Chapter 17, Problem 17.20P

(a)

Interpretation Introduction

Interpretation : The $K_c$ value for the given reaction should be calculated with the help of the given reaction.

  $\begin{array}{l}2H_{2}S\left(g\right)\rightleftharpoons 2H_2\left(g\right)+S_2\left(g\right)K_{\text{c1}}=1.6\times {10}^{-2}\mathrm{...}(1)\\ \raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.S_2\left(g\right)+H_2\left(g\right)\rightleftharpoons H_{2}S\left(g\right)K_c=?\end{array}$

Concept Introduction : When a chemical process reaches equilibrium, the equilibrium constant gives insight into the interaction between the reactants and products. It can be expressed as $K_{\text{c}}$ .

  $A +B \rightleftharpoons C+D$

  $K_{\text{c}}=\frac{[aC][aD]}{[aA][aB]}$

Here, ‘a’ represents the active mass.

(b)

Interpretation Introduction

Interpretation : The $K_c$ value for the given reaction should be calculated with the help of the given reaction:

  $\begin{array}{l}2H_{2}S\left(g\right)\rightleftharpoons 2H_2\left(g\right)+S_2\left(g\right)K_c=1.6\times {10}^{-2}\\ 5H_{2}S\left(g\right)\rightleftharpoons 5H_2\left(g\right)+\frac{5}{2}{S}_2\left(g\right)K_c=?\end{array}$

Concept Introduction : When a chemical process reaches equilibrium, the equilibrium constant gives insight on the interaction between the reactants and products. It can be expressed as $K_{\text{c}}$ .

  $A +B \rightleftharpoons C+D$

  $K_{\text{c}}=\frac{[aC][aD]}{[aA][aB]}$

Here, ‘a’ represents the active mass.