CALCULUS:EARLY TRANS.-SAPLINGPLUS
CALCULUS:EARLY TRANS.-SAPLINGPLUS
4th Edition
ISBN: 9781319279813
Author: Rogawski
Publisher: MAC HIGHER
Question
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Chapter 17, Problem 1CRE
To determine

To evaluate:

The line integral Cf.dr directly as well as using Green’s theorem.

Expert Solution & Answer
Check Mark

Answer to Problem 1CRE

Solution:

The given linear integral has been evaluated to zero.

Cf.dr=0

Explanation of Solution

Given:

A multivariable vector field f(x,y)=x+y2,x2y. A unit circle C oriented counter-clockwise.

Formula used:

Cf.dr=abf(r(t))r'(t)dt

As per Green’s Theorem:

Cf.dr=CPdx+Qdy=D(δQδxδPδy)dA

Calculation:

Using line integral, we can represent the circle C as:

C:x2+y2=1x=cos(t),y=sin(t);0t2πC:r(t)=cos(t),sin(t);0t2π

We have,

r(t)=cost,sintr'(t)=sint,cost

Thus, the line integral becomes:

Cf.dr=abf(r(t))r'(t)dtCf.dr=02πcost+sin2t,cos2tsintsint,costdtCf.dr=02π(sintcostsin3t+cos3tsintcost)dtCf.dr=02π(sin3t+cos3t2sintcost)dtCf.dr=0

Now, we have to evaluate the given line integral using Green’s Theorem. Using Green’s theorem, we can write:

Cf.dr=CPdx+QdyCf.dr=D(δQδxδPδy)dACf.dr=D(δδx(x2y)δδy(x+y2))dACf.dr=D(2x2y)dACf.dr=02π012(rcostrsint)rdrdtCf.dr=202π01r2(costsint)drdtCf.dr=202π(costsint)dt01r2drCf.dr=2(0)(13)=0Cf.dr=0

Conclusion:

The given integral was evaluated both using direct linear integrals as well as using Green’s Theorem.

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Chapter 17 Solutions

CALCULUS:EARLY TRANS.-SAPLINGPLUS

Ch. 17.1 - Prob. 6ECh. 17.1 - Prob. 7ECh. 17.1 - Prob. 8ECh. 17.1 - Prob. 9ECh. 17.1 - Prob. 10ECh. 17.1 - Prob. 11ECh. 17.1 - Prob. 12ECh. 17.1 - Prob. 13ECh. 17.1 - Prob. 14ECh. 17.1 - Prob. 15ECh. 17.1 - Prob. 16ECh. 17.1 - Prob. 17ECh. 17.1 - Prob. 18ECh. 17.1 - Prob. 19ECh. 17.1 - Prob. 20ECh. 17.1 - Prob. 21ECh. 17.1 - Prob. 22ECh. 17.1 - Prob. 23ECh. 17.1 - Prob. 24ECh. 17.1 - Prob. 25ECh. 17.1 - Prob. 26ECh. 17.1 - Prob. 27ECh. 17.1 - Prob. 28ECh. 17.1 - Prob. 29ECh. 17.1 - Prob. 30ECh. 17.1 - Prob. 31ECh. 17.1 - Prob. 32ECh. 17.1 - Prob. 33ECh. 17.1 - Prob. 34ECh. 17.1 - Prob. 35ECh. 17.1 - Prob. 36ECh. 17.1 - Prob. 37ECh. 17.1 - Prob. 38ECh. 17.1 - Prob. 39ECh. 17.1 - Prob. 40ECh. 17.1 - Prob. 41ECh. 17.1 - Prob. 42ECh. 17.1 - Prob. 43ECh. 17.1 - Prob. 44ECh. 17.1 - Prob. 45ECh. 17.1 - Prob. 46ECh. 17.1 - Prob. 47ECh. 17.1 - Prob. 48ECh. 17.1 - Prob. 49ECh. 17.1 - Prob. 50ECh. 17.1 - Prob. 51ECh. 17.2 - Prob. 1PQCh. 17.2 - Prob. 2PQCh. 17.2 - Prob. 3PQCh. 17.2 - Prob. 4PQCh. 17.2 - Prob. 5PQCh. 17.2 - Prob. 1ECh. 17.2 - Prob. 2ECh. 17.2 - Prob. 3ECh. 17.2 - Prob. 4ECh. 17.2 - Prob. 5ECh. 17.2 - Prob. 6ECh. 17.2 - Prob. 7ECh. 17.2 - Prob. 8ECh. 17.2 - Prob. 9ECh. 17.2 - Prob. 10ECh. 17.2 - Prob. 11ECh. 17.2 - Prob. 12ECh. 17.2 - Prob. 13ECh. 17.2 - Prob. 14ECh. 17.2 - Prob. 15ECh. 17.2 - Prob. 16ECh. 17.2 - Prob. 17ECh. 17.2 - Prob. 18ECh. 17.2 - Prob. 19ECh. 17.2 - Prob. 20ECh. 17.2 - Prob. 21ECh. 17.2 - Prob. 22ECh. 17.2 - Prob. 23ECh. 17.2 - Prob. 24ECh. 17.2 - Prob. 25ECh. 17.2 - Prob. 26ECh. 17.2 - Prob. 27ECh. 17.2 - Prob. 28ECh. 17.2 - Prob. 29ECh. 17.2 - Prob. 30ECh. 17.2 - Prob. 31ECh. 17.2 - Prob. 32ECh. 17.2 - Prob. 33ECh. 17.2 - Prob. 34ECh. 17.2 - Prob. 35ECh. 17.2 - Prob. 36ECh. 17.2 - Prob. 37ECh. 17.2 - Prob. 38ECh. 17.3 - Prob. 1PQCh. 17.3 - Prob. 2PQCh. 17.3 - Prob. 3PQCh. 17.3 - Prob. 4PQCh. 17.3 - Prob. 5PQCh. 17.3 - Prob. 1ECh. 17.3 - Prob. 2ECh. 17.3 - Prob. 3ECh. 17.3 - Prob. 4ECh. 17.3 - Prob. 5ECh. 17.3 - Prob. 6ECh. 17.3 - Prob. 7ECh. 17.3 - Prob. 8ECh. 17.3 - Prob. 9ECh. 17.3 - Prob. 10ECh. 17.3 - Prob. 11ECh. 17.3 - Prob. 12ECh. 17.3 - Prob. 13ECh. 17.3 - Prob. 14ECh. 17.3 - Prob. 15ECh. 17.3 - Prob. 16ECh. 17.3 - Prob. 17ECh. 17.3 - Prob. 18ECh. 17.3 - Prob. 19ECh. 17.3 - Prob. 20ECh. 17.3 - Prob. 21ECh. 17.3 - Prob. 22ECh. 17.3 - Prob. 23ECh. 17.3 - Prob. 24ECh. 17.3 - Prob. 25ECh. 17.3 - Prob. 26ECh. 17.3 - Prob. 27ECh. 17.3 - Prob. 28ECh. 17.3 - Prob. 29ECh. 17.3 - Prob. 30ECh. 17.3 - Prob. 31ECh. 17.3 - Prob. 32ECh. 17.3 - Prob. 33ECh. 17.3 - Prob. 34ECh. 17.3 - Prob. 35ECh. 17.3 - Prob. 36ECh. 17.3 - Prob. 37ECh. 17.3 - Prob. 38ECh. 17.3 - Prob. 39ECh. 17.3 - Prob. 40ECh. 17.3 - Prob. 41ECh. 17.3 - Prob. 42ECh. 17.3 - Prob. 43ECh. 17.3 - Prob. 44ECh. 17 - Prob. 1CRECh. 17 - Prob. 2CRECh. 17 - Prob. 3CRECh. 17 - Prob. 4CRECh. 17 - Prob. 5CRECh. 17 - Prob. 6CRECh. 17 - Prob. 7CRECh. 17 - Prob. 8CRECh. 17 - Prob. 9CRECh. 17 - Prob. 10CRECh. 17 - Prob. 11CRECh. 17 - Prob. 12CRECh. 17 - Prob. 13CRECh. 17 - Prob. 14CRECh. 17 - Prob. 15CRECh. 17 - Prob. 16CRECh. 17 - Prob. 17CRECh. 17 - Prob. 18CRECh. 17 - Prob. 19CRECh. 17 - Prob. 20CRECh. 17 - Prob. 21CRECh. 17 - Prob. 22CRECh. 17 - Prob. 23CRECh. 17 - Prob. 24CRECh. 17 - Prob. 25CRECh. 17 - Prob. 26CRECh. 17 - Prob. 27CRECh. 17 - Prob. 28CRECh. 17 - Prob. 29CRECh. 17 - Prob. 30CRECh. 17 - Prob. 31CRECh. 17 - Prob. 32CRECh. 17 - Prob. 33CRECh. 17 - Prob. 34CRECh. 17 - Prob. 35CRECh. 17 - Prob. 36CRECh. 17 - Prob. 37CRECh. 17 - Prob. 38CRECh. 17 - Prob. 39CRECh. 17 - Prob. 40CRECh. 17 - Prob. 41CRE
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