Explanation Solving the quadratic equation in x by completing the square Step 1: If the coefficient of x 2 is 1. If not, divide both sides of the equation by the coefficient of x 2 . Step 2: Get all terms with variables on one side of the equation and constants on the other side. Step 3: Find half the coefficient of x and then square the result. Add this number to both sides of the equation. Step 4: Factor the resulting perfect square trinomial. Step 5: Use the square root property to solve the equation. Calculation: Given, 3 x 2 + x = 2 Step-1: 3 x 2 + x = 2 Divide by 3 the coefficient of x 2 on both sides, 3 x 2 3 + x 3 = 2 3 x 2 + x 3 = 2 3 Step-2: Not necessary Step-3: Make the expression on the left side as a perfect square. Add the square of the half of the coefficient of x on both sides, x 2 + x 3 + ( 1 6 ) 2 = 2 3 + ( 1 6 ) 2 x 2 + 1 3 x + ( 1 6 ) 2 = 2 3 + 1 36 x 2 + 1 3 x + ( 1 6 ) 2 = 2 3 ⋅ 12 12 + 1 36 x 2 + 1 36 x + ( 1 6 ) 2 = 24 36 + 1 36 x 2 + 1 3 x + ( 1 6 ) 2 = 25 36 Now, we express x 2 + 1 3 x + ( 1

Prealgebra & Introductory Algebra (4th Edition)

4th Edition

ISBN: 9780321955791

Author: Elayn Martin-Gay

Publisher: PEARSON

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Chapter 16.CR, Problem 63CR

To determine

To solve:

3x2+x=2

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Chapter 16.CR, Problem 62CR

Chapter 16.CR, Problem 64CR

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Chapter 16 Solutions

Prealgebra & Introductory Algebra (4th Edition)

Ch. 16.1 - Prob. 1P Ch. 16.1 - Prob. 2P Ch. 16.1 - Prob. 3P Ch. 16.1 - Prob. 4P Ch. 16.1 - Prob. 5P Ch. 16.1 - Prob. 6P Ch. 16.1 - Prob. 7P Ch. 16.1 - Prob. 8P Ch. 16.1 - Prob. 9P Ch. 16.1 - Prob. 1E

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3 x 2 + x = 2

To solve: 3x2+x=2

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Chapter 16 Solutions

To solve:

3x2+x=2