EBK BUSINESS MATH
11th Edition
ISBN: 8220103632072
Author: NOBLE
Publisher: Pearson Education (US)
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Chapter 17.2, Problem 1-1SC
To determine
To Calculate: The depreciation for the
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ind
Original: 100-200 = 20,000
200400=20,000 80
602=3600 694761
=4
4x1.3225-6.29
4761/3600 = 1-3225 5.29-1058msy
6). The dose to the body was 200 mSv. Find
the dose to the lung in mrem?
W 200ms
20
2.15
and
8) A technique of 20 mAs, 40 kV produces a
f4 Sy Find the dose to the Thyroid in
original ssD
400x (100) 2 400 x (14)=100
34
10or (2)² = 100 × (0-85) = 100 x = 72.25
100x
40
72.25 =36.13
500
36.13 13.84
O. 7225
12x13.84≈ 166.08mAs
10) The dose of a radiograph was 100 mSv with a technique of: 10 mAs, 180 kV at 200 cm and
tabletop. If the technique is changed to: 20 mAs, 153 kV at 100 cm using a 5:1 grid then find the
new dose in rem to the Lungs.
11) A radiographic technique produces an exposure index of EI= 300 and TEI=600 at a source-
to-image receptor distance (SID) of 200 cm, 100 kV, 5:1 grid using 10 mAs. If the technique is
changed to 100 cm and 85 kV and 5 mAs with table top find the new exposure index? What is
the value of DI?
10
exam review please help!
Chapter 17 Solutions
EBK BUSINESS MATH
Ch. 17.1 - Prob. 1-1SCCh. 17.1 - Prob. 1-2SCCh. 17.1 - Prob. 1-3SCCh. 17.1 - Prob. 1-4SCCh. 17.1 - Prob. 1-5SCCh. 17.1 - Prob. 2-1SCCh. 17.1 - Prob. 2-2SCCh. 17.1 - Prob. 2-3SCCh. 17.1 - Prob. 2-4SCCh. 17.1 - Prob. 3-1SC
Ch. 17.1 - Prob. 3-2SCCh. 17.1 - Prob. 3-3SCCh. 17.1 - Prob. 3-4SCCh. 17.1 - Prob. 4-1SCCh. 17.1 - Prob. 4-2SCCh. 17.1 - Prob. 4-3SCCh. 17.1 - Prob. 4-4SCCh. 17.1 - Prob. 1SECh. 17.1 - Prob. 2SECh. 17.1 - Prob. 3SECh. 17.1 - Prob. 4SECh. 17.1 - Prob. 5SECh. 17.1 - Prob. 6SECh. 17.1 - Prob. 7SECh. 17.1 - Prob. 8SECh. 17.1 - Prob. 9SECh. 17.1 - Prob. 10SECh. 17.1 - Prob. 11SECh. 17.1 - Prob. 12SECh. 17.1 - Prob. 13SECh. 17.1 - Prob. 14SECh. 17.1 - Prob. 15SECh. 17.1 - Prob. 16SECh. 17.1 - Prob. 17SECh. 17.1 - Prob. 18SECh. 17.1 - Prob. 19SECh. 17.1 - Prob. 20SECh. 17.1 - Prob. 21SECh. 17.1 - Prob. 22SECh. 17.1 - Prob. 23SECh. 17.2 - Prob. 1-1SCCh. 17.2 - Prob. 1-2SCCh. 17.2 - Prob. 1-3SCCh. 17.2 - Prob. 1-4SCCh. 17.2 - Prob. 2-1SCCh. 17.2 - Prob. 2-2SCCh. 17.2 - Prob. 2-3SCCh. 17.2 - Prob. 2-4SCCh. 17.2 - Prob. 1SECh. 17.2 - Prob. 2SECh. 17.2 - Prob. 3SECh. 17.2 - Prob. 4SECh. 17.2 - Prob. 5SECh. 17.2 - Prob. 6SECh. 17.2 - Prob. 7SECh. 17.2 - Prob. 8SECh. 17.2 - Prob. 9SECh. 17.2 - Prob. 10SECh. 17.2 - Prob. 11SECh. 17.2 - Prob. 12SECh. 17.2 - Prob. 13SECh. 17.2 - Prob. 14SECh. 17.2 - Prob. 15SECh. 17 - Prob. 1ESCh. 17 - Prob. 2ESCh. 17 - Prob. 3ESCh. 17 - Prob. 4ESCh. 17 - Prob. 5ESCh. 17 - Prob. 6ESCh. 17 - Prob. 7ESCh. 17 - Prob. 8ESCh. 17 - Prob. 9ESCh. 17 - Prob. 10ESCh. 17 - Prob. 11ESCh. 17 - Prob. 12ESCh. 17 - Prob. 13ESCh. 17 - Prob. 14ESCh. 17 - Prob. 15ESCh. 17 - Prob. 16ESCh. 17 - Prob. 17ESCh. 17 - Prob. 18ESCh. 17 - Prob. 19ESCh. 17 - Prob. 20ESCh. 17 - Prob. 21ESCh. 17 - Prob. 22ESCh. 17 - Prob. 23ESCh. 17 - Prob. 24ESCh. 17 - Prob. 25ESCh. 17 - Prob. 26ESCh. 17 - Prob. 27ESCh. 17 - Prob. 28ESCh. 17 - Prob. 29ESCh. 17 - Prob. 30ESCh. 17 - Prob. 31ESCh. 17 - Prob. 32ESCh. 17 - Prob. 33ESCh. 17 - Prob. 34ESCh. 17 - Prob. 35ESCh. 17 - Prob. 36ESCh. 17 - Prob. 37ESCh. 17 - Prob. 38ESCh. 17 - Prob. 39ESCh. 17 - Prob. 40ESCh. 17 - Prob. 1PTCh. 17 - Prob. 2PTCh. 17 - Prob. 3PTCh. 17 - Prob. 4PTCh. 17 - Prob. 5PTCh. 17 - Prob. 6PTCh. 17 - Prob. 7PTCh. 17 - Prob. 8PTCh. 17 - Prob. 9PTCh. 17 - Prob. 10PTCh. 17 - Prob. 11PTCh. 17 - Prob. 12PTCh. 17 - Prob. 1CTCh. 17 - Prob. 2CTCh. 17 - Prob. 3CTCh. 17 - Prob. 4CTCh. 17 - Prob. 5CTCh. 17 - Prob. 6CTCh. 17 - Prob. 7CTCh. 17 - Prob. 8CTCh. 17 - Prob. 1CPCh. 17 - Prob. 2CPCh. 17 - Prob. 1CS1Ch. 17 - Prob. 2CS1Ch. 17 - Prob. 3CS1Ch. 17 - Prob. 4CS1Ch. 17 - Prob. 1CS2Ch. 17 - Prob. 2CS2Ch. 17 - Prob. 3CS2
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- 0. 75 and 34 KV arved fromise to 75 halfed NAME Genesis Ward 0 mAs is 40 #2). A technique involves 150 mAs, 40 kV and produces an intensity of 2 R. are gone down KV C15%! In = 200% Find the new intensity in mGya, using 300 mAs and 46 kV? =100 206a 150mAS 40KV 2R kv 150 is so divide 00 mA, 200 alue of 100. Boomts 46KY 4). A technique is taken with 100 mA, 200 ms, 60 kV and produces 200 mSv.arrow_forwardFi is 2 O 2 ms, #3). A technique is taken with 100 mA, 200 60 kV and produces an EI value of 100. Find the EI value when this technique is changed to 200 mA, 100 ms, 69 kV? 4) m 2arrow_forward11) A radiographic technique produces an exposure index of EI= 300 and TEI=600 at a source- to-image receptor distance (SID) of 200 cm, 100 kV, 5:1 grid using 10 mAs. If the technique is changed to 100 cm and 85 kV and 5 mAs with table top find the new exposure index? What is the value of DI?arrow_forward
- exam review please help!arrow_forward5). The dose to the breast was 120 mGy find the entire body dose represented in rad?arrow_forward1000 x= 800mGy to body X= = rad 7). If EI=300, TEI=500 with mAs = 20 and you want to decrease the kV by 15% then 0.8 Gy what is the new mAs value to set DI=0? =0% 100-00 Dorad 8) A te dose of rem w kV? 2 tom i sv 4sv 48rem to thyr. KV+ I formula K In = Fox2 kV (1979) (48 rem = 8.2 = 16. SVx 100 160oren-body 1600.0.03=X I M M Earrow_forward
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- Solve for a 25 55 30 a=?arrow_forwardvide 0. OMS its 150MAS 40k 300mts 46KV 4). A technique is taken with 100 mA, 200 ms, 60 kV and produces 200 mSv. Find the intensity in rem when this technique is changed to 200 mA, 400 ms, 69 kV? nd 5). The dose to the body was 200 mSy. Findarrow_forwardGenesis Ward #9) A good exposure is taken using a technique of 12 mAs, 200 cm SSD,40kv, table top, and produces an EI value of 400 with a TEI value of 500. Find the new mAs value required to set DI=0, if a 100 cm SSD,34kV and a 6:1 grid were substituted. 12 MAS, 200cm SSD, 40kv E1 = 400 TEL = 500 of a radiograph was 100 mSv with a technique of: 10 mAs, 180 kV at 200 cm and 2 IV at 00 cm using a 5:1 grid then find thearrow_forward
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