The reason for increased solubility of Ag 3 PO 4 in water than the value of its solubility calculated using K sp value has to be explained. Concept introduction: The solubility of insoluble salts containing anions (conjugate base of a weak acid) such as hydroxide, acetate, carbonate, phosphate, and sulfide is greater than the value calculated using K sp value. This is because the anion undergoes hydrolysis that is it reacts with water (acid-base reaction). This decreases the concentration of the anion in the solution and as result the reaction equilibrium shifts to right-hand side or become product favored. Thus the solubility of the salt increases.
The reason for increased solubility of Ag 3 PO 4 in water than the value of its solubility calculated using K sp value has to be explained. Concept introduction: The solubility of insoluble salts containing anions (conjugate base of a weak acid) such as hydroxide, acetate, carbonate, phosphate, and sulfide is greater than the value calculated using K sp value. This is because the anion undergoes hydrolysis that is it reacts with water (acid-base reaction). This decreases the concentration of the anion in the solution and as result the reaction equilibrium shifts to right-hand side or become product favored. Thus the solubility of the salt increases.
Solution Summary: The author explains that the solubility of insoluble salts containing anions is greater than the value calculated using K_sp value.
The reason for increased solubility of Ag3PO4 in water than the value of its solubility calculated using Ksp value has to be explained.
Concept introduction: The solubility of insoluble salts containing anions (conjugate base of a weak acid) such as hydroxide, acetate, carbonate, phosphate, and sulfide is greater than the value calculated using Ksp value. This is because the anion undergoes hydrolysis that is it reacts with water (acid-base reaction). This decreases the concentration of the anion in the solution and as result the reaction equilibrium shifts to right-hand side or become product favored. Thus the solubility of the salt increases.
You have now performed a liquid-liquid extraction protocol in Experiment 4. In doing so, you
manipulated and exploited the acid-base chemistry of one or more of the compounds in your
mixture to facilitate their separation into different phases. The key to understanding how liquid-
liquid extractions work is by knowing which layer a compound is in, and in what protonation state.
The following liquid-liquid extraction is different from the one you performed in Experiment
4, but it uses the same type of logic. Your task is to show how to separate apart Compound
A and Compound B.
. Complete the following flowchart of a liquid-liquid extraction. Handwritten work is
encouraged.
•
Draw by hand (neatly) only the appropriate organic compound(s) in the boxes.
.
Specify the reagent(s)/chemicals (name is fine) and concentration as required in Boxes 4
and 5.
•
Box 7a requires the solvent (name is fine).
•
Box 7b requires one inorganic compound.
• You can neatly complete this assignment by hand and…