Chapter 17, Problem 138AP

Calculate x, the number of molecules of water in oxalic acid hydrate ${\text{(H}}_{\text{2}}{\text{C}}_{\text{2}}{\text{O}}_{\text{4}}\cdot x{\text{H}}_{\text{2}}\text{O)}$, from the following data: 5.00 g of the compound is made up to exactly 250 mL solution, and 25.0 mL of this solution requires $\text{15}\text{.9 mL of 0}\text{.500 }M\text{ NaOH}$ solution for neutralization.