Explanation Given: F → = 〈 2 x z e x 2 , 0 , e x 2 〉 is a vector field. Formula used: If f is a potential function for the vector field F → then F → = ∇ → f Where, ∇ → = 〈 ∂ ∂ x , ∂ ∂ y , ∂ ∂ z 〉 Curl of a vector is given by ∇ → × F → If Curl F → = 0 F → is conservative then potential function exist. If Curl F → ≠ 0 mean F → is not conservative then potential function does not exist. Calculation: Checking for existence of the potential function by taking Curl of the given potential function, F → = 〈 2 x z e x 2 , 0 , e x 2 〉 we get- = ∇ → × F → = | i ^ j ^ k ^ ∂ ∂ x ∂ ∂ y ∂ ∂ z 2 x z e x 2 0 e x 2 | = i ^ × 0 − j ^ ( 2 x e x 2 − 2 x e x 2 ) + k ^ ( 0 − 0 ) = 0 Thus, Curl F → = 0 . This mean F → is conservative. Thus the potential function exists...

4th Edition

ISBN: 9781319308858

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 16.1, Problem 46E

To determine

Potential function for the vector field $\vec{F} = 〈 2 x z e^{x^{2}}, 0, e^{x^{2}} 〉$ by inspection or show that one does not exist.

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Chapter 16.1, Problem 45E

Chapter 16.1, Problem 47E

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Chapter 16 Solutions

CALCULUS:EARLY TRANS.(LL)-W/ACCESS

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Knowledge Booster

Potential function for the vector field F → = 〈 2 x z e x 2 , 0 , e x 2 〉 by inspection or show that one does not exist.

Potential function for the vector field F→=〈2xzex2,0,ex2〉 by inspection or show that one does not exist.

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Chapter 16 Solutions

Potential function for the vector field $\vec{F} = 〈 2 x z e^{x^{2}}, 0, e^{x^{2}} 〉$ by inspection or show that one does not exist.