COMPTIA A+ GUIDE TO IT TECH SUPPORT
COMPTIA A+ GUIDE TO IT TECH SUPPORT
10th Edition
ISBN: 9780357466810
Author: ANDREWS
Publisher: CENGAGE L
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Chapter 16, Problem 9TC

Explanation of Solution

Given:

A computer named Fin.

The Explorer search box is present to access the Remote Admin Share.

To find: The command that can be entered in explorer to get an access to the Remote Admin share on computer...

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Please answer JAVA OOP problem below: You are working at a university that tracks students. Each student is identified by their name and faculty advisor. Each faculty advisor is identified by their name, department, and maximum number of students they can advise. Using solid OO design principles, create a modular program that implements all the classes for the problem and also creates an implementation class that gathers user input for one student and then prints out the information gathered by creating the appropriate data definition and implementation classes. All data must be validated.    I have given the code so far: Implementation: import javax.swing.JOptionPane; public class Implementation {     public static void main(String[] args) {         FacultyAdvisor facultyAdvisor = new FacultyAdvisor("Sharmin Sultana", "IT", 30);         Student student = new Student("John", facultyAdvisor);         JOptionPane.showMessageDialog(null, student.toString());     } }   Student: public…
Exercise 1 Function and Structure [30 pts] Please debug the following program and answer the following questions. There is a cycle in a linked list if some node in the list can be reached again by continuously following the next pointer. #include typedef struct node { int value; struct node *next; } node; int 11_has_cycle (node *first) if (first == node *head { NULL) return 0;B = first; while (head->next != NULL) { if (head == first) { return 1; } head head->next; } return 0; void test_11_has_cycle() { int i; node nodes [6]; for (i = 0; i < 6; i++) nodes [i] .next = NULL; nodes [i].value i; } nodes [0] .next = &nodes [1]; nodes [1] .next = &nodes [2]; nodes [2] .next = &nodes [3]; nodes [3] .next = & nodes [4]; nodes [4] .next = NULL; nodes [5] .next = &nodes [0]; printf("1. Checking first list for cycles. \n Function 11_has_cycle says it hass cycle\n\n", 11_has_cycle (&nodes [0]) ?"a":"no"); printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle says it has %s…
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