EBK PHYSICS OF EVERYDAY PHENOMENA
8th Edition
ISBN: 8220106637050
Author: Griffith
Publisher: YUZU
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 17, Problem 35CQ
To determine
Whether the objective of a microscope is likely to have a longer focal length than the objective of a telescope.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionChapter 17 Solutions
EBK PHYSICS OF EVERYDAY PHENOMENA
Ch. 17 - Prob. 1CQCh. 17 - Prob. 2CQCh. 17 - Prob. 3CQCh. 17 - Prob. 4CQCh. 17 - If you want to view your full height in a plane...Ch. 17 - Prob. 6CQCh. 17 - Prob. 7CQCh. 17 - Prob. 8CQCh. 17 - Prob. 9CQCh. 17 - Prob. 10CQ
Ch. 17 - Prob. 11CQCh. 17 - Prob. 12CQCh. 17 - Prob. 13CQCh. 17 - Prob. 14CQCh. 17 - Prob. 15CQCh. 17 - Prob. 16CQCh. 17 - Prob. 17CQCh. 17 - Prob. 18CQCh. 17 - Prob. 19CQCh. 17 - Is there any position in which an object could be...Ch. 17 - Prob. 21CQCh. 17 - Prob. 22CQCh. 17 - Prob. 23CQCh. 17 - Prob. 24CQCh. 17 - Prob. 25CQCh. 17 - Prob. 26CQCh. 17 - Prob. 27CQCh. 17 - Prob. 28CQCh. 17 - Prob. 29CQCh. 17 - For a nearsighted person, is the lens of the...Ch. 17 - Prob. 31CQCh. 17 - Prob. 32CQCh. 17 - Prob. 33CQCh. 17 - Prob. 34CQCh. 17 - Prob. 35CQCh. 17 - Prob. 36CQCh. 17 - Prob. 1ECh. 17 - Prob. 2ECh. 17 - Prob. 3ECh. 17 - Prob. 4ECh. 17 - Prob. 5ECh. 17 - Prob. 6ECh. 17 - Prob. 7ECh. 17 - Prob. 8ECh. 17 - Prob. 9ECh. 17 - Prob. 10ECh. 17 - Prob. 11ECh. 17 - Prob. 12ECh. 17 - Prob. 13ECh. 17 - Prob. 14ECh. 17 - Prob. 15ECh. 17 - Prob. 16ECh. 17 - Prob. 17ECh. 17 - Prob. 1SPCh. 17 - Prob. 2SPCh. 17 - Prob. 3SPCh. 17 - Prob. 4SPCh. 17 - Prob. 5SP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A group of students is given two converging lenses. Lens A has a focal length of 12.5 cm, and lens B has a focal length of 50.0 cm. The diameter of each lens is 6.50 cm. The students are asked to construct a microscope from these lenses that has the same magnification as the telescope in Problem 80 if possible, and they have this discussion: Avi: These are the same lenses we used to make a telescope. So they wont work as a microscope. Microscopes are for looking at close objects; telescopes are for looking at far objects. Cameron: All you need for a microscope are two converging lenses. I think the difference from a telescope is just that the order of the lenses is switched. A microscope is just a backward telescope. Shannon: I think the order of the lenses doesnt matter because the magnification is inversely proportional to both focal lengths. I think we have to adjust the distance between the lenses. a. What do you think? b. If a microscope can be constructed with these two lenses, describe its design. What is the minimum separation of the lenses? Where must you place the object?arrow_forwardA particular nearsighted patient cant see objects clearly beyond 15.0 cm from their eye. Determine (a) the lens power required to correct the patients vision and (b) the type of lens required (converging or diverging). Neglect the distance between the eye and the corrective lens.arrow_forwardA converging lens has a focal length of 10.0 cm. Locate the object if a real image is located at a distance from the lens of (a) 20.0 cm and (b) 50.0 cm. What If? Redo the calculations if the images are virtual and located at a distance from the lens of (c) 20.0 cm and (d) 50.0 cm.arrow_forward
- Two thin lenses of focal lengths f1 = 15.0 and f2 = 10.0 cm, respectively, are separated by 35.0 cm along a common axis. The f1 lens is located to the left of the f2 lens. An object is now placed 50.0 cm to the left of the f1 lens, and a final image due to light passing though both lenses forms. By what factor is the final image different in size from the object? (a) 0.600 (b) 1.20 (c) 2.40 (d) 3.60 (e) none of those answersarrow_forwardWhich of the following is true of a concave lens? (7.4) (a) It is a converging lens. (b) It is thicker at the center than at the edge. (c) It is a lens that forms virtual images for Do f. (d) It is a lens that forms real images for Do f.arrow_forwardThe near point of an eye is 75.0 cm. (a) What should be the power of a corrective lens prescribed to enable the eye to see an object clearly at 25.0 cm? (b) If, using the corrective lens, the person can see an object clearly at 26 0 cm but not at 25.0 cm, by how many diopters did the lens grinder miss the prescription?arrow_forward
- Two lenses made of kinds of glass having different indices of refraction n1 and n2 are cemented together to form an optical doublet. Optical doublets are often used to correct chromatic aberrations in optical devices. The first lens of a certain doublet has index of refraction n1, one flat side, and one concave side with a radius of curvature of magnitude R. The second lens has index of refraction n2 and two convex sides with radii of curvature also of magnitude R. Show that the doublet can be modeled as a single thin lens with a focal length described by 1f=2n2n11Rarrow_forwardAu object of height 3.0 cm is placed at 25 cm in front of a diverging lens of focal length 20 cm. Behind the diverging lens, there is a converging lens of focal length 20 cm. The distance between the lenses is 5.0 cm. Fluid the location and size of the final image.arrow_forwardA converging lens made of crown glass has a focal length of 15.0 cm when used in air. If the lens is immersed in water, what is its focal length? (a) negative (b) less than 15.0 cm (c) equal to 15.0 cm (d) greater than 15.0 cm (e) none of those answersarrow_forward
- It has become common to replace the cataract-clouded lens of the eye with an internal lens. This intraocular lens can be chosen so that the person has perfect distant vision. Will the person be able to read without glasses? If the person was nearsighted, is the power of the intraocular lens greater or less than the removed lens?arrow_forwardFor a normal, relaxed eye, a magnifying glass produces an angular magnification of 4.0. What is the largest magnification possible with this magnifying glass?arrow_forwardA lamp of height S cm is placed 40 cm in front of a converging lens of focal length 20 cm. There is a plane mirror 15 cm behind the lens. Where would you find the image when you look in the mirror?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningUniversity Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningAn Introduction to Physical SciencePhysicsISBN:9781305079137Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar TorresPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
An Introduction to Physical Science
Physics
ISBN:9781305079137
Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Convex and Concave Lenses; Author: Manocha Academy;https://www.youtube.com/watch?v=CJ6aB5ULqa0;License: Standard YouTube License, CC-BY