mm 300 $1098 400 */ 400*300* 300 200 300 100 ORIGINAL SECTION/PRECA CAST-IN-PLACE (CIP) PART PRECAST LOADING AT SERVICE M • 21 KN (DEAD LOAD ONLY) 21KN 4.75m 9.25m CIVEN DATA STRANDS: 12-02 AT 120KN/STRAND (GOMM FROM BOTTOM) 8-2 AT 120HN/STRAND (120mm FROM BOTTOM) fc 42.5 MPa (BEAM) fc 38 MPa (CIP) f'a = 80% or fa fp-1860 MPa ESTRANDS 1976Pa OONG 23.6/m³ LOES 1-8% Loss 18% APPLY 3M LIVE LOAD AT CONST. PHASEarrow_forward4. Determine the stability of the cantilever shown in the figure below (use Coulomb earth theory for the lateral stress due to the backfill material). 1 m 0.5 m Backfill 7 = 18.5 kN/m³ • = 30° 20 6 = 20° 6 m Y₁ = 24 kN/m³ 1.2 m 1 m 4.5 m Base soil Clay: 7 = 19 kN/m³,0 = 30%, 0,, = 20°, s,, = 94 kPa a. With s₁ = c = 94 kPa (disregard values), determine allowable soil bearing capacity of the base soil if the factor of safety is equal to 3. b. Determine the FS against overturning. C. Determine the FS against sliding if the coefficient of friction between footing concrete base and soil is b. d. Determine the FS for bearing capacity.arrow_forwardDirections: Show your solutions explicitly, i.e., do not just write the final answer. 1. A wall footing is to be constructed on a clay soil 1.4 below the ground. The footing is to support a wall that imposes a load of 130 kN per meter of wall length. Considering general shear failure, determine the following: 130 kN/mm 1.4 m a. Footing width if the factor of safety is 3. b. Ultimate bearing capacity if B = 0.95 m. C. New factor of safety. y = 17.92 kN/m² c = 14.5 kPa $ = 30° 1.5 m and has its hottom 2 m below the ground surface.arrow_forward
- 2. A square footing shown has a dimension of 1.5 m x 1.5 m and has its bottom 2 m below the ground surface. The groundwater table is located at a depth of 3 m below the ground surface. Assume a general shear failure. Determine the following: 2 m y = 16 kN/m³ c = 14.5 kPa → = 28° 3 m 1,5 m ysat 18.5 kN/m³ a. Ultimate bearing capacity of the soil beneath the footing (in kPa). b. Allowable bearing capacity if it has a factor of safety of 3 (in kPa). C. Allowable load that the footing could carry (in kN). d. Allowable net bearing capacity if factor of safety is 3. Allowable net load if factor of safety is 3.arrow_forwardProblem (11): A pipe discharges an unknown fluid into the atmosphere from a tank of depth (h) through a pipe of length (L), and diameter (d). Given the values of L [m], d [cm], and (h) [cm], calculate the discharge rate (Q) [lit/s] that would maintain Laminar flow in the pipe with a Reynolds number of Re-1500. Ignore minor losses. Givens: L = 139.364 m d = 12.614 cm h = 76.609 cm Answers: ( 1 ) 6.911 lit/s (2) 8.179 lit/s ( 3 ) 4.244 lit/s (4) 4.987 lit/s h darrow_forwardProblem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and (y2), respectively. Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s]. Givens: y1 = 4.112 m y2 = 0.387 m b = 0.942 m Answers: ( 1 ) 1880.186 lit/s ( 2 ) 4042.945 lit/s ( 3 ) 2553.11 lit/s ( 4 ) 3130.448 lit/sarrow_forward
- Problem (14): A pump is being used to lift water from an underground tank through a pipe of diameter (d) at discharge (Q). The total head loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h where (V) is the flow velocity in the pipe. The elevation difference between the pump and tank surface is (h). Given the values of h [cm], d [cm], and K [-], calculate the maximum discharge Q [Lit/s] beyond which cavitation would take place at the pump entrance. Assume Turbulent flow conditions. Givens: h = 120.31 cm d = 14.455 cm K = 8.976 Q Answers: (1) 94.917 lit/s (2) 49.048 lit/s ( 3 ) 80.722 lit/s 68.588 lit/s 4arrow_forwardProblem (13): A pump is being used to lift water from the bottom tank to the top tank in a galvanized iron pipe at a discharge (Q). The length and diameter of the pipe section from the bottom tank to the pump are (L₁) and (d₁), respectively. The length and diameter of the pipe section from the pump to the top tank are (L2) and (d2), respectively. Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m], calculate total head loss due to friction (i.e., major loss) in the pipe (hmajor-loss) in [cm]. Givens: L₁,d₁ Pump L₂,d2 오 0.533 lit/s L1 = 6920.729 m d1 = 1.065 m L2 = 70.946 m d2 0.072 m Answers: (1) 3.069 cm (2) 3.914 cm ( 3 ) 2.519 cm ( 4 ) 1.855 cm TABLE 8.1 Equivalent Roughness for New Pipes Pipe Riveted steel Concrete Wood stave Cast iron Galvanized iron Equivalent Roughness, & Feet Millimeters 0.003-0.03 0.9-9.0 0.001-0.01 0.3-3.0 0.0006-0.003 0.18-0.9 0.00085 0.26 0.0005 0.15 0.045 0.000005 0.0015 0.0 (smooth) 0.0 (smooth) Commercial steel or wrought iron 0.00015 Drawn…arrow_forwardThe flow rate is 12.275 Liters/s and the diameter is 6.266 cm.arrow_forward
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