ALEKS 360; 18WKS F/ GEN. CHEMISTRY >I<
13th Edition
ISBN: 9781264070077
Author: Chang
Publisher: INTER MCG
expand_more
expand_more
format_list_bulleted
Textbook Question
Chapter 17, Problem 17.32QP
Calculate ΔG° for the process
Is the formation of graphite from diamond favored at 25°C? If so, why is it that diamonds do not become graphite on standing?
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionChapter 17 Solutions
ALEKS 360; 18WKS F/ GEN. CHEMISTRY >I<
Ch. 17.3 - How does the entropy of a system change for each...Ch. 17.3 - For which of the following physical changes is S...Ch. 17.3 - Determine if the sign for S is positive or...Ch. 17.4 - Prob. 2PECh. 17.4 - Prob. 3PECh. 17.4 - Calculate the standard entropy change for the...Ch. 17.4 - Consider the gas-phase reaction of A2 (blue) and...Ch. 17.5 - Prob. 4PECh. 17.5 - The molar heats of fusion and vaporization of...Ch. 17.5 - Under what circumstances will an endothermic...
Ch. 17.5 - Prob. 2RCFCh. 17.5 - Prob. 3RCFCh. 17.5 - Prob. 4RCFCh. 17.6 - Calculate the equilibrium constant (KP) for the...Ch. 17.6 - Prob. 7PECh. 17.6 - Prob. 8PECh. 17.6 - A reaction has a positive H and a negative S.Is...Ch. 17.6 - For the reaction A(g)+B(g)C(g) G = 33.3 kJ/mol at...Ch. 17.6 - For the reaction C(aq)A(aq)+B(aq) G = 1.95 kJ/mol...Ch. 17 - Explain what is meant by a spontaneous process....Ch. 17 - State which of the following processes are...Ch. 17 - Prob. 17.3QPCh. 17 - Define entropy. What are the units of entropy?Ch. 17 - How does the entropy of a system change for each...Ch. 17 - State the second law of thermodynamics in words...Ch. 17 - State the third law of thermodynamics and explain...Ch. 17 - For each pair of substances listed here, choose...Ch. 17 - Arrange the following substances (1 mole each) in...Ch. 17 - Using the data in Appendix 2, calculate the...Ch. 17 - Using the data in Appendix 2, calculate the...Ch. 17 - Without consulting Appendix 2, predict whether the...Ch. 17 - Prob. 17.14QPCh. 17 - Define free energy. What are its units?Ch. 17 - Why is it more convenient to predict the direction...Ch. 17 - Calculate G for the following reactions at 25C:...Ch. 17 - Calculate G for the following reactions at 25C:...Ch. 17 - From the values of H and S, predict which of the...Ch. 17 - Find the temperatures at which reactions with the...Ch. 17 - Explain the difference between G and G.Ch. 17 - Explain why Equation (17.14). is of great...Ch. 17 - Calculate KP for the following reaction at 25C:...Ch. 17 - For the autoionization of water at 25C,...Ch. 17 - Consider the following reaction at 25C:...Ch. 17 - Calculate G and KP for the following equilibrium...Ch. 17 - (a) Calculate G and KP for the following...Ch. 17 - The equilibrium constant (KP) for the reaction...Ch. 17 - Consider the decomposition of calcium carbonate:...Ch. 17 - The equilibrium constant KP for the reaction...Ch. 17 - At 25C, G for the process H2O(l)H2O(g) is 8.6...Ch. 17 - Calculate G for the process C(diamond)C(graphite)...Ch. 17 - What is a coupled reaction? What is its importance...Ch. 17 - What is the role of ATP in biological reactions?Ch. 17 - Referring to the metabolic process involving...Ch. 17 - In the metabolism of glucose, the first step is...Ch. 17 - Explain the following nursery rhyme in terms of...Ch. 17 - Calculate G for the reaction H2O(l)H+(aq)+OH(aq)...Ch. 17 - Calculate the Ssoln for the following processes:...Ch. 17 - The following reaction is spontaneous at a certain...Ch. 17 - Which of the following thermodynamic functions are...Ch. 17 - A student placed 1 g of each of three compounds A,...Ch. 17 - Use the data in Appendix 2 to calculate the...Ch. 17 - Predict the signs of H, S, and G of the system for...Ch. 17 - Prob. 17.45QPCh. 17 - Ammonium nitrate (NH4NO3) dissolves spontaneously...Ch. 17 - Calculate the equilibrium pressure of CO2 due to...Ch. 17 - Prob. 17.48QPCh. 17 - Prob. 17.49QPCh. 17 - Carbon monoxide (CO) and nitric oxide (NO) are...Ch. 17 - Prob. 17.51QPCh. 17 - Use the thermodynamic data in Appendix 2 to...Ch. 17 - Consider the reaction A B + C at 298 K. Given...Ch. 17 - The Ksp of AgCl is given in Table 16.2. What is...Ch. 17 - Prob. 17.55QPCh. 17 - Water gas, a mixture of H2 and CO, is a fuel made...Ch. 17 - Consider the following Brnstead acid-base reaction...Ch. 17 - Crystallization of sodium acetate from a...Ch. 17 - Prob. 17.59QPCh. 17 - A certain reaction is spontaneous at 72C. If the...Ch. 17 - Predict whether the entropy change is positive or...Ch. 17 - 17.62The reaction NH3(g)+HCl(g)NH4Cl(s) proceeds...Ch. 17 - Prob. 17.63QPCh. 17 - The molar heat of vaporization of ethanol is 39.3...Ch. 17 - Prob. 17.65QPCh. 17 - In the Mond process for the purification of...Ch. 17 - Calculate G and KP for the following processes at...Ch. 17 - Calculate the pressure of O2 (in atm) over a...Ch. 17 - Prob. 17.69QPCh. 17 - Prob. 17.70QPCh. 17 - Consider the reaction N2(g)+O2(g)2NO(g) Given that...Ch. 17 - Prob. 17.72QPCh. 17 - Prob. 17.73QPCh. 17 - Prob. 17.74QPCh. 17 - Prob. 17.75QPCh. 17 - Prob. 17.76QPCh. 17 - Prob. 17.77QPCh. 17 - Prob. 17.78QPCh. 17 - Prob. 17.79QPCh. 17 - Prob. 17.80QPCh. 17 - Prob. 17.81QPCh. 17 - Prob. 17.82QPCh. 17 - Prob. 17.83QPCh. 17 - Prob. 17.84QPCh. 17 - Shown here are the thermodynamic data for ethanol:...Ch. 17 - The reaction shown here is spontaneous at a...Ch. 17 - Consider two carboxylic acids (acids that contain...Ch. 17 - Many hydrocarbons exist as structural isomers,...Ch. 17 - Use the thermodynamic data in Appendix 2 to...Ch. 17 - A rubber band is stretched vertically by attaching...Ch. 17 - One of the steps in the extraction of iron from...Ch. 17 - Derive the equation G=RTln(Q/K) where Q is the...Ch. 17 - The sublimation of carbon dioxide at 78C is...Ch. 17 - Entropy has sometimes been described as times...Ch. 17 - Referring to Figure 17.1, we see that the...Ch. 17 - A student looked up the Gf, Hf, and S values for...Ch. 17 - Consider the following reaction at 298 K:...Ch. 17 - As an approximation, we can assume that proteins...Ch. 17 - Which of the following are not state functions: S,...Ch. 17 - Which of the following is not accompanied by an...Ch. 17 - Hydrogenation reactions (for example, the process...Ch. 17 - Give a detailed example of each of the following,...Ch. 17 - At 0 K, the entropy of carbon monoxide crystal is...Ch. 17 - Comment on the correctness of the analogy...Ch. 17 - The standard enthalpy of formation and the...Ch. 17 - In chemistry, the standard state for as solution...Ch. 17 - The following diagram shows the variation of the...Ch. 17 - Consider the gas-phase reaction between A2 (green)...Ch. 17 - The KP for the reaction N2+3H22NH3 is 2.4 103 at...Ch. 17 - The table shown here lists the ion-product...Ch. 17 - Draw the missing distributions in Figure 17.2....Ch. 17 - The reaction NH3(g)+HCl(g)NH4Cl(s) is spontaneous...Ch. 17 - The boiling point of diethyl ether is 34.6C....Ch. 17 - Nicotine is the compound in tobacco responsible...Ch. 17 - Estimate S for the process depicted in Figure...Ch. 17 - At what point in the series HOnH(g) (n = 1, 2, 3,...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- a Calculate K1, at 25C for sulfurous acid: H2SO3(aq)H+(aq)+HSO3(aq) b Which thermodynamic factor is the most significant in accounting for the fact that sulfurous acid is a weak acid? Why?arrow_forwardThe decomposition of diamond to graphite [C(diamond) C(graphite)] is thermodynamically favored, but occurs slowly at room temperature. a. Use fG values from Appendix L to calculate rG and Keq for the reaction under standard conditions and 298.15 K. b. Use fH and S values from Appendix L to estimate rG and Keq for the reaction at 1000 K. Assume that enthalpy and entropy values are valid at these temperatures. Does heating shift the equilibrium toward the formation of diamond or graphite? c. Why is the formation of diamond favored at high pressures? d. The phase diagram shows that diamond is thermodynamically favored over graphite at 20,000 atmospheres pressure (about 2 GPa) at room temperature. Why is this conversion actually done at much higher temperatures and pressures?arrow_forwardElemental boron, in the form of thin fibers, can be made by reducing a boron halide with H2. BCl3(g) + 32 H2(g) B(s) + 3 HCl(g) Calculate rH, rS, and rG at 25 C for this reaction. Is the reaction predicted to be product-favored at equilibrium at 25 C? If so, is it enthalpy- or entropy-driven? [S for B(s) is 5.86 J/K mol.]arrow_forward
- Elemental boron, in the form of thin fibers, can be made by reducing a boron halide with H2. BCl3(g) + 3/2 H2(g) B(s) + 3HCl(g) Calculate H, S, and G at 25 C for this reaction. Is the reaction predicted to be product favored at equilibrium at 25 C? If so, is it enthalpy driven or entropy driven?arrow_forwardChemists and engineers who design nuclear power plants have to worry about high-temperature reactions because it is possible for water to decompose. (a) Under what conditions does this reaction occur spontaneously? 2H2O(g) 2H2(g) + O2(g) (b) Under conditions where the decomposition of water is spontaneous, do nuclear engineers have to worry about an oxygen/hydrogen explosion? Justify your answer.arrow_forwardConsider the decomposition of red mercury(II) oxide under standard state conditions.. 2HgO(s,red)2Hg(l)+O2(g) (a) Is the decomposition spontaneous under standard state conditions? (b) Above what temperature does the reaction become spontaneous?arrow_forward
- Consider the reaction of 2 mol H2(g) at 25C and 1 atm with 1 mol O2(g) at the same temperature and pressure to produce liquid water at these conditions. If this reaction is run in a controlled way to generate work, what is the maximum useful work that can be obtained? How much entropy is produced in this case?arrow_forwardBenzene can be prepared from acetylene. 3C2H2(g)C6H6(g). Determine the equilibrium constant at 25 C and at 850 C. Is the reaction spontaneous at either of these temperatures? Why is all acetylene not found as benzene?arrow_forwardThe Ostwald process for the commercial production of nitric acid involves three steps: 4NH3(g)+5O2(g)825CPt4NO(g)+6H2O(g)2NO(g)+O2(g)2NO2(g)3NO2(g)+H2O(l)2HNO3(l)+NO(g) a. Calculate H, S,G and K (at 298 K) for each of the three steps in the Ostwald process (see Appendix 4). b. Calculate the equilibrium constant for the first step at 825C, assuming H and S do not depend on temperature. c. Is there a thermodynamic reason for the high temperature in the first step, assuming standard conditions?arrow_forward
- Use the data in Appendix J to calculate rG andKPat 25 C for the reaction 2HBr(g)+Cl2(g)2HCl(g)+Br2() Comment on the connection between the sign of rG and the magnitude ofKP.arrow_forwardWhat is the sign of the standard Gibbs free-energy change at low temperatures and at high temperatures for the explosive decomposition of TNT? Use your knowledge of TNT and the chemical equation, particularly the phases, to answer this question. (Thermodynamic data for TNT are not in Appendix G.) 2C7H5N3O6(s) 3N2(g) + 5H2O() + 7C(s) + 7CO(g)arrow_forwardImpure nickel, refined by smelting sulfide ores in a blast furnace, can be converted into metal from 99.90% to 99.99% purity by the Mond process. The primary reaction involved in the Mond process is Ni(s)+4CO(g)Ni(CO)4(g) a. Without referring to Appendix 4, predict the sign of S for the above reaction. Explain. b. The spontaneity of the above reaction is temperature-dependent. Predict the sign of Ssurr, for this reaction. Explain c. For Ni(CO)4(g), Hfo=607KJ/mol and S = 417 J/K mol at 298 K. Using these values and data in Appendix 4, calculate H and S for the above reaction. d. Calculate the temperature at which G = 0 (K = 1) for the above reaction, assuming that H and S do not depend on temperature. e. The first step of the Mood process involves equilibrating impure nickel with CO(g) and Ni(CO)4(g) at about 50C. The purpose of this step is to convert as much nickel as possible into the gas phase. Calculate the equilibrium constant for the above reaction at 50.C. f. In the second step of the Mood process, the gaseous Ni(CO)4 is isolated and heated to 227C. The purpose of this step is to deposit as much nickel as possible as pure solid (the reverse of the preceding reaction). Calculate the equilibrium constant for the preceding reaction at 227C. g. Why is temperature increased for the second step of the Mood process? h. The Mond process relies on the volatility of Ni(CO)4 for its success. Only pressures and temperatures at which Ni(CO)4 is a gas are useful. A recently developed variation of the Mood process carries out the first step at higher pressures and a temperature of l52C. Estimate the maximum pressure of Ni(CO)4(g) that can be attained before the gas will liquefy at 152C. The boiling point for Ni(CO)4 is 42C and the enthalpy of vaporization is 29.0 kJ/mol. [Hint: The phase change reaction and the corresponding equilibrium expression are Ni(CO)4(l)Ni(CO)4(g)K=PNi(CO)4 Ni(CO)4(g) will liquefy when the pressure of Ni(CO)4 is greater than the K value.]arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStax
- General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry by OpenStax (2015-05-04)
Chemistry
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:OpenStax
General Chemistry - Standalone book (MindTap Cour...
Chemistry
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
The Laws of Thermodynamics, Entropy, and Gibbs Free Energy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=8N1BxHgsoOw;License: Standard YouTube License, CC-BY