Chapter 17, Problem 17.89UTC

Interpretation Introduction

To determine: The bases in the parent and new strands

Answer to Problem 17.89UTC

Solution:

Explanation of Solution

As we know, in DNA, Guanine-Cytosine (G-C) and Adenine-Thymine (A-T) pair together and form hydrogen bonds between the two bases.

Conclusion

Based on the above fact, we can say that missing bases in the parent and new strands are

AGGTCGCCT

TCCAGCGGA

Interpretation Introduction

To determine: The m-RNA sequence using the new strand as template

Answer to Problem 17.89UTC

Solution:

Explanation of Solution

In RNA, the base present is Uracil instead of Thymine, which has a very alike structure to Thymine. As a result, the pairing of Adenine with Uracil (A-U) takes place by the same interaction that is hydrogen bonding as in the A-T base pair.

Conclusion

Based on the above fact we can say that the m-RNA sequence would be AGGUCGCCU

Interpretation Introduction

To determine: The 3 letters symbol for the amino acids that would go into the peptide from the m-RNA in part b

Answer to Problem 17.89UTC

Solution: Arg-Ser-Pro

Explanation of Solution

A triplet codon is the consecutive three bases on RNA forming a genetic code. The representation of each triplet codon is an amino acid. The sequence of bases on RNA could be seen as sequence of triplet codons. Thus, an amino acid sequence can be determined by the sequence of three letter codons on m-RNA. Each three letter codons either codes for a specific amino acid or codes for a stop signal. In this m-RNA, AGG codes for arginine, UCG codes for serine and CCU codes for proline. So, the amino acid sequence would be:

Arg-Ser-Pro

Conclusion

Based on the explanation as provided, we can say that amino acid sequence would be Arg-Ser-Pro.