COLLEGE PHYSICS-ACHIEVE AC (1-TERM)
COLLEGE PHYSICS-ACHIEVE AC (1-TERM)
3rd Edition
ISBN: 9781319453916
Author: Freedman
Publisher: MAC HIGHER
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Chapter 17, Problem 106QAP
To determine

(a)

  • Charge on the capacitor
  • Energy stored in the capacitor

Expert Solution
Check Mark

Answer to Problem 106QAP

  • Charge on the capacitor is 75μC.
  • Energy stored in the capacitor is 112.5×106J.

Explanation of Solution

Given:

Circuit diagram

COLLEGE PHYSICS-ACHIEVE AC (1-TERM), Chapter 17, Problem 106QAP , additional homework tip  1

Figure.1

Formula used:

Capacitance is given as

  C=qV

Here,

  q is the charge

  V is the voltage

Energy stored in the capacitor is given as

  U=12CV2

Here,

  C is the capacitance

  V is the voltage

Calculation:

Consider the given circuit diagram

COLLEGE PHYSICS-ACHIEVE AC (1-TERM), Chapter 17, Problem 106QAP , additional homework tip  2

Figure.1

When the switch S is connected to the point A, then only capacitor 25μF is connected to the battery, charge stored in the capacitor is calculated as

  C=qV

Plugging the values in the above equation

  25=q3q=75μC

Energy stored in the capacitor is given as

  U=12CV2

Plugging the values in the above equation

  U=12×25×106×32=112.5×106J

Conclusion:

  • Charge on the capacitor is 75μC.
  • Energy stored in the capacitor is 112.5×106J.
To determine

(b)

  • Charge and energy stored in the 25μF capacitor is
  • Charge and energy stored in the 20μF capacitor is

Expert Solution
Check Mark

Answer to Problem 106QAP

  • Charge and energy stored in the 25μF capacitor is 75μC and 112.5×106J respectively.
  • Charge and energy stored in the 20μF capacitor is 75μC and 140.6×106Jrespectively.

Explanation of Solution

Given:

Circuit diagram

COLLEGE PHYSICS-ACHIEVE AC (1-TERM), Chapter 17, Problem 106QAP , additional homework tip  3

Figure.1

Formula used:

Capacitance is given as

  C=qV

Here,

  q is the charge

  V is the voltage

Energy stored in the capacitor is given as

  U=12CV2

Here,

  C is the capacitance

  V is the voltage

Calculation:

Consider the given circuit diagram

COLLEGE PHYSICS-ACHIEVE AC (1-TERM), Chapter 17, Problem 106QAP , additional homework tip  4

Figure.1

When the switch S is connected to the point b, than none of the capacitor is connected to the battery and both the capacitor are connected in series.

In series connection both the capacitor has same charge, therefore the charge on both the capacitor is 75μC

Energy stored in the capacitor is given as

  U=12×q2C

Energy on the 25μF capacitor is calculated as

  U=12×75225=112.5×106J

Energy on the 20μF capacitor is calculated as

  U=12×75220=140.6×106J

Conclusion:

  • Charge and energy stored in the 25μF capacitor is 75μC and 112.5×106J respectively.
  • Charge and energy stored in the 20μF capacitor is 75μC and 140.6×106Jrespectively.

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Chapter 17 Solutions

COLLEGE PHYSICS-ACHIEVE AC (1-TERM)

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