Chapter 16, Problem 90E

Interpretation Introduction

Interpretation:

The normality of a solution of ${\text{HNO}}_{\text{3}}$ prepared by dilution of $\text{25}\text{.0}\text{mL}$ of $\text{15}\text{M}$ ${\text{HNO}}_{\text{3}}$ to $4.00\times {10}^2\text{mL}$ is to be calculated.

Concept introduction:

Molarity is defined as the number of moles of solute present in one liter of solution. This can be expressed by the relation given below.

$\text{M}=\frac{\text{n}}{\text{V}\left(\text{in L}\right)}$

On dilution, the molarity and the volume of the final solution are calculated by the relation given below.

${\text{M}}_{\text{c}}{\text{V}}_{\text{c}}={\text{M}}_{\text{d}}{\text{V}}_{\text{d}}$