ORGANIC CHEMISTRY 3E WPNGC LL SET 1S 
ORGANIC CHEMISTRY 3E WPNGC LL SET 1S 
3rd Edition
ISBN: 9781119815792
Author: Klein
Publisher: WILEY
Question
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Chapter 16, Problem 62IP
Interpretation Introduction

Interpretation:

The all possible conjugated dienes with the molecular formula C6H10 are needed to be drawn.

Concept introduction:

  • The Hydrogen Deficiency Index (HDI): It is used to measure the number of degrees of unsaturation (double and triple bonds or ring) present in a given molecule. It is determined by using the formula.

HDI=12[(2×No. of Carbon atoms)+2+(No. of Nitrogen atoms)              - (No. of Hydrogen atoms)-(No. of halogens)]

  • Constitutional isomers are having the same molecular formula and different bond connectivity between the atoms.

To draw: all possible conjugated dienes with the molecular formula C6H10 .

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2.
Please solve for the following Electrochemistry that occurs
Commercial bleach contains either chlorine or oxygen as an active ingredient.  A commercial oxygenated bleach is much safer to handle and less likely to ruin your clothes.  It is possible to determine the amount of active ingredient in an oxygenated bleach product by performing a redox titration.  The balance reaction for such a titration is: 6H+ +5H2O2 +2MnO4- à 5O2 + 2Mn2+ + 8H2O If you performed the following procedure: “First, dilute the Seventh Generation Non-Chlorine Bleach by pipetting 10 mL of bleach in a 100 mL volumetric flask and filling the flask to the mark with distilled water. Next, pipet 10 mL of the diluted bleach solution into a 250 mL Erlenmeyer flask and add 20 mL of 1.0 M H2SO4 to the flask. This solution should be titrated with 0.0100 M KMnO4 solution.”  It took 18.47mL of the KMnO4 to reach the endpoint on average.  What was the concentration of H2O2 in the original bleach solution in weight % assuming the density of bleach is 1g/mL?

Chapter 16 Solutions

ORGANIC CHEMISTRY 3E WPNGC LL SET 1S 

Ch. 16.5 - Prob. 9PTSCh. 16.5 - Prob. 10PTSCh. 16.5 - Prob. 11ATSCh. 16.5 - Prob. 12CCCh. 16.7 - Prob. 3LTSCh. 16.7 - Prob. 13PTSCh. 16.7 - Prob. 14ATSCh. 16.7 - Prob. 15CCCh. 16.7 - Prob. 16CCCh. 16.7 - Prob. 17CCCh. 16.7 - Predict the regiochemical outcome (major product)...Ch. 16.8 - Prob. 19CCCh. 16.9 - Prob. 20CCCh. 16.9 - Prob. 4LTSCh. 16.9 - Prob. 21PTSCh. 16.9 - Prob. 22ATSCh. 16.10 - Prob. 23CCCh. 16.10 - Prob. 24CCCh. 16.10 - Prob. 25CCCh. 16.10 - Prob. 26CCCh. 16.11 - Prob. 5LTSCh. 16.11 - Prob. 27PTSCh. 16.11 - Prob. 28ATSCh. 16.12 - Prob. 29CCCh. 16 - Prob. 30PPCh. 16 - Prob. 31PPCh. 16 - Prob. 32PPCh. 16 - Prob. 33PPCh. 16 - Prob. 34PPCh. 16 - Prob. 35PPCh. 16 - Prob. 36PPCh. 16 - Prob. 37PPCh. 16 - Prob. 38PPCh. 16 - Prob. 39PPCh. 16 - Prob. 40PPCh. 16 - Prob. 41PPCh. 16 - Prob. 42PPCh. 16 - Prob. 43PPCh. 16 - Prob. 44PPCh. 16 - Prob. 45PPCh. 16 - Prob. 46PPCh. 16 - Prob. 47PPCh. 16 - Prob. 48PPCh. 16 - Prob. 49PPCh. 16 - Prob. 50PPCh. 16 - Prob. 51PPCh. 16 - Prob. 52PPCh. 16 - Prob. 53PPCh. 16 - Prob. 54PPCh. 16 - Prob. 55PPCh. 16 - Prob. 56PPCh. 16 - Prob. 57PPCh. 16 - Prob. 58PPCh. 16 - Prob. 59PPCh. 16 - Prob. 60IPCh. 16 - Prob. 61IPCh. 16 - Prob. 62IPCh. 16 - Prob. 63IPCh. 16 - Prob. 64IPCh. 16 - Prob. 65IPCh. 16 - Prob. 66IPCh. 16 - Prob. 67IPCh. 16 - Prob. 68IPCh. 16 - Prob. 69IPCh. 16 - Prob. 70IPCh. 16 - Prob. 71IPCh. 16 - Prob. 72IPCh. 16 - Prob. 73IPCh. 16 - Prob. 74IPCh. 16 - Prob. 76IPCh. 16 - Prob. 77CPCh. 16 - Prob. 78CPCh. 16 - Prob. 79CPCh. 16 - Prob. 80CPCh. 16 - Prob. 81CP
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