Explanation Given information: Load support P = 1500 N . The maximum shear stress in the pin is τ s = 150 MPa . Factor of safety at pins at B and C is 2 . Free body diagram of bike: For the system to be in equilibrium, ∑ F H = 0 ∑ F V = 0 ∑ M A = 0 Shear stress in pin is given by using the formula of shear stress. τ s = F s h e a r A s h e a r Shear area is given by: A s h e a r a t B = 2 × s h e a r i n g a r e a = 2 × π 4 d B 2 A s h e a r a t C = 2 × s h e a r i n g a r e a = 2 × π 4 d C 2 Factor of safety is given by: F O S = τ f a i l τ a l l o w a b l e Calculation: For the system to be in the horizontal equilibrium, ∑ F H = 0 F B D cos 60 ° + R C x = 0 R C x = − 3 2 F B D ............. 1 For the system to be in the vertical equilibrium, ∑ F V = 0 F B D sin 60 ° + R C y − P = 0 F B D sin 60 ° + R C y = P F B D × 1 2 + R C y = 1500 N ............. 2 Moment equilibrium about C . ∑ M C = 0 F B D cos 60 ° × 30 mm + F B D sin 60 ° × 100 mm − P × 400 mm = 0 3 2 F B D × 30 mm + F B D × 1 2 × 100 mm = P × 400 mm 75.98 F B D mm = 1500 N × 400 mm F B D = 600000 N-mm 75.98 mm F B D = 7896.82 N

11th Edition

ISBN: 9780137605460

Author: Russell C. Hibbeler

Publisher: Pearson Education (US)

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Question

Chapter 1.7, Problem 88P

To determine

The minimum diameter of pins B and C .

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Chapter 1.7, Problem 87P

Chapter 1.7, Problem 89P

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Mechanics of Materials

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The minimum diameter of pins B and C .

Solution Summary: The author explains the minimum diameter of pins B and C, and the maximum shear stress in the pin.

The minimum diameter of pins B and C .

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