MATERIALS SCI.+ENGR.:INTRO.-NEXTGEN
10th Edition
ISBN: 9781119503941
Author: Callister
Publisher: WILEY
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Chapter 17, Problem 24QAP
To determine
To explain:
Why for a small anode to cathode area ratio, the corrosion rate will be higher than for a large ratio.
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Fundimentals of Energy Systems Q8
Two wattmeters are used to measure power in a three
phase, three-wire network. Show by means of connection
and complexor (phasor) diagrams that the sum of the
wattmeter readings will measure the total active power.
Two such wattmeters read 120 W and 50 W when
connected to measure the active power taken by a balanced three-phase load. Find the power factor of the load.
If one wattmeter tends to read in the reverse direction,
explain what changes may have occurred in the circuit
ANS:
0.815
Fundimentals of Energy Systems Q7
Chapter 17 Solutions
MATERIALS SCI.+ENGR.:INTRO.-NEXTGEN
Ch. 17 - Prob. 1QAPCh. 17 - Prob. 2QAPCh. 17 - Prob. 3QAPCh. 17 - Prob. 4QAPCh. 17 - Prob. 10QAPCh. 17 - Prob. 13QAPCh. 17 - Prob. 15QAPCh. 17 - Prob. 16QAPCh. 17 - Prob. 19QAPCh. 17 - Prob. 20QAP
Ch. 17 - Prob. 21QAPCh. 17 - Prob. 22QAPCh. 17 - Prob. 23QAPCh. 17 - Prob. 24QAPCh. 17 - Prob. 25QAPCh. 17 - Prob. 26QAPCh. 17 - Prob. 27QAPCh. 17 - Prob. 29QAPCh. 17 - Prob. 31QAPCh. 17 - Prob. 32QAPCh. 17 - Prob. 1DPCh. 17 - Prob. 2DPCh. 17 - Prob. 3DPCh. 17 - Prob. 1FEQPCh. 17 - Prob. 2FEQPCh. 17 - Prob. 3FEQP
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- Problem #1 (Beam optimization). Calculate the length "a" of AB such that the bending moment diagram is optimized (the absolute value of the max and the min is at its lowest). Then draw the shear and moment diagram for the optimized length. Optimize the length to the nearest 0.1 m. You can use RISA 2D as a tool to find the optimized length, however you need to solve for the support reactions at A, B and C by hand and draw the shear and moment diagram by hand. w=20 kN/m A + + a 12 m B Carrow_forwardcan u solve this questionarrow_forward1. Unsigned Integers If we have an n-digit unsigned numeral dn-1d n-2...do in radix (or base) r, then the value of that numeral is n−1 r² di Σi=0 which is basically saying that instead of a 10's or 100's place we have an r's or r²'s place. For binary, decimal, and hex r equals 2, 10, and 16, respectively. Just a reminder that in order to write down a large number, we typically use the IEC or SI prefixing system: IEC: Ki = 210, Mi = 220, Gi = 230, Ti = 240, Pi = 250, Ei = 260, Zi = 270, Yi = 280; SI: K=103, M = 106, G = 109, T = 10¹², P = 1015, E = 10¹8, Z = 1021, Y = 1024. 1.1 Conversions a. (15 pts) Write the following using IEC prefixes: 213, 223, 251, 272, 226, 244 21323 Ki8 Ki 223 23 Mi 8 Mi b. (15 pts) Write the following using SI prefixes: 107, 10¹7, 10¹¹, 1022, 1026, 1015 107 10¹ M = 10 M = 1017102 P = 100 P c. (10 pts) Write the following with powers of 10: 7 K, 100 E, 21 G 7 K = 7*10³arrow_forward
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