Excursions in Modern Mathematics (9th Edition)
9th Edition
ISBN: 9780134468372
Author: Peter Tannenbaum
Publisher: PEARSON
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Chapter 17, Problem 28E
To determine
To calculate:
The mean
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(c) Because logistic regression predicts probabilities of outcomes, observations used to build a logistic regression model need not be independent.
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Chapter 17 Solutions
Excursions in Modern Mathematics (9th Edition)
Ch. 17 - Consider the normal distribution represented by...Ch. 17 - Consider the normal distribution represented by...Ch. 17 - Consider the normal distribution represented by...Ch. 17 - Consider the normal distribution represented by...Ch. 17 - Consider a normal distribution with mean =81.2lb...Ch. 17 - Consider a normal distribution with mean =2354...Ch. 17 - Consider a normal distribution with first quartile...Ch. 17 - Consider a normal distribution with first quartile...Ch. 17 - Estimate the value of the standard deviation ...Ch. 17 - Estimate the value of the standard deviation ...
Ch. 17 - Explain why a distribution with median M=82, mean...Ch. 17 - Explain why a distribution with median M=453, mean...Ch. 17 - Explain why a distribution with =195, Q1=180 and...Ch. 17 - Explain why a distribution with M==47, Q1=35 and...Ch. 17 - A normal distribution has mean =30kg and standard...Ch. 17 - Prob. 16ECh. 17 - Prob. 17ECh. 17 - Prob. 18ECh. 17 - Prob. 19ECh. 17 - In a normal distribution with mean =83.2 and...Ch. 17 - Prob. 21ECh. 17 - Prob. 22ECh. 17 - Prob. 23ECh. 17 - Prob. 24ECh. 17 - Prob. 25ECh. 17 - In a normal distribution with standard deviation...Ch. 17 - Prob. 27ECh. 17 - Prob. 28ECh. 17 - Consider the normal distribution represented by...Ch. 17 - Consider the normal distribution represented by...Ch. 17 - Consider the normal distribution defined by Fig....Ch. 17 - Consider the normal distribution defined by Fig....Ch. 17 - A normal distribution has mean =71.5in., and the...Ch. 17 - A normal distribution has standard deviation =12.3...Ch. 17 - Prob. 35ECh. 17 - Prob. 36ECh. 17 - Prob. 37ECh. 17 - A normal distribution has mean =500 and standard...Ch. 17 - In a normal distribution, what percent of the data...Ch. 17 - In a normal distribution, what percent of the data...Ch. 17 - Exercises 41 through 44 refer to the following:...Ch. 17 - Exercises 41 through 44 refer to the following:...Ch. 17 - Exercises 41 through 44 refer to the following:...Ch. 17 - Exercises 41 through 44 refer to the following:...Ch. 17 - Exercises 45 through 48 refer to the following: As...Ch. 17 - Exercises 45 through 48 refer to the following: As...Ch. 17 - Exercises 45 through 48 refer to the following: As...Ch. 17 - Exercises 45 through 48 refer to the following: As...Ch. 17 - Exercises 49 through 52 refer to the following:...Ch. 17 - Exercises 49 through 52 refer to the following:...Ch. 17 - Exercises 49 through 52 refer to the following:...Ch. 17 - Exercises 49 through 52 refer to the following:...Ch. 17 - Exercises 53 through 56 refer to the distribution...Ch. 17 - Exercises 53 through 56 refer to the distribution...Ch. 17 - Exercises 53 through 56 refer to the distribution...Ch. 17 - Exercises 53 through 56 refer to the distribution...Ch. 17 - An honest coin is tossed n=3600 times. Let the...Ch. 17 - Prob. 58ECh. 17 - Suppose that a random sample of n=7056 adults is...Ch. 17 - An honest die is rolled. If the roll comes out...Ch. 17 - A dishonest coin with probability of heads p=0.4...Ch. 17 - A dishonest coin with probability of heads p=0.75...Ch. 17 - Prob. 63ECh. 17 - Suppose that 1 out of every 10 plasma televisions...Ch. 17 - Prob. 65ECh. 17 - Prob. 66ECh. 17 - Percentiles. The pth percentile of a sorted data...Ch. 17 - Prob. 68ECh. 17 - Prob. 69ECh. 17 - Percentiles. The pth percentile of a sorted data...Ch. 17 - Prob. 71ECh. 17 - Percentiles. The pth percentile of a sorted data...Ch. 17 - Prob. 73ECh. 17 - Prob. 74ECh. 17 - Prob. 75ECh. 17 - Prob. 76ECh. 17 - A dishonest coin with probability of heads p=0.1...Ch. 17 - Prob. 78ECh. 17 - In American roulette there are 18 red numbers, 18...Ch. 17 - After polling a random sample of 800 voters during...
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- Business discussarrow_forwardSpam filters are built on principles similar to those used in logistic regression. We fit a probability that each message is spam or not spam. We have several variables for each email. Here are a few: to_multiple=1 if there are multiple recipients, winner=1 if the word 'winner' appears in the subject line, format=1 if the email is poorly formatted, re_subj=1 if "re" appears in the subject line. A logistic model was fit to a dataset with the following output: Estimate SE Z Pr(>|Z|) (Intercept) -0.8161 0.086 -9.4895 0 to_multiple -2.5651 0.3052 -8.4047 0 winner 1.5801 0.3156 5.0067 0 format -0.1528 0.1136 -1.3451 0.1786 re_subj -2.8401 0.363 -7.824 0 (a) Write down the model using the coefficients from the model fit.log_odds(spam) = -0.8161 + -2.5651 + to_multiple + 1.5801 winner + -0.1528 format + -2.8401 re_subj(b) Suppose we have an observation where to_multiple=0, winner=1, format=0, and re_subj=0. What is the predicted probability that this message is spam?…arrow_forwardConsider an event X comprised of three outcomes whose probabilities are 9/18, 1/18,and 6/18. Compute the probability of the complement of the event. Question content area bottom Part 1 A.1/2 B.2/18 C.16/18 D.16/3arrow_forward
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