Chapter 17, Problem 3SAQ

Interpretation Introduction

Interpretation: The missing particle in the following nuclear equation is to be determined.

$\text{M}\text{g}\to \text{N}\text{a}+\underset{\_}{}$

Concept Introduction: When atomic number of element decreases by 1, the type of emission is called positron emission. During positron emission, a proton changes into a neutron and emits a positron in the process. Thus, positron emission is a consequence of emission of positron from an unstable nucleus. The mass of positron is same as that of electron, the charge of positron is $1+$. The symbol positron is denoted as:$\text{e}$.