To determine To find : The time required for the sound intensity level heard by the gardener to increase by 10.0 dB . Explanation Given data: A portable radio is sitting at the edge of a balcony 5.1 m above the ground. The unit is emitting the sound uniformly in all directions. By an accident, the radio falls from the balcony and continue to play on the way down. A gardener is working in a flower bed directly below the falling unit. Formula used: Consider the sound intensity level at the initial position (edge of the balcony), and at the final position (ground) of the radio as β i , and β f respectively. Refer to the equation (16.10) in the textbook, and modify the expression for sound intensity level at the initial position of the radio as follows. β i = ( 10 dB ) log ( I i I 0 ) (1) Here, I i is the sound intensity at the initial position of the radio, and I 0 is the intensity of the reference level, which is 1.0 × 10 − 12 W m 2 . Refer to the equation (16.10) in the textbook, and modify the expression for sound intensity level at the final position of the radio as follows. β f = ( 10 dB ) log ( I f I 0 ) (2) Here, I f is the sound final at the initial position of the radio Consider the height (distance) between the radio (source) and the gardener (observer) as h i when the radio at its initial position, which is given as 5.1 m. Consider the height between the radio and the gardener as h f when the radio at its final position. Refer to the equation (16.9) in the textbook, and modify the expression for sound intensity at the initial position of the radio as follows. I i = P 4 π ( h i ) 2 (3) Here, P is the power radiated from the radio, which is equal at all points (since the radio emits the sound uniformly in all the directions). Refer to the equation (16.9) in the textbook, and modify the expression for sound intensity at the final position of the radio as follows. I f = P 4 π ( h f ) 2 (4) From the given data, the sound intensity level increased to 10.0 dB when the radio falls to ground from the balcony. Therefore, write the expression as follows. β f − β i = 10.0 dB (5) Calculation of height between the radio and the gardener when the radio at its final position ( h f ) : From the given data, the height between the radio and the gardener when the radio at its initial position is 5.1 m. h i = 5.1 m Subtract equation (1) from equation (2) as follows. β f − β i = ( 10 dB ) log ( I f I 0 ) − ( 10 dB ) log ( I i I 0 ) = ( 10 dB ) [ log ( I f I 0 ) − log ( I i I 0 ) ] = ( 10 dB ) log [ ( I f I 0 ) ( I i I 0 ) ] { ∵ log ( A ) − log ( B ) = log ( A B ) } = ( 10 dB ) log ( I f I i ) From equation (3), and (4), substitute P 4 π ( h i ) 2 for I i , and P 4 π ( h f ) 2 for I f , β f − β i = ( 10 dB ) log [ P 4 π ( h f ) 2

11th Edition

ISBN: 9781119326342

Author: CUTNELL

Publisher: WILEY

See similar textbooks

Concept explainers

Properties of sound

A sound wave is a mechanical wave (or mechanical vibration) that transit through media such as gas (air), liquid (water), and solid (wood).

Quality Of Sound

A sound or a sound wave is defined as the energy produced due to the vibrations of particles in a medium. When any medium produces a disturbance or vibrations, it causes a movement in the air particles which produces sound waves. Molecules in the air vib…

Categories of Sound Wave

People perceive sound in different ways, like a medico student takes sound as vibration produced by objects reaching the human eardrum. A physicist perceives sound as vibration produced by an object, which produces disturbances in nearby air molecules th…

Videos

Question

Chapter 16, Problem 73P

To determine

To find: The time required for the sound intensity level heard by the gardener to increase by 10.0 dB .

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 16, Problem 72P

Chapter 16, Problem 76P

Students have asked these similar questions

Calculate the center of mass of the hollow cone shown below. Clearly specify the origin and the coordinate system you are using. Z r Y h X

12. If all three collisions in the figure below are totally inelastic, which will cause more damage? (think about which collision has a larger amount of kinetic energy dissipated/lost to the environment? I m II III A. I B. II C. III m m v brick wall ע ע 0.5v 2v 0.5m D. I and II E. II and III F. I and III G. I, II and III (all of them) 2m

Can you solve this 2 question teach me step by step and draw for me

Chapter 16 Solutions

Physics

Ch. 16.1 - Prob. 2CYU Ch. 16.2 - 3. A sound wave (a periodic longitudinal wave)...Ch. 16.3 - Prob. 4CYU Ch. 16.3 - Prob. 5CYU Ch. 16.3 - Prob. 6CYU Ch. 16.3 - Prob. 7CYU Ch. 16.3 - Prob. 8CYU Ch. 16.3 - Prob. 9CYU Ch. 16.5 - 10. In a traveling sound wave, are there any...Ch. 16.6 - 11. Do you expect an echo to return to you more...

Ch. 16.6 - 12. Carbon monoxide (CO), hydrogen (H2). and...Ch. 16.6 - Prob. 13CYU Ch. 16.7 - 14. Sonic animals rely on an acute sense of...Ch. 16.7 - Prob. 15CYU Ch. 16.8 - Prob. 16CYU Ch. 16.8 - Prob. 17CYU Ch. 16.9 - Prob. 18CYU Ch. 16.9 - 19. When a car is at rest, its horn emits a...Ch. 16.9 - Prob. 20CYU Ch. 16.9 - Prob. 21CYU Ch. 16.9 - Prob. 22CYU Ch. 16 - Prob. 2FC Ch. 16 - Prob. 3FC Ch. 16 - Prob. 6FC Ch. 16 - Prob. 7FC Ch. 16 - Prob. 10FC Ch. 16 - 11. As the amplitude of a sound wave in air...Ch. 16 - Prob. 12FC Ch. 16 - Prob. 13FC Ch. 16 - Prob. 15FC Ch. 16 - Prob. 17FC Ch. 16 - Prob. 18FC Ch. 16 - Prob. 19FC Ch. 16 - Prob. 1P Ch. 16 - Prob. 2P Ch. 16 - Prob. 3P Ch. 16 - Prob. 4P Ch. 16 - Prob. 5P Ch. 16 - Prob. 6P Ch. 16 - Prob. 7P Ch. 16 - Prob. 8P Ch. 16 - Prob. 9P Ch. 16 - Prob. 10P Ch. 16 - Prob. 12P Ch. 16 - Prob. 13P Ch. 16 - Prob. 14P Ch. 16 - Prob. 15P Ch. 16 - Prob. 16P Ch. 16 - Prob. 17P Ch. 16 - Prob. 18P Ch. 16 - Prob. 19P Ch. 16 - Prob. 20P Ch. 16 - Prob. 21P Ch. 16 - Prob. 23P Ch. 16 - Prob. 24P Ch. 16 - Prob. 25P Ch. 16 - Prob. 26P Ch. 16 - Prob. 27P Ch. 16 - Prob. 28P Ch. 16 - Prob. 29P Ch. 16 - Prob. 30P Ch. 16 - Prob. 31P Ch. 16 - Prob. 32P Ch. 16 - Prob. 33P Ch. 16 - Prob. 34P Ch. 16 - Prob. 35P Ch. 16 - Prob. 36P Ch. 16 - Prob. 37P Ch. 16 - Prob. 38P Ch. 16 - Prob. 39P Ch. 16 - Prob. 40P Ch. 16 - 41. An explosion occurs at the end of a pier. The...Ch. 16 - Prob. 42P Ch. 16 - Prob. 43P Ch. 16 - Prob. 44P Ch. 16 - Prob. 45P Ch. 16 - Prob. 46P Ch. 16 - Prob. 47P Ch. 16 - Prob. 48P Ch. 16 - Prob. 52P Ch. 16 - Prob. 53P Ch. 16 - 54. A source of sound is located at the center of...Ch. 16 - Prob. 56P Ch. 16 - 57. A loudspeaker has a circular opening with a...Ch. 16 - Prob. 58P Ch. 16 - Prob. 59P Ch. 16 - Prob. 60P Ch. 16 - Prob. 61P Ch. 16 - Prob. 63P Ch. 16 - Prob. 64P Ch. 16 - Prob. 65P Ch. 16 - Prob. 66P Ch. 16 - Prob. 67P Ch. 16 - Prob. 68P Ch. 16 - Prob. 69P Ch. 16 - Prob. 70P Ch. 16 - Prob. 71P Ch. 16 - Prob. 72P Ch. 16 - 73. A portable radio is sitting at the edge of a...Ch. 16 - Prob. 76P Ch. 16 - Prob. 77P Ch. 16 - Prob. 78P Ch. 16 - Prob. 79P Ch. 16 - Prob. 80P Ch. 16 - 81. a car is parked 20.0 m directly south of a...Ch. 16 - 82. A loudspeaker in a parked car is producing...Ch. 16 - Prob. 83P Ch. 16 - Prob. 84P Ch. 16 - Prob. 85P Ch. 16 - Prob. 86P Ch. 16 - Prob. 87P Ch. 16 - 89. A recording engineer works in a soundproofed...Ch. 16 - Prob. 92AP Ch. 16 - Prob. 93AP Ch. 16 - Prob. 94AP Ch. 16 - Prob. 95AP Ch. 16 - Prob. 96AP Ch. 16 - Prob. 97AP Ch. 16 - Prob. 98AP Ch. 16 - Prob. 99AP Ch. 16 - Prob. 100AP Ch. 16 - Prob. 101AP Ch. 16 - Prob. 102AP Ch. 16 - Prob. 103AP Ch. 16 - Prob. 104AP Ch. 16 - Prob. 105AP Ch. 16 - 106. spider hangs from a strand of silk whose...Ch. 16 - Prob. 108AP Ch. 16 - Prob. 111AP Ch. 16 - Prob. 112CCP Ch. 16 - Prob. 113CCP Ch. 16 - Prob. 114TP Ch. 16 - Prob. 115TP

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.