Chapter 17, Problem 17.20QP

Interpretation Introduction

Interpretation:

By using the given concentration of potassium hydroxide and weight of diprotic acid, the molar mass has to be calculated.

Concept introduction:

Molar mass: It is obtained by dividing the mass of substance with the amount of substance and the S.I. unit of molar mass is $\text{kg/mol}$. It is numerically equal to the molecular weight since molecular weight is sum of all individual atom weight present in molecule which is represented in $amu$.

  $\text{Molar}\text{mass}\left(\text{g/mol}\right)=\frac{\text{Given}\text{mass}\text{of}\text{substance}\left(\text{g}\right)}{\text{Moles}\text{of}\text{substance}\left(mol\right)}$

Titration: It is a quantitative analysis method used to express the concentration of acid or base present in the solution.

For an acid-base titration ${\left(Eq\right)}_{acid}={\left(Eq\right)}_{base}$

That is,

  $\begin{array}{l}{N}_{acid}\times V_{acid}=N_{base}\times V_{base}\\ where,\\ N=Normality\\ V=Volume\end{array}$

Molarity: The concentration for solutions is expressed in terms of molarity as follows,

$\text{Molarity = }\frac{\text{No}\text{. of moles of solute}}{\text{Volume of solution in L}}$