Explanation Given The pH of an aqueous solution of NaOH is 11.50 . The pOH of NaOH solution is calculated by the formula, pH + pOH = 14 pOH = 14 − pH Where, pOH is the negative logarithm in the base 10 of [ OH − ] . pH is the negative logarithm in the base 10 of [ H + ] . Substitute the value of pH in the above formula. pOH = 14 − 11.50 = 2

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Chapter 16, Problem 47E

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To determine: The concentration of an aqueous solution of NaOH that has a pH of 11.50 .

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Chapter 16, Problem 46E

Chapter 16, Problem 48E

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CHEMISTRY: THE CENTRAL SCIENCE

Ch. 16.2 - Practice Exercise 1 Consider the following...Ch. 16.2 - Prob. 16.1.2PE Ch. 16.2 - Prob. 16.2.1PE Ch. 16.2 - Practice Exercise 2 When lithium oxide (Li2O) is...Ch. 16.2 - Based on information in Figure 16.4, place the...Ch. 16.2 - Practice Exercise 2 For each reaction, use Figure...Ch. 16.3 - Practice Exercise 1 In a certain acidic solution...Ch. 16.3 - Practice Exercise 2 Indicate whether solutions...Ch. 16.3 - Prob. 16.5.1PE Ch. 16.3 - Prob. 16.5.2PE

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