(a) Explanation Section 1: To determine: The specific heat of copper can. Answer: The specific heat of copper can is ( 173.9 J / K ) T . Explanation: Given Info: The mass of copper calorimeter can is 0.446 kg , the specific heat of copper is 390 J / kg K , the initial temperature of the can is 100 °C Formula to calculate the specific heat of the copper can is, Q can = m c ( T − T 1 ) Q can is the specific heat of the copper can. m is the mass of copper can. c is the specific heat of copper. T is the final temperature of system T 1 is the initial temperature of system Substitute 0.446 kg for m , 390 J / kg ° C for c and 0 ° C for T 1 to find Q can . Q can = ( 0.446 kg ) ( 390 J/kg .°C ) ( T 2 − 0 ° C ) = ( 173.9 J / K ) T Thus, the specific heat of copper can is ( 173.9 J / K ) T . Section 2: To determine: The specific heat of ice. Answer: The specific heat of ice is 3.173 × 10 4 J + ( 398.0 J / K ) T . Explanation: Given Info: The mass of ice is 0.0950 kg , the specific heat of water is 4190 J / kg ° C , the initial temperature of the can is 0 °C and the latent heat of fusion is 334 × 10 3 J / kg . Formula to calculate the specific heat of ice is. Q ice = m L f + m c ( T − T 1 ) Q ice Q isthe specific heat of the ice. m is the mass of ice. c is the specific heat of water. T is the final temperature of system. T 1 is the initial temperature of ice. L f is the latent heat of fusion of water. Substitute 4190 J / kg ° C . for c , 0 ° C for T 1 , 0.0950 kg for m and 3.34 × 10 5 J / kg for L f to find Q ice . Q ice = ( 0.0950 kg ) ( 334 × 10 3 ) + ( 0.0950 kg ) ( 4190 J / kg °C ) ( T − 0 ° C ) = 3.173 × 10 4 J+ ( 398.0 J / K ) T Thus, The specific heat of ice is 3.173 × 10 4 J + ( 398.0 J / K ) T . Section 3: To determine: The specific heat of steam. Answer: The specific heat of ice is − 9.362 × 10 4 J + ( 146.6 J / K ) T . Explanation: Given Info: The mass of steamis 0.0350 kg , the specific heat of water is 4190 J / kg ° C , the initial temperature of the steam is 100 °C and the latent heat of steam is 2256 × 10 3 J / kg Formula to calculate the specific heat of steam is, Q steam = − m L v + m c ( T − T 1 ) Q steam isthe specific heat of the ice (b) To determine The mass of the content of the system.

14th Edition

ISBN: 9780133969290

Author: Hugh D. Young, Roger A. Freedman

Publisher: PEARSON

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Question

Chapter 17, Problem 17.95P

(a)

To determine

The final temperature of the calorimeter can.

(b)

To determine

The mass of the content of the system.

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Chapter 17, Problem 17.94P

Chapter 17, Problem 17.96P

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Chapter 17 Solutions

University Physics (14th Edition)

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