Explanation Given info: The power of the microwave oven is 625 W , rate at which energy supplied by the microwave is 1.0 kW and heat capacity of the pan is 1.4 kJ / K . Explanation: Write the expression for the rate at which heat energy absorbed to heat the water. Q Δ t = C tot Δ T Δ t Here, Q is the amount of heat energy required to heat the water C tot is the heat capacity of the water and container Δ T is the change in temperature Δ t is the time interval Rearrange the above equation to get temperature rise per second. Δ T Δ t = Q C tot Δ t Substitute P for Q Δ t to get Δ T Δ t . Δ T Δ t = P C tot (1) Here, P is the rate at which energy absorbed In the case of microwave oven only water is heated and paper cup has not specific heat capacity., Therefore C tot = m c . Substitute m c for C tot and P micro for P in equation (1) to get Δ T Δ t in the case of water in oven. Δ T Δ t = P micro m c (2) Here, P micro is the rate at which heat energy supplied by oven m is the mass of the water c is the specific heat capacity of water In the case of stove both water and pan need to be heated and pan has a specific heat capacity of C pan , Therefore C tot = m c + C pan . Substitute m c + C pan for C tot and P stove for P in equation (1) to get Δ T Δ t in the case of water in stove

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ISBN: 9780134988559

Author: Wolfson, Richard

Publisher: Pearson Education,

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First law of Thermodynamics

The word thermodynamics consists of two words: thermo- and dynamics. Dynamics means the study of motion. The field of thermodynamics is all about the study of the movement of heat. In a more meaningful way, it is stated as the study of the transfer of en…

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Chapter 16, Problem 53P

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The amount of water needed before it becomes quicker to heat on the stovetop.

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Chapter 16, Problem 52P

Chapter 16, Problem 54P

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Chapter 16 Solutions

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