The change in enthalpy of the reaction is to be calculated.

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It is not unexpected that the methoxyl substituent on a cyclohexane ring prefers to adopt the equatorial conformation. OMe H A G₂ = +0.6 kcal/mol OMe What is unexpected is that the closely related 2-methoxytetrahydropyran prefers the axial conformation: H H OMe OMe A Gp=-0.6 kcal/mol Methoxy: CH3O group Please be specific and clearly write the reason why this is observed. This effect that provides stabilization of the axial OCH 3 group in this molecule is called the anomeric effect. [Recall in the way of example, the staggered conformer of ethane is more stable than eclipsed owing to bonding MO interacting with anti-bonding MO...]

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Chapter 17, Problem 78E

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Interpretation: The change in enthalpy of the reaction is to be calculated.

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