Excursions in Mathematics, Loose-Leaf Edition Plus MyLab Math with Pearson eText -- 18 Week Access Card Package

9th Edition

ISBN: 9780136208754

Author: Tannenbaum, Peter

Publisher: PEARSON

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Textbook Question

Chapter 17, Problem 41E

Exercises 41 through 44 refer to the following: 2500 students take a college entrance exam. The scores on the exam have an approximately normal distribution with mean μ = 52 points and standard deviation σ = 11 points.

a. Estimate the average score on the exam.

b. Estimate the percentage of students scoring 52 points or more.

c. Estimate the percentage of students scoring between 41 and 63 points.

d. Estimate the percentage of students scoring 63 points or more.

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

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Chapter 17, Problem 40E

Chapter 17, Problem 42E

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Chapter 17 Solutions

Excursions in Mathematics, Loose-Leaf Edition Plus MyLab Math with Pearson eText -- 18 Week Access Card Package

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Solution Summary: The author analyzes how a normal distribution divides the data into two identical halves: the average score and the percentage of students scoring between 41 and 63 points.

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