KLEIN'S ORGANIC CHEMISTRY
3rd Edition
ISBN: 9781119423126
Author: Klein
Publisher: WILEY
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Question
Chapter 16.9, Problem 21PTS
(a)
Interpretation Introduction
Interpretation:
For the given reactions, the product formed should be determined.
Concept introduction:
- Electrocyclic reaction is a concerted cyclization reaction of conjugated polyenes (π-system), in which one π-bond is converted into an σ-bond and remaining π-bonds shift their positions. Thereby the newly formed σ-bond connects the two ends of π-system to form a ring.
- The mechanism of the ring formation in the Electrocyclic reaction is drawn by using arrows representing the forming σ-bond and the shifting of π-bonds in the π-system of a polyene.
- The reaction conditions (thermal or photochemical) controls the product in such a way that the rotation for end lobes (ring closure) of the HOMO of conjugated (π-system) polyene.
- According to Woodward-Hoffmann rule for thermal and photochemical Electrocyclic reactions,
π-systems | Thermal | Photochemical |
4- π-electrons | Conrotatory | Disrotatory |
6- π-electrons | Disrotatory | Conrotatory |
- The mechanism for reverse of Electrocyclic reaction is drawn by using arrows representing the conversion of σ-bond to π-bond and the shifting of π-bonds in the π-system of a cyclic
alkene .
To determine: the major product formed for each of the given electrocyclic reactions.
(b)
Interpretation Introduction
Interpretation:
For the given reactions, the product formed should be determined.
Concept introduction:
- Electrocyclic reaction is a concerted cyclization reaction of conjugated polyenes (π-system), in which one π-bond is converted into an σ-bond and remaining π-bonds shift their positions. Thereby the newly formed σ-bond connects the two ends of π-system to form a ring.
- The mechanism of the ring formation in the Electrocyclic reaction is drawn by using arrows representing the forming σ-bond and the shifting of π-bonds in the π-system of a polyene.
- The reaction conditions (thermal or photochemical) controls the product in such a way that the rotation for end lobes (ring closure) of the HOMO of conjugated (π-system) polyene.
- According to Woodward-Hoffmann rule for thermal and photochemical Electrocyclic reactions,
π-systems | Thermal | Photochemical |
4- π-electrons | Conrotatory | Disrotatory |
6- π-electrons | Disrotatory | Conrotatory |
- The mechanism for reverse of Electrocyclic reaction is drawn by using arrows representing the conversion of σ-bond to π-bond and the shifting of π-bonds in the π-system of a cyclic alkene.
To determine: the major product formed for each of the given electrocyclic reactions.
(c)
Interpretation Introduction
Interpretation:
For the given reactions, the product formed should be determined.
Concept introduction:
- Electrocyclic reaction is a concerted cyclization reaction of conjugated polyenes (π-system), in which one π-bond is converted into an σ-bond and remaining π-bonds shift their positions. Thereby the newly formed σ-bond connects the two ends of π-system to form a ring.
- The mechanism of the ring formation in the Electrocyclic reaction is drawn by using arrows representing the forming σ-bond and the shifting of π-bonds in the π-system of a polyene.
- The reaction conditions (thermal or photochemical) controls the product in such a way that the rotation for end lobes (ring closure) of the HOMO of conjugated (π-system) polyene.
- According to Woodward-Hoffmann rule for thermal and photochemical Electrocyclic reactions,
π-systems | Thermal | Photochemical |
4- π-electrons | Conrotatory | Disrotatory |
6- π-electrons | Disrotatory | Conrotatory |
- The mechanism for reverse of Electrocyclic reaction is drawn by using arrows representing the conversion of σ-bond to π-bond and the shifting of π-bonds in the π-system of a cyclic alkene.
To determine: the major product formed for each of the given electrocyclic reactions.
Expert Solution & Answer
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Deducing the reactants of a Diels-Alder reaction
n the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one
step, by moderately heating the reactants?
?
Δ
• If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any
arrangement you like.
• If your answer is no, check the box under the drawing area instead.
Explanation Check
Click and drag to start drawing a structure.
>
Predict the major products of the following organic reaction:
+
Some important notes:
A
?
• Draw the major product, or products, of the reaction in the drawing area below.
• If there aren't any products, because no reaction will take place, check the box below the drawing area instead.
• Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are
enantiomers.
Explanation
Check
Click and drag to start drawing a structure.
Chapter 16 Solutions
KLEIN'S ORGANIC CHEMISTRY
Ch. 16.1 - Prob. 1CCCh. 16.2 - Prob. 2CCCh. 16.2 - Prob. 3CCCh. 16.2 - Prob. 4CCCh. 16.3 - Prob. 5CCCh. 16.4 - Prob. 1LTSCh. 16.4 - Prob. 6PTSCh. 16.4 - Prob. 7PTSCh. 16.4 - Prob. 8ATSCh. 16.5 - Prob. 2LTS
Ch. 16.5 - Prob. 9PTSCh. 16.5 - Prob. 10PTSCh. 16.5 - Prob. 11ATSCh. 16.5 - Prob. 12CCCh. 16.7 - Prob. 3LTSCh. 16.7 - Prob. 13PTSCh. 16.7 - Prob. 14ATSCh. 16.7 - Prob. 15CCCh. 16.7 - Prob. 16CCCh. 16.7 - Prob. 17CCCh. 16.7 - Predict the regiochemical outcome (major product)...Ch. 16.8 - Prob. 19CCCh. 16.9 - Prob. 20CCCh. 16.9 - Prob. 4LTSCh. 16.9 - Prob. 21PTSCh. 16.9 - Prob. 22ATSCh. 16.10 - Prob. 23CCCh. 16.10 - Prob. 24CCCh. 16.10 - Prob. 25CCCh. 16.10 - Prob. 26CCCh. 16.11 - Prob. 5LTSCh. 16.11 - Prob. 27PTSCh. 16.11 - Prob. 28ATSCh. 16.12 - Prob. 29CCCh. 16 - Prob. 30PPCh. 16 - Prob. 31PPCh. 16 - Prob. 32PPCh. 16 - Prob. 33PPCh. 16 - Prob. 34PPCh. 16 - Prob. 35PPCh. 16 - Prob. 36PPCh. 16 - Prob. 37PPCh. 16 - Prob. 38PPCh. 16 - Prob. 39PPCh. 16 - Prob. 40PPCh. 16 - Prob. 41PPCh. 16 - Prob. 42PPCh. 16 - Prob. 43PPCh. 16 - Prob. 44PPCh. 16 - Prob. 45PPCh. 16 - Prob. 46PPCh. 16 - Prob. 47PPCh. 16 - Prob. 48PPCh. 16 - Prob. 49PPCh. 16 - Prob. 50PPCh. 16 - Prob. 51PPCh. 16 - Prob. 52PPCh. 16 - Prob. 53PPCh. 16 - Prob. 54PPCh. 16 - Prob. 55PPCh. 16 - Prob. 56PPCh. 16 - Prob. 57PPCh. 16 - Prob. 58PPCh. 16 - Prob. 59PPCh. 16 - Prob. 60IPCh. 16 - Prob. 61IPCh. 16 - Prob. 62IPCh. 16 - Prob. 63IPCh. 16 - Prob. 64IPCh. 16 - Prob. 65IPCh. 16 - Prob. 66IPCh. 16 - Prob. 67IPCh. 16 - Prob. 68IPCh. 16 - Prob. 69IPCh. 16 - Prob. 70IPCh. 16 - Prob. 71IPCh. 16 - Prob. 72IPCh. 16 - Prob. 73IPCh. 16 - Prob. 74IPCh. 16 - Prob. 76IPCh. 16 - Prob. 77CPCh. 16 - Prob. 78CPCh. 16 - Prob. 79CPCh. 16 - Prob. 80CPCh. 16 - Prob. 81CP
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