
(a)
Interpretation:
An explanation corresponding to the fact that pyrrole is isoelectronic with the cyclopentadienyl anion is to be stated.
Concept introduction:
Isoelectronic species are those species that have same number of electrons or same electronic configuration. These species have same chemical properties.
(b)
Interpretation:
The difference between the compound cyclopentadienyl anion and pyrrole is to be determined.
Concept introduction:
Bases are the molecules that can accept the proton by sharing its lone pair of electrons. The atoms that are basic in a molecule always have the lone to lone pair to accept the proton. Some of the molecules may contain more than one basic atom.
The lone pairs that are present in the molecule can be neutral or anionic atoms.
(c)
Interpretation:
The resonance structures that show the charge distribution on the pyrrole structure are to be represented.
Concept introduction:
The concept of resonance related to the stability of the molecules. Resonance structures show the movement of delocalized electrons in the molecule, when the bonding of the molecule cannot express by the single structures.

Want to see the full answer?
Check out a sample textbook solution
Chapter 16 Solutions
ORGANIC CHEMISTRY II LAB MANUAL>CUSTOM<
- Draw the mechanism of the reaction.arrow_forward9. Draw all of the possible Monochlorination Products that would Result From the Free Radical Chlormation OF 23,4-TRIMethyl Pentane b. Calculate the To Yield For the major • Product given the Following Relative Restritus For 1° 2° and 30 Hydrogens toward Free Radical Chloration 5.0: 38 : 1 30 2° 1° C. what would be the major product in the Free Radical brominator Of the Same Molecule. Explain your Reasoning.arrow_forwardWhat is the complete reaction mechanism for the chlorination of Ethane, C2H6?arrow_forward
- A 13C NMR spectrum is shown for a molecule with the molecular formula of C6H100. Draw the structure that best fits this data. 220 200 180 160 140 120100 80 60 40 20 Drawingarrow_forwardPlease help me figure out the blan areas with step by step calculations.arrow_forwardneeding help draw all of the possible monochlorination products that would result from the free radical chlorination of 2,3,4-trimethylpentanearrow_forward
- HAND DRAWarrow_forwardBased on the 1H NMR, 13C NMR, DEPT 135 NMR and DEPT 90 NMR, provide a reasoning step and arrive at the final structure of an unknown organic compound containing 7 carbons. Dept 135 shows peak to be positive at 128.62 and 13.63 Dept 135 shows peak to be negative at 130.28, 64.32, 30.62 and 19.10. Provide assignment for the provided structurearrow_forwardO Predict the 'H NMR integration ratio for the following structure. IV I. 3 H A II. 1 H III. 2 H IV. 3 H I. 3 H B II. O H III. 2 H IV. 3 H I. 3 H C II. 2 H III. 2 Harrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning

