
Concept explainers
(a)
To show: The left hand side of the given equation is
(a)

Answer to Problem 50CP
Explanation of Solution
Given info: The frequency of wave is
Write the expression of the
Multiply
Integrate the above equation over on period of time
The term
The left side of the equation is,
Conclusion:
Therefore, the left hand side of the given equation is
(b)
To show: The terms of the right hand side of the given equation involving
(b)

Answer to Problem 50CP
Explanation of Solution
Given info: The frequency of wave is
The part of the right hand of the equation (1) involving
Conclusion:
Therefore, the terms of the right hand side of the given equation involving
(c)
To show: The terms of the right hand side of the given equation involving
(c)

Answer to Problem 50CP
Explanation of Solution
Given info: The frequency of wave is
The part of the right hand of the equation (1) involving
The integration of the
Conclusion:
Therefore, the terms of the right hand side of the given equation involving
(d)
To show: The entire right hand side of the equation reduces to
(d)

Answer to Problem 50CP
Explanation of Solution
Given info: The frequency of wave is
The right hand side of the equation (1) is,
The integer
Substitute
Conclusion:
Therefore, the entire right hand side of the equation reduces to
(e)
To show: The Fourier series expansion for a square wave is
(e)

Answer to Problem 50CP
Explanation of Solution
Given info: The frequency of wave is
The general equation of
From the part (a), The value of
From the part (d), the value of
Therefore,
Substitute
Substitute
Substitute
Conclusion:
Therefore, the Fourier series expansion for a square wave is
Want to see more full solutions like this?
Chapter 17 Solutions
PHYSICS:F/SCI.+ENGRS.(LL)-W/WEBASSIGN
- Refer to the image attachedarrow_forwardShrinking Loop. A circular loop of flexible iron wire has an initial circumference of 161 cm , but its circumference is decreasing at a constant rate of 15.0 cm/s due to a tangential pull on the wire. The loop is in a constant uniform magnetic field of magnitude 1.00 T , which is oriented perpendicular to the plane of the loop. Assume that you are facing the loop and that the magnetic field points into the loop. Find the magnitude of the emf E induced in the loop after exactly time 9.00 s has passed since the circumference of the loop started to decrease. Find the direction of the induced current in the loop as viewed looking along the direction of the magnetic field. Please explain all stepsarrow_forwardMake up an application physics principle problem that provides three (3) significant equations based on the concepts of capacitors and ohm's law.arrow_forward
- A straight horizontal garden hose 38.0 m long with an interior diameter of 1.50 cm is used to deliver 20oC water at the rate of 0.590 liters/s. Assuming that Poiseuille's Law applies, estimate the pressure drop (in Pa) from one end of the hose to the other.arrow_forwardA rectangle measuring 30.0 cm by 40.0 cm is located inside a region of a spatially uniform magnetic field of 1.70 T , with the field perpendicular to the plane of the coil (the figure (Figure 1)). The coil is pulled out at a steady rate of 2.00 cm/s traveling perpendicular to the field lines. The region of the field ends abruptly as shown. Find the emf induced in this coil when it is all inside the field, when it is partly in the field, and when it is fully outside. Please show all steps.arrow_forwardA rectangular circuit is moved at a constant velocity of 3.00 m/s into, through, and then out of a uniform 1.25 T magnetic field, as shown in the figure (Figure 1). The magnetic field region is considerably wider than 50.0 cm . Find the direction (clockwise or counterclockwise) of the current induced in the circuit as it is going into the magnetic field (the first case), totally within the magnetic field but still moving (the second case), and moving out of the field (the third case). Find the magnitude of the current induced in the circuit as it is going into the magnetic field . Find the magnitude of the current induced in the circuit as it is totally within the magnetic field but still moving. Find the magnitude of the current induced in the circuit as it is moving out of the field. Please show all stepsarrow_forward
- Shrinking Loop. A circular loop of flexible iron wire has an initial circumference of 161 cm , but its circumference is decreasing at a constant rate of 15.0 cm/s due to a tangential pull on the wire. The loop is in a constant uniform magnetic field of magnitude 1.00 T , which is oriented perpendicular to the plane of the loop. Assume that you are facing the loop and that the magnetic field points into the loop. Find the magnitude of the emf E induced in the loop after exactly time 9.00 s has passed since the circumference of the loop started to decrease. Find the direction of the induced current in the loop as viewed looking along the direction of the magnetic field. Please explain all stepsarrow_forwardA circular loop of wire with radius 0.0480 m and resistance 0.163 Ω is in a region of spatially uniform magnetic field, as shown in the following figure (Figure 1). The magnetic field is directed out of the plane of the figure. The magnetic field has an initial value of 7.88 T and is decreasing at a rate of -0.696 T/s . Is the induced current in the loop clockwise or counterclockwise? What is the rate at which electrical energy is being dissipated by the resistance of the loop? Please explain all stepsarrow_forwardA 0.333 m long metal bar is pulled to the left by an applied force F and moves to the left at a constant speed of 5.90 m/s. The bar rides on parallel metal rails connected through a 46.7 Ω resistor, as shown in (Figure 1), so the apparatus makes a complete circuit. You can ignore the resistance of the bar and rails. The circuit is in a uniform 0.625 T magnetic field that is directed out of the plane of the figure. Is the induced current in the circuit clockwise or counterclockwise? What is the rate at which the applied force is doing work on the bar? Please explain all stepsarrow_forward
- A 0.850-m-long metal bar is pulled to the right at a steady 5.0 m/s perpendicular to a uniform, 0.650-T magnetic field. The bar rides on parallel metal rails connected through a 25-Ω, resistor (Figure 1), so the apparatus makes a complete circuit. Ignore the resistance of the bar and the rails. Calculate the magnitude of the emf induced in the circuit. Find the direction of the current induced in the circuit. Calculate the current through the resistor.arrow_forwardIn the figure, a conducting rod with length L = 29.0 cm moves in a magnetic field B→ of magnitude 0.510 T directed into the plane of the figure. The rod moves with speed v = 5.00 m/s in the direction shown. When the charges in the rod are in equilibrium, which point, a or b, has an excess of positive charge and where does the electric field point? What is the magnitude E of the electric field within the rod, the potential difference between the ends of the rod, and the magnitude E of the motional emf induced in the rod? Which point has a higher potential? Please explain all stepsarrow_forwardExamine the data and % error values in Data Table 2 where the mass of the pendulum bob increased but the angular displacement and length of the simple pendulum remained constant. Describe whether or not your data shows that the period of the pendulum depends on the mass of the pendulum bob, to within a reasonable percent error.arrow_forward
- University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice UniversityPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningClassical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage Learning





