GEN COMBO LOOSELEAF MICROBIOLOGY:A SYSTEMS APPROACH; CONNECT ACCESS CARD
GEN COMBO LOOSELEAF MICROBIOLOGY:A SYSTEMS APPROACH; CONNECT ACCESS CARD
5th Edition
ISBN: 9781260149364
Author: Marjorie Kelly Cowan Professor
Publisher: McGraw-Hill Education
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Chapter 17.3, Problem 14AYP

Explain the difference between a direct and an indirect ELISA.

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. Consider a base substitution mutation that occurred in a DNA sequence that resulted in a change in the encoded protein from the amino acid glutamic acid to aspartic acid. Normally the glutamic acid amino acid is located on the outside of the soluble protein but not near an active site. O-H¨ A. What type of mutation occurred? O-H B. What 2 types of chemical bonds are found in the R-groups of each amino acid? The R groups are shaded. CH2 CH2 CH2 H2N-C-COOH H2N-C-COOH 1 H Glutamic acid H Aspartic acid C. What 2 types of bonds could each R-group of each of these amino acids form with other molecules? D. Consider the chemical properties of the two amino acids and the location of the amino acid in the protein. Explain what effect this mutation will have on this protein's function and why.
engineered constructs that consist of hollow fibers are acting as synthetic capillaries, around which cells have been loaded. The cellular space around a single fiber can be modeled as if it were a Krogh tissue cylinder. Each fiber has an outside “capillary” radius of 100 µm and the “tissue” radius can be taken as 200 µm. The following values apply to the device:R0 = 20 µM/secaO2 = 1.35 µM/mmHgDO2,T = 1.67 x 10-5 cm2/secPO2,m = 4 x 10-3 cm/secInstead of blood inside the fibers, the oxygen transport and tissue consumption are being investigated by usingan aqueous solution saturated with pure oxygen. As a result, there is no mass transfer resistance in the synthetic“capillary”, only that due to the membrane itself. Rather than accounting for pO2 variations along the length ofthe fiber, use an average value in the “capillary” of 130 mmHg.Is the tissue fully oxygenated?
Molecular Biology Please help with question. thank you You are studying the expression of the lac operon. You have isolated mutants as described below. In the presence of glucose, explain/describe what would happen, for each mutant, to the expression of the lac operon when you add lactose AND what would happen when the bacteria has used up all of the lactose (if the mutant is able to use lactose).5. Mutations in the lac operator that strengthen the binding of the lac repressor 200 fold 6. Mutations in the promoter that prevent binding of RNA polymerase 7. Mutations in CRP/CAP protein that prevent binding of cAMP8. Mutations in sigma factor that prevent binding of sigma to core RNA polymerase
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