Chapter 17, Problem 17.101P

(a)

Interpretation Introduction

Interpretation:

Overall reaction for the formation of carbon dioxide and hydrogen from methane, steam and oxygen has to be given.

(b)

Interpretation Introduction

Interpretation:

${\text{K}}_{\text{p}}$ for the overall reaction has to be determined.

Concept Introduction:

Equilibrium constant: It is the ratio of products to reactants has a constant value when the reaction is in equilibrium at a certain temperature. And it is represented by the letter K.

For a reaction,

$\text{aA}\text{+}\text{bB}\underset{}{\rightleftharpoons }\text{cC}\text{+}\text{dD}$

The equilibrium constant in terms of  partial pressure is, $K=\frac{{\left(P_{\text{C}}\right)}^{\text{c}}{\left(P_D\right)}^{\text{d}}}{{\left(P_A\right)}^{\text{a}}{\left(P_{\text{B}}\right)}^{\text{b}}}$

where,

a, b, c and d are the stoichiometric coefficients of reactant and product in the reactions

(c)

Interpretation Introduction

Interpretation:

${\text{K}}_{\text{C}}$ for the overall reaction has to be calculated.

Concept Introduction:

The relation between and ${\text{K}}_{\text{p}}$ and ${\text{K}}_{\text{c}}$ is given by the following equation.

${\text{K}}_{\text{p}}{\text{ = K}}_{\text{c}}{\text{(RT)}}^{\Delta {\text{n}}_{\text{gas}}}\boxed{\begin{array}{l}{\text{K}}_{\text{p}}\text{ = }Equilibriumcons\tan tintermsofpartialpressure\\ {\text{K}}_{\text{c}}\text{ = }Equilibriumcons\tan tintermsofconcentration\\ \Delta {\text{n}}_{\text{gas}}\text{ = moles of gaseous product }-\text{ moles of gaseous reactant}\end{array}}$

Only moles of gaseous products and reactants are used for calculating $\Delta {\text{n}}_{\text{gas}}.$

(d)

Interpretation Introduction

Interpretation:

Final pressure for the given reaction has to be calculated using the given data.

Concept Introduction:

The relation between pressure and number of moles of gas is given by the following equation.

  $\begin{array}{c}\frac{n_{initial}}{P_{initial}}\text{ = }\frac{n_{final}}{P_{final}}\\ \\ where,\\ n\text{ = No}\text{. of moles}\\ P=\text{ Pressure}\end{array}$