Engineering Your Future
Engineering Your Future
9th Edition
ISBN: 9780190279264
Author: William C. Oakes, Les L. Leone
Publisher: Oxford University Press, USA
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Chapter 17, Problem 17.10EAA
To determine

Determine what moment M exists at support A.

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I need help with a MATLAB code. This code just keeps running and does not give me any plots. I even reduced the tolerance from 1e-9 to 1e-6. Can you help me fix this? Please make sure your solution runs. % Initial Conditions rev = 0:0.001:2;   g1 = deg2rad(1); g2 = deg2rad(3); g3 = deg2rad(6); g4 = deg2rad(30); g0 = deg2rad(0);   Z0 = 0; w0 = [0; Z0*cos(g0); -Z0*sin(g0)];   Z1 = 5; w1 = [0; Z1*cos(g1); -Z1*sin(g1)];   Z2 = 11; w2 = [0; Z2*cos(g2); -Z2*sin(g2)];   [v3, psi3, eta3] = Nut_angle(Z2, g2, w2);   plot(v3, psi3)     function dwedt = K_DDE(~, w_en)   % Extracting the initial condtions to a variable % Extracting the initial condtions to a variable w = w_en(1:3); e = w_en(4:7); Z = w_en(8);     I = 0.060214; J = 0.015707; x = (J/I) - 1; y = Z - 1; s = Z;   % Kinematic Differential Equations dedt = zeros(4,1); dedt(1) = pi*(e(3)*(s-w(2)-1) + e(2)*w(3) + e(4)*w(1)); dedt(2) = pi*(e(4)*(w(2)-1-s) + e(3)*w(1) - e(1)*w(3)); dedt(3) = pi*(-e(1)*(s-w(2)-1) - e(2)*w(1) + e(4)*w(3));…
alpha 1 is not zero alpha 1 can equal alpha 2 use velocity triangle to solve for alpha 1   USE MATLAB ONLY provide typed code   solve for velocity triangle and dont provide copied answer  Turbomachienery .   GIven:  vx = 185 m/s, flow angle = 60 degrees, (leaving a stator in axial flow)  R = 0.5, U = 150 m/s, b2 = -a3, a2 = -b3   Find: velocity triangle , a. magnitude of abs vel leaving rotor (m/s) b. flow absolute angles (a1, a2, a3) 3. flow rel angles (b2, b3) d. specific work done e. use code to draw vel. diagram     Use this code for plot      % plots Velocity Tri. in Ch4 function plotveltri(al1,al2,al3,b2,b3)   S1L = [0 1]; V1x = [0 0]; V1s = [0 1*tand(al3)];   S2L = [2 3]; V2x = [0 0]; V2s = [0 1*tand(al2)]; W2s = [0 1*tand(b2)];   U2x = [3 3]; U2y = [1*tand(b2) 1*tand(al2)];   S3L = [4 5]; V3x = [0 0]; V3r = [0 1*tand(al3)]; W3r = [0 1*tand(b3)];   U3x = [5 5]; U3y = [1*tand(b3) 1*tand(al3)];   plot(S1L,V1x,'k',S1L,V1s,'r',... S2L,V2x,'k',S2L,V2s,'r',S2L,W2s,'b',U2x,U2y,'g',...…
3. Find a basis of eigenvectors and diagonalize. 4 0 -19 7 a. b. 1-42 16 12-20 [21-61

Chapter 17 Solutions

Engineering Your Future

Ch. 17 - Prob. 17.11EAACh. 17 - Prob. 17.12EAACh. 17 - Prob. 17.13EAACh. 17 - Prob. 17.14EAACh. 17 - Prob. 17.15EAACh. 17 - Prob. 17.16EAACh. 17 - Prob. 17.17EAACh. 17 - Prob. 17.18EAACh. 17 - Prob. 17.19EAACh. 17 - Prob. 17.20EAACh. 17 - Prob. 17.21EAACh. 17 - Prob. 17.22EAACh. 17 - Prob. 17.23EAACh. 17 - Prob. 17.24EAACh. 17 - Prob. 17.25EAACh. 17 - Prob. 17.26EAACh. 17 - Prob. 17.27EAACh. 17 - Prob. 17.28EAACh. 17 - Prob. 17.29EAACh. 17 - Prob. 17.30EAACh. 17 - Prob. 17.31EAACh. 17 - Prob. 17.32EAACh. 17 - Prob. 17.33EAACh. 17 - Prob. 17.34EAACh. 17 - Prob. 17.35EAACh. 17 - Prob. 17.36EAACh. 17 - Prob. 17.37EAACh. 17 - Prob. 17.38EAACh. 17 - Prob. 17.39EAACh. 17 - Prob. 17.40EAACh. 17 - Prob. 17.41EAACh. 17 - Prob. 17.42EAACh. 17 - Prob. 17.43EAACh. 17 - Prob. 17.44EAACh. 17 - Prob. 17.45EAACh. 17 - Prob. 17.46EAACh. 17 - Prob. 17.47EAACh. 17 - Prob. 17.48EAACh. 17 - Prob. 17.49EAACh. 17 - Prob. 17.50EAACh. 17 - Prob. 17.51EAACh. 17 - Prob. 17.52EAACh. 17 - Prob. 17.53EAACh. 17 - Prob. 17.54EAACh. 17 - Prob. 17.55EAACh. 17 - Prob. 17.56EAACh. 17 - Prob. 17.57EAACh. 17 - Prob. 17.58EAACh. 17 - Prob. 17.59EAACh. 17 - Prob. 17.60EAACh. 17 - Prob. 17.61EAACh. 17 - Prob. 17.62EAACh. 17 - Prob. 17.63EAACh. 17 - Prob. 17.64EAACh. 17 - Prob. 17.65EAACh. 17 - Prob. 17.66EAACh. 17 - Prob. 17.67EAACh. 17 - Prob. 17.68EAACh. 17 - Prob. 17.69EAACh. 17 - Prob. 17.70EAACh. 17 - Prob. 17.71EAACh. 17 - Prob. 17.72EAACh. 17 - Prob. 17.73EAACh. 17 - Prob. 17.74EAACh. 17 - Prob. 17.75EAACh. 17 - Prob. 17.76EAACh. 17 - Prob. 17.77EAACh. 17 - Prob. 17.78EAACh. 17 - Prob. 17.79EAACh. 17 - Prob. 17.80EAACh. 17 - Prob. 17.81EAACh. 17 - Prob. 17.82EAACh. 17 - Prob. 17.83EAACh. 17 - Prob. 17.84EAACh. 17 - Prob. 17.85EAACh. 17 - Prob. 17.86EAA
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