Explanation Since electric force acting on the electron is in x direction, electron experiences an acceleration along x direction. Since the electric field does not have component in y direction, there is no force on the electron in the electron y direction and it moves with initial velocity with which it was entered. Write the expression for the displacement of the electron along y direction. Δ y = v y Δ t + 1 2 a y ( Δ t ) 2 Here, Δ y is the displacement along y direction, v y is the velocity of electron along y direction, Δ t is the time taken to travel and a y is the acceleration along the y direction Since there is no force in the y direction, the value of a y will also be zero. Substitute 0 for a y in the above equation. Δ y = v y Δ t + 0 = v y Δ t (I) Write the expression for the electric force on the electron in x direction. Σ F x = − e E (II) Here, Σ F x is the net force along x direction, − e is the charge of electron and E is the electric field. Write the newton’s second law along x direction. Σ F x = m a x (III) Here. m is the mass of electron and a x is the acceleration of the electron in x direction. Equate equations (II) and (III) and rewrite the equation for a x . m a x = − e E a x = − e E m (IV) Write the expression for the displacement of electron along x direction. Δ x = v x ( Δ t ) + 1 2 a x ( Δ t ) 2 Here, Δ x is the displacement along x direction, v x is the velocity of electron along x direction. Since the electron has initial velocity only in y direction, the value of v x is zero. Δ x = 0 + 1 2 a x ( Δ t ) 2 = 1 2 a x ( Δ t ) 2 Put equation (IV) in the above equation. Δ x = 1 2 ( − e E m ) ( Δ t ) 2 = − 1 2 ( e E m ) ( Δ t ) 2 (VI) Conclusion: Substitute 10

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ISBN: 9781260486919

Author: GIAMBATTISTA

Publisher: MCG

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

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Chapter 16, Problem 97P

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The x and y components of the electron’s displacement 2.40 μs after entering the electric-filed region if no other forces act on it.

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Chapter 16, Problem 96P

Chapter 16, Problem 98P

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Chapter 16 Solutions

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Ch. 16.1 - 16.1 A glass rod and piece of silk are both...Ch. 16.1 - Prob. 16.1PP Ch. 16.2 - Prob. 16.2PP Ch. 16.3 - Prob. 16.3CP Ch. 16.3 - 16.3 Electric Force on a Point Charge Suppose...Ch. 16.3 - 16.4 Three Point Charges Three identical point...Ch. 16.4 - 16.5 Effect of Doubling the Charge on the Hanging...Ch. 16.4 - Practice Problem 16.6 Electric Field at Point P...Ch. 16.4 - Practice Problem 16.7 Electric Field due to Two...Ch. 16.4 - 16.4 What is the direction of the electric field...

Ch. 16.4 - Prob. 16.8PP Ch. 16.5 - Prob. 16.5CP Ch. 16.5 - 16.9 Slowing Some Protons If a beam of protons...Ch. 16.5 - Prob. 16.10PP Ch. 16.6 - Prob. 16.11PP Ch. 16.7 - Prob. 16.12PP Ch. 16.7 - Prob. 16.13PP Ch. 16 - Prob. 1CQ Ch. 16 - Prob. 2CQ Ch. 16 - Prob. 3CQ Ch. 16 - Prob. 4CQ Ch. 16 - Prob. 5CQ Ch. 16 - Prob. 6CQ Ch. 16 - Prob. 7CQ Ch. 16 - Prob. 8CQ Ch. 16 - Prob. 9CQ Ch. 16 - Prob. 10CQ Ch. 16 - Prob. 11CQ Ch. 16 - Prob. 12CQ Ch. 16 - 13. An electroscope consists of a conducting...Ch. 16 - Prob. 14CQ Ch. 16 - Prob. 15CQ Ch. 16 - 16. In some textbooks, the electric field is...Ch. 16 - Prob. 17CQ Ch. 16 - Prob. 18CQ Ch. 16 - Prob. 19CQ Ch. 16 - Prob. 1MCQ Ch. 16 - 2. In electrostatic equilibrium, the excess...Ch. 16 - Prob. 3MCQ Ch. 16 - Prob. 4MCQ Ch. 16 - Prob. 5MCQ Ch. 16 - 6. A tiny charged pellet of mass m is suspended at...Ch. 16 - Prob. 7MCQ Ch. 16 - Prob. 8MCQ Ch. 16 - Prob. 9MCQ Ch. 16 - Prob. 10MCQ Ch. 16 - 1. 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