The time required for the decay of technetium-99m from 0.050 milligram to 6.3 × 10 − 3 mg , having a half-life of 6.0 hours is to be determined. Concept introduction: The half-life of a substance is the numerical value in which the given radioactive substance is assumed to be reduced to half of its initial number. The half-life for a given substance is represented by t 1/2 . In case, the decay of a radioactive substance is exponential, it will remain constant for the life time of the substance. After each half-life period, the amount of the substance is reduced to half of the initial number. The time required for the decay of the substance to a given amount of substance can be calculated using the formula mentioned below: ln ( N t N 0 ) = − kt In the above equation, ‘N t ’ represents the mass of the radioactive substance after a certain time interval t, ‘N 0 ’ indicates the initial mass of the radioactive material, ‘k’ represents the decay constant and ‘t’ represents the time interval for the half-life (t 1/2 ).

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Answer 1

Question

Chapter 17, Problem 71E

Interpretation Introduction

Interpretation:

The time required for the decay of technetium-99m from $0.050 milligram$ to $6.3×10−3 mg$ , having a half-life of 6.0 hours is to be determined.

Concept introduction:

The half-life of a substance is the numerical value in which the given radioactive substance is assumed to be reduced to half of its initial number. The half-life for a given substance is represented by t_1/2.

In case, the decay of a radioactive substance is exponential, it will remain constant for the life time of the substance.

After each half-life period, the amount of the substance is reduced to half of the initial number.

The time required for the decay of the substance to a given amount of substance can be calculated using the formula mentioned below:

$ln(NtN0)=−kt$

In the above equation, ‘N_t’ represents the mass of the radioactive substance after a certain time interval t, ‘N₀’ indicates the initial mass of the radioactive material, ‘k’ represents the decay constant and ‘t’ represents the time interval for the half-life (t_1/2).

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Answer 2

Question

Chapter 17, Problem 71E

Interpretation Introduction

Interpretation:

The time required for the decay of technetium-99m from $0.050 milligram$ to $6.3×10−3 mg$ , having a half-life of 6.0 hours is to be determined.

Concept introduction:

The half-life of a substance is the numerical value in which the given radioactive substance is assumed to be reduced to half of its initial number. The half-life for a given substance is represented by t_1/2.

In case, the decay of a radioactive substance is exponential, it will remain constant for the life time of the substance.

After each half-life period, the amount of the substance is reduced to half of the initial number.

The time required for the decay of the substance to a given amount of substance can be calculated using the formula mentioned below:

$ln(NtN0)=−kt$

In the above equation, ‘N_t’ represents the mass of the radioactive substance after a certain time interval t, ‘N₀’ indicates the initial mass of the radioactive material, ‘k’ represents the decay constant and ‘t’ represents the time interval for the half-life (t_1/2).

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Answer 3

Question

Chapter 17, Problem 71E

Interpretation Introduction

Interpretation:

The time required for the decay of technetium-99m from $0.050 milligram$ to $6.3×10−3 mg$ , having a half-life of 6.0 hours is to be determined.

Concept introduction:

The half-life of a substance is the numerical value in which the given radioactive substance is assumed to be reduced to half of its initial number. The half-life for a given substance is represented by t_1/2.

In case, the decay of a radioactive substance is exponential, it will remain constant for the life time of the substance.

After each half-life period, the amount of the substance is reduced to half of the initial number.

The time required for the decay of the substance to a given amount of substance can be calculated using the formula mentioned below:

$ln(NtN0)=−kt$

In the above equation, ‘N_t’ represents the mass of the radioactive substance after a certain time interval t, ‘N₀’ indicates the initial mass of the radioactive material, ‘k’ represents the decay constant and ‘t’ represents the time interval for the half-life (t_1/2).

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Answer 4

Question

Chapter 17, Problem 71E

Interpretation Introduction

Interpretation:

The time required for the decay of technetium-99m from $0.050 milligram$ to $6.3×10−3 mg$ , having a half-life of 6.0 hours is to be determined.

Concept introduction:

The half-life of a substance is the numerical value in which the given radioactive substance is assumed to be reduced to half of its initial number. The half-life for a given substance is represented by t_1/2.

In case, the decay of a radioactive substance is exponential, it will remain constant for the life time of the substance.

After each half-life period, the amount of the substance is reduced to half of the initial number.

The time required for the decay of the substance to a given amount of substance can be calculated using the formula mentioned below:

$ln(NtN0)=−kt$

In the above equation, ‘N_t’ represents the mass of the radioactive substance after a certain time interval t, ‘N₀’ indicates the initial mass of the radioactive material, ‘k’ represents the decay constant and ‘t’ represents the time interval for the half-life (t_1/2).

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Answer 5

Chapter 17, Problem 71E

Interpretation Introduction

Interpretation:

The time required for the decay of technetium-99m from $0.050 milligram$ to $6.3×10−3 mg$ , having a half-life of 6.0 hours is to be determined.

Concept introduction:

The half-life of a substance is the numerical value in which the given radioactive substance is assumed to be reduced to half of its initial number. The half-life for a given substance is represented by t_1/2.

In case, the decay of a radioactive substance is exponential, it will remain constant for the life time of the substance.

After each half-life period, the amount of the substance is reduced to half of the initial number.

The time required for the decay of the substance to a given amount of substance can be calculated using the formula mentioned below:

$ln(NtN0)=−kt$

In the above equation, ‘N_t’ represents the mass of the radioactive substance after a certain time interval t, ‘N₀’ indicates the initial mass of the radioactive material, ‘k’ represents the decay constant and ‘t’ represents the time interval for the half-life (t_1/2).

Answer 6

Chapter 17, Problem 71E

Interpretation Introduction

Interpretation:

The time required for the decay of technetium-99m from $0.050 milligram$ to $6.3×10−3 mg$ , having a half-life of 6.0 hours is to be determined.

Concept introduction:

The half-life of a substance is the numerical value in which the given radioactive substance is assumed to be reduced to half of its initial number. The half-life for a given substance is represented by t_1/2.

In case, the decay of a radioactive substance is exponential, it will remain constant for the life time of the substance.

After each half-life period, the amount of the substance is reduced to half of the initial number.

The time required for the decay of the substance to a given amount of substance can be calculated using the formula mentioned below:

$ln(NtN0)=−kt$

In the above equation, ‘N_t’ represents the mass of the radioactive substance after a certain time interval t, ‘N₀’ indicates the initial mass of the radioactive material, ‘k’ represents the decay constant and ‘t’ represents the time interval for the half-life (t_1/2).

Answer 7

Chapter 17, Problem 71E

Interpretation Introduction

Interpretation:

The time required for the decay of technetium-99m from $0.050 milligram$ to $6.3×10−3 mg$ , having a half-life of 6.0 hours is to be determined.

Concept introduction:

The half-life of a substance is the numerical value in which the given radioactive substance is assumed to be reduced to half of its initial number. The half-life for a given substance is represented by t_1/2.

In case, the decay of a radioactive substance is exponential, it will remain constant for the life time of the substance.

After each half-life period, the amount of the substance is reduced to half of the initial number.

The time required for the decay of the substance to a given amount of substance can be calculated using the formula mentioned below:

$ln(NtN0)=−kt$

In the above equation, ‘N_t’ represents the mass of the radioactive substance after a certain time interval t, ‘N₀’ indicates the initial mass of the radioactive material, ‘k’ represents the decay constant and ‘t’ represents the time interval for the half-life (t_1/2).

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 17 - Prob. 1SAQ Ch. 17 - Prob. 2SAQ Ch. 17 - Prob. 3SAQ Ch. 17 - Prob. 4SAQ Ch. 17 - Prob. 5SAQ Ch. 17 - Prob. 6SAQ Ch. 17 - Prob. 7SAQ Ch. 17 - Prob. 8SAQ Ch. 17 - Prob. 9SAQ Ch. 17 - Prob. 10SAQ

Solution Summary: The author explains that the half-life of a given radioactive substance is represented by t 1/2. The amount of the substance decays to 6.3times 10-3mg in

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