2 SEM ACC W/RAVEN CARDED
2 SEM ACC W/RAVEN CARDED
12th Edition
ISBN: 9781264439218
Author: Raven
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Chapter 16, Problem 7A

A mechanism of control in E. coli not discussed in this chapter involves pausing of ribosomes allowing a transcription terminator to form in the mRNA. In eukaryotic fission yeast, this mechanism should

a. be common since they are unicellular.

b. not be common since they are unicellular.

c. not occur as transcription occurs in the nucleus and translation in the cytoplasm.

d. not occur due to possibility of alternative splicing.

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Molecular Biology A-C components of the question are corresponding to attached image labeled 1. D component of the question is corresponding to attached image labeled 2. For a eukaryotic mRNA, the sequences is as follows where AUGrepresents the start codon, the yellow is the Kozak sequence and (XXX) just represents any codonfor an amino acid (no stop codons here). G-cap and polyA tail are not shown A. How long is the peptide produced?B. What is the function (a sentence) of the UAA highlighted in blue?C. If the sequence highlighted in blue were changed from UAA to UAG, how would that affecttranslation? D. (1) The sequence highlighted in yellow above is moved to a new position indicated below. Howwould that affect translation? (2) How long would be the protein produced from this new mRNA? Thank you
Molecular Biology Question Explain why the cell doesn’t need 61 tRNAs (one for each codon). Please help. Thank you

Chapter 16 Solutions

2 SEM ACC W/RAVEN CARDED

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