Explanation Given: The ∬ G x 2 z d S where G is the x 2 + y 2 = 4 , and 0 ≤ z ≤ 3 . Formula used: Calculation: To calculate ∬ G x 2 z d S put the limit of x and z . Here x varies from − 2 to 2 and 0 ≤ z ≤ 3 . So; ∬ G x 2 z d S = ∫ − 2 2 ∫ 0 3 x 2 z d z d x = ∫ − 2 2 [ z 2 2...

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Chapter 17.4, Problem 39E

To determine

The $\iint_{G} x^{2} z d S$ where $G$ is the $x^{2} + y^{2} = 4$ , and $0 \leq z \leq 3$ .

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Chapter 17.4, Problem 38E

Chapter 17.4, Problem 40E

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Chapter 17 Solutions

Calculus - Standalone book

Ch. 17.1 - Prob. 1PQ Ch. 17.1 - Prob. 2PQ Ch. 17.1 - Prob. 3PQ Ch. 17.1 - Prob. 4PQ Ch. 17.1 - Prob. 1E Ch. 17.1 - Prob. 2E Ch. 17.1 - Prob. 3E Ch. 17.1 - Prob. 4E Ch. 17.1 - Prob. 5E Ch. 17.1 - Prob. 6E

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The ∬ G x 2 z d S where G is the x 2 + y 2 = 4 , and 0 ≤ z ≤ 3 .

Solution Summary: The author explains the formula used to determine the value of G x 2 z d S.

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The ∬Gx2zdS where G is the x2+y2=4, and 0≤z≤3.

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Chapter 17 Solutions

The $\iint_{G} x^{2} z d S$ where $G$ is the $x^{2} + y^{2} = 4$ , and $0 \leq z \leq 3$ .