Chapter 16.2, Problem 68E

(a)

To determine

To calculate: The vertical position of a worn shock absorber on a car undergoes simple harmonic motion at $t=0$ so that the height of the car frame after t seconds is given by the equation $p\left(t\right)=4.2\sin \left(2\pi t+\frac{\pi }{2}\right)$ centimeters above the rest position.

(b)

To determine

To calculate: The speed of changing the height of the car and the direction at times $t=0$ and $t=0.25$ if a worn shock absorber on a car undergoes simple harmonic motion so that the height of the car frame after t seconds is given by $p\left(t\right)=4.2\sin \left(2\pi t+\frac{\pi }{2}\right)$ centimeters above the rest position.

(c)

To determine

To calculate: The frequency of oscillation of the car frame if a worn shock absorber on a car undergoes simple harmonic motion so that the height of the car frame after t seconds is given by $p\left(t\right)=4.2\sin \left(2\pi t+\frac{\pi }{2}\right)$ centimeters above the rest position. The frequency of oscillation is defined as the reciprocal of the period.