The product of the given reaction has to be predicted. Concept introduction: Lithium aluminium hydride ( LiAlH 4 ) and sodium borohydride ( NaBH 4 ) are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde , ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the LiAlH 4 thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively. Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

Question

Want to see the full answer?

Answer 1

Question

Chapter 16.7, Problem 26P

(a)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

(b)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

(c)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

(d)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

HELP NOW PLEASE ! URGENT!

Answer 2

Question

Chapter 16.7, Problem 26P

(a)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

(b)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

(c)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

(d)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 16.7, Problem 26P

(a)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

(b)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

(c)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

(d)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 16.7, Problem 26P

(a)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

(b)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

(c)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

(d)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 16.7, Problem 26P

(a)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

(b)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

(c)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

(d)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

Answer 6

Chapter 16.7, Problem 26P

(a)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

Answer 7

Chapter 16.7, Problem 26P

(a)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

Answer 10

(c)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

Answer 11

(c)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

Answer 12

(d)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

Answer 13

(d)

Interpretation Introduction

Interpretation:

The product of the given reaction has to be predicted.

Concept introduction:

Lithium aluminium hydride $(LiAlH4)$ and sodium borohydride $(NaBH4)$ are hydride ion donors and act as reducing agents. Lithium aluminium hydride is a strong reducing agent and it reduces aldehyde, ketone, esters carboxylic acid and amides. Sodium borohydride, on the other hand, is weak reducing agent compared to the $LiAlH4$ thus reduces selectively aldehyde and ketone into primary and secondary alcohols respectively.

Carbon-carbon double and triple bond can be reduced via catalytic hydrogenation in presence of palladium metal. The hydrogen atom can be added across the multiple bonds and thus can be reduced. Aldehyde and ketones cannot be reduced by catalytic hydrogenation in presence of palladium metal.

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 17

Ch. 16.1 - Give two names for each of the following:Ch. 16.1 - Prob. 2P Ch. 16.1 - Name the following:Ch. 16.2 - Prob. 4P Ch. 16.4 - What products are formed when the following...Ch. 16.4 - We saw on the previous page that...Ch. 16.4 - a. How many stereoisomers are obtained from the...Ch. 16.4 - Prob. 9P Ch. 16.4 - Write the mechanism for the reaction of acetyl...Ch. 16.4 - Prob. 11P

Solution Summary: The author explains that hydride ion donors and reducing agents reduce aldehyde, ketone, esters carboxylic acid, etc.

Want to see the full answer?

Chapter 16 Solutions