THERMODYNAMICS LLF W/ CONNECT ACCESS
9th Edition
ISBN: 9781264446889
Author: CENGEL
Publisher: MCG
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Chapter 16.6, Problem 83RP
To determine
The equilibrium constant of the dissociation process
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1- Determine the following: 1- RSHF? 2- C.C.C in tons-ref. 3- Mass
of supply air?
Fresh
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air
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How do I solve this task
A weight for a lift is suspended using an adapter. The counterweight is held up with 4 screws. The weight F is 3200kg.
The screws have a strength class of 8.8. Safety factor 3
Which is the smallest bunch size that can be used?+_Sr/Fm =0,16Gr=0,71ơ=800·0.8=640 MPaAs=?Fmax= As·ơ·GrFs=ơs·AsFFm= Fs· GFSF =SF / FFm · FFm Fpreload =Fload / SF → Fload /3Fpreload per screw =Fload / SF → Fload /4As=Fpreload per screw /ơ·Gr → As= Fpreload per screw / 640· 0.71
The correct answer should be M12 with As=84.3mm²
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Chapter 16 Solutions
THERMODYNAMICS LLF W/ CONNECT ACCESS
Ch. 16.6 - Why is the criterion for chemical equilibrium...Ch. 16.6 - Write three different KPrelations for reacting...Ch. 16.6 - Is a wooden table in chemical equilibrium with the...Ch. 16.6 - A reaction chamber contains a mixture of CO2, CO,...Ch. 16.6 - A reaction chamber contains a mixture of N2and N...Ch. 16.6 - A reaction chamber contains a mixture of CO2, CO,...Ch. 16.6 - Which element is more likely to dissociate into...Ch. 16.6 - Prob. 8PCh. 16.6 - Prob. 9PCh. 16.6 - Prob. 10P
Ch. 16.6 - Prob. 11PCh. 16.6 - Prob. 12PCh. 16.6 - Prob. 13PCh. 16.6 - Prob. 14PCh. 16.6 - Prob. 15PCh. 16.6 - Prob. 16PCh. 16.6 - Prob. 17PCh. 16.6 - Prob. 18PCh. 16.6 - Prob. 19PCh. 16.6 - Prob. 20PCh. 16.6 - Prob. 21PCh. 16.6 - Prob. 22PCh. 16.6 - Prob. 23PCh. 16.6 - Determine the equilibrium constant KP for the...Ch. 16.6 - Prob. 26PCh. 16.6 - Prob. 27PCh. 16.6 - Carbon monoxide is burned with 100 percent excess...Ch. 16.6 - Prob. 30PCh. 16.6 - Prob. 31PCh. 16.6 - Estimate KP for the following equilibrium reaction...Ch. 16.6 - Prob. 33PCh. 16.6 - A mixture of 3 mol of N2, 1 mol of O2, and 0.1 mol...Ch. 16.6 - Prob. 35PCh. 16.6 - Prob. 36PCh. 16.6 - Prob. 37PCh. 16.6 - Prob. 38PCh. 16.6 - Prob. 40PCh. 16.6 - What is the equilibrium criterion for systems that...Ch. 16.6 - Prob. 43PCh. 16.6 - Prob. 44PCh. 16.6 - Prob. 45PCh. 16.6 - Prob. 47PCh. 16.6 - Prob. 48PCh. 16.6 - Prob. 51PCh. 16.6 - Prob. 52PCh. 16.6 - Prob. 53PCh. 16.6 - Prob. 54PCh. 16.6 - Prob. 55PCh. 16.6 - Prob. 56PCh. 16.6 - Prob. 58PCh. 16.6 - Prob. 59PCh. 16.6 - Prob. 60PCh. 16.6 - Prob. 61PCh. 16.6 - Using the Henrys constant data for a gas dissolved...Ch. 16.6 - Prob. 63PCh. 16.6 - Prob. 64PCh. 16.6 - Prob. 65PCh. 16.6 - Prob. 66PCh. 16.6 - A liquid-vapor mixture of refrigerant-134a is at...Ch. 16.6 - Prob. 68PCh. 16.6 - Prob. 69PCh. 16.6 - An oxygennitrogen mixture consists of 30 kg of...Ch. 16.6 - Prob. 71PCh. 16.6 - Prob. 72PCh. 16.6 - Prob. 73PCh. 16.6 - Prob. 74PCh. 16.6 - Prob. 75PCh. 16.6 - Prob. 76PCh. 16.6 - An ammoniawater absorption refrigeration unit...Ch. 16.6 - Prob. 78PCh. 16.6 - Prob. 79PCh. 16.6 - Prob. 80PCh. 16.6 - One lbmol of refrigerant-134a is mixed with 1...Ch. 16.6 - Prob. 82RPCh. 16.6 - Prob. 83RPCh. 16.6 - Prob. 84RPCh. 16.6 - Prob. 85RPCh. 16.6 - Prob. 88RPCh. 16.6 - Prob. 89RPCh. 16.6 - Prob. 90RPCh. 16.6 - Prob. 91RPCh. 16.6 - Prob. 92RPCh. 16.6 - A constant-volume tank contains a mixture of 1 mol...Ch. 16.6 - Prob. 94RPCh. 16.6 - Prob. 95RPCh. 16.6 - Prob. 96RPCh. 16.6 - Prob. 97RPCh. 16.6 - Prob. 99RPCh. 16.6 - Consider a glass of water in a room at 25C and 100...Ch. 16.6 - Prob. 101RPCh. 16.6 - Prob. 102RPCh. 16.6 - Prob. 105RPCh. 16.6 - Prob. 106RPCh. 16.6 - Prob. 107RPCh. 16.6 - Prob. 108RPCh. 16.6 - Prob. 109FEPCh. 16.6 - Prob. 110FEPCh. 16.6 - Prob. 111FEPCh. 16.6 - Prob. 112FEPCh. 16.6 - Prob. 113FEPCh. 16.6 - Prob. 114FEPCh. 16.6 - Propane C3H8 is burned with air, and the...Ch. 16.6 - Prob. 116FEPCh. 16.6 - Prob. 117FEPCh. 16.6 - The solubility of nitrogen gas in rubber at 25C is...
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- A spring package with two springs and an external force, 200N. The short spring has a loin of 35 mm. Constantly looking for spring for short spring so that total compression is 35 mm (d). Known values: Long spring: Short spring:C=3.98 N/mm Lo=65mmLo=87.4mmF=c·fTotal compression is same for both spring. 200 = (3.98(c1) × 35) + (c₂ × 35) 200 = 139.3 + 35c₂ 200 - 139.3 = 35c₂ 60.7 = 35c₂ c₂ = 60.7/35 Short spring (c₂) = 1.73 N/mm According to my study book, the correct answer is 4.82N/mm What is wrong with the calculating?arrow_forwardWhat is the reason for this composition?arrow_forwardHomework: ANOVA Table for followed design B AB Dr -1 -1 1 (15.18,12) 1 -1 -1 (45.48.51) -1 1 -1 (25,28,19) 1 1 (75.75,81)arrow_forward
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